98/97+1
cho B=1*98+2*97+3*6+..+2*97+1*98/1*2+2*3+3*4+97*98+98*99
So sánh
A=97^98+1/ 97^99+1 va B=97^97+1/ 97^98+1
Ta có: \(A=\frac{97^{98}+1}{97^{99}+1}\Rightarrow97A=\frac{97^{99}+97}{97^{99}+1}=\frac{97^{99}+1+96}{97^{99}+1}=1+\frac{96}{97^{99}+1}\)
\(B=\frac{97^{97}+1}{97^{98}+1}\Rightarrow97B=\frac{97^{98}+97}{97^{98}+1}=\frac{97^{98}+1+96}{97^{98}+1}=1+\frac{96}{97^{98}+1}\)
Vì \(\frac{96}{97^{99}+1}< \frac{96}{97^{98}+1}\Rightarrow1+\frac{96}{97^{99}+1}< 1+\frac{96}{97^{98}+1}\Rightarrow97A< 97B\Rightarrow A< B\)
Vậy A < B
Ta thấy A < 1 và 96 > 1 nên ta có:
A < 9798 + 1 + 96 / 9799 + 1 + 96
=> A < 9798 + 97 / 9799 + 97
=> A < 97(9797 + 1) / 97(9798 + 1)
=> A < 9797 + 1 / 9798 + 1 = B
=> A < B
1+ 99/98 -98/97+ 1/97*98
\(1+\frac{99}{98}-\frac{98}{97}+\frac{1}{97.98}\)
\(=1+1+\frac{1}{98}-\left(1+\frac{1}{97}\right)+\frac{1}{97}-\frac{1}{98}\)
\(=1+1+\frac{1}{98}-1-\frac{1}{97}+\frac{1}{97}-\frac{1}{98}\)
\(=1+1-1\)
\(=1\)
99/98 - 98/97 + 1/97*98
\(\frac{99}{98}-\frac{98}{97}+\frac{1}{97\times98}\)
\(=\left(1+\frac{1}{98}\right)-\left(1+\frac{1}{97}\right)+\frac{1}{97\times98}\)
\(=\frac{1}{98}-\frac{1}{97}+\frac{1}{97\times98}\)
\(=\frac{-1}{97\times98}+\frac{1}{97\times98}\)
\(=0\)
\(\frac{99}{98}-\frac{98}{97}+\frac{1}{97X98}=\left(1+\frac{1}{98}\right)-\left(1+\frac{1}{97}\right)+\frac{1}{97X98}\)
\(=\frac{1}{97X98}-\frac{1}{97X98}=0\)
Nguyễn tuấn thảo ơi người ta mới lớp 5 bạn thêm -1 vào chi ? :)
Tính nhanh
1/100 - 1/ 100 . 99 - 1/99 . 98 - 1/ 97 .98 - 1/ 97 .98 - ..- 1/ 3.2 - 1/2.1
đề :
= 1/100 - (1 / 100.99 +1/99.98 + ...+ 1/3.2 +1/2.1 )
=1/100 - (1 /1.2 +1/ 2.3 +...+ 1/ 98.99 +1 / 99.100)
=1/100 -( 1- 1/ 2 +1/2 -1/3 +...+1/98 -1/99 +1/99 -1/100)
=1/100 - ( 1- 1/100)
=1/100 - 99 /100
= -98/100
= -49 /50
Tính nhanh
1 1/98-1 1/97+ 1/97+98
Chứng minh rằng : A=1×98+2×97+3×96+. . . . .+96×3+97×2+98×1/1×2+2×3+3×4+. . . . .+96×97+97×98+98×99=1/2
Ai giải ra nhanh và sớm nhất mk sẽ tk cho 5 tk lun
Thank you very good!
Bạn tìm ở link này nha: https://olm.vn/hoi-dap/tim-kiem?q=+Ch%E1%BB%A9ng+minh+r%E1%BA%B1ng+1.98+2.97+3.96+...+96.3+97.2+98.11.2+2.3+3.4+...+96.97+97.98+98.99+=1/2+&id=517786
b=1*99+2*98+3*97+...+97*2+98*1
1^98+2^97+3^96+...+96^3+97^2+98^1
Giải giúp mình nhé:
1. ( 91-99+98)-(-99+98)
2. ( 99-98+97)-(99+97+98)
(91-99+98)-(-99+98)=91-99+98+99-98=91
(99-98+97)-(99+97+98)=99-98+97-99-97-98=(-98)*2=-196
1. (91 - 99 + 98) - (-99 + 98)
= 91 - 99 + 98 + 99 - 98
= (-99 + 99) + (98 - 98) + 91
= 0 + 0 + 91
= 91
2. (99 - 98 + 97) - (99 + 97 + 98)
= 99 - 98 + 97 - 99 - 97 - 98
= (99 - 99) + (97 - 97) + (-98 - 98)
= 0 + 0 + (-196)
= -196