(100+42) x42+(200-58)x58

=142x42+142x58

=142x(42+58)

=142x100

=14200

\(\left(100+42\right)\times42+\left(200-58\right)\times58\)

\(=142\times42+142\times58\)

\(=142\times\left(42+58\right)\)

\(=142\times100=14200\)

142 x 42 + 142 x 58

= 142 x (42 +58)

=142 X 100

=14200

K NHÉ +kb

12,7 + 12,7 + 12,7 + 12,7 x 8 - 12,7

= 12,7 x (1 + 1 + 1 + 8 - 1)

= 12,7 x 10

= 127

(100 + 42) x 42 + (200 - 58) x 58

= 142 x 42 + 142 x 58 

= 142 x (42 x 58)

= 142 x 100

= 14200

a.

12,7 + 12,7 + 12,7 + 12,7 x 8 - 12,7

= 12,7 x ( 1 + 1 + 1 + 8 - 1 )

= 12,7 x 10

= 127

b.

( 100 + 42 ) x 42 + ( 200 - 58 ) x 58

= 142 x 42 + 142 x 58

= 142 x ( 42 + 58 )

= 142 x 100

= 14200

`@` `\text {Ans}`

`\downarrow`

`2023 \times 14 + 2023 \times 83+97`

`= 2023 \times (14+83) + 97`

`= 2023 \times 97 + 97`

`= 196231 +97`

`= 196328`

`78 \times 31+78 \times 24+78 \times 17+78 \times 22 \times 72`

`= 78 \times (31+24+17+22 \times 72)`

`= 78 \times (31+24+17+1584)`

`= 78 \times 1656`

`= 129168`

`371 \times 69+371 \times 14+629 \times 83`

`= 371 \times (69+14) + 629 \times 83`

`= 371 \times 83 + 629 \times 83`

`= 83 \times (371+629)`

`= 83 \times 1000`

`= 83000`

`91 \times 51+49 \times 163-49 \times 72`

`= 91 \times 51 + 49 \times (163-72)`

`= 91 \times 51+49 \times 91`

`= 91 \times (51+49)`

`= 91 \times 100`

`= 9100`

`3 \times 12 \times 17 + 4 \times 9 \times 81 + 2 \times 6 \times 6`

`= 9 \times 4 \times 17 + 4 \times 9 \times 81 + 4 \times 9 \times 2`

`= 9 \times 4 \times (17+81+2)`

`= 36 \times 100` 

`= 3600`

`42 \times 17 + 58 \times 83 \times 42 \times 83 + 42 \times 83 + 17`

`= 17 \times (42+58) + 42 \times 83 \times (58 \times 83 +1)`

`= 17 \times 100 + 3486 \times 4815`

`= 1700 + 16785090`

`= 16786790`

`(x+1) + (x+2) + ... + (x+100) = 5750`

Số số ngoặc trong phép tính là:

`(100 - 1) : 1 + 1 = 100` (ngoặc)

`=> 100x + (1+2+3+...+100) = 5750`

`=>  100x + ((100 + 1) . 100 : 2) = 5750`

`=> 100x + 5050 = 5750`

`=> 100x = 200`

`=> x = 2`

`(x+1) . (2y-5) = 143`

`=> (2y-5) ∈ Ư(143)`

mà `2y-5 lẻ`

`=> 2y-5 ∈ {-1;-11;1;11} => y = {2;-3;3;8}`

mà `y ∈ N => y = {2;3;8}`

`=> x+1 ∈ {-143;143;13}`

`=> x ∈ {-144;142;12}`

mà `x ∈ N => x ∈ {142;12}`

Vậy `(x;y) = (142;3);(12;8)`

(Chúc bạn học tốt)

a) Ta có: \(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)

\(\Leftrightarrow100x+5050=5750\)

\(\Leftrightarrow100x=700\)

hay x=7

(100 + 42 ) x 42 + ( 200 - 58 ) x 58 

= 142 x 42 + 142 x 58

= 142 x ( 42 + 58 )

= 142 x 100

= 14200

( 100 + 42 ) x 42 + ( 200 - 58 ) x 58

= 142 x 42 + 142 x 58

= 142 x ( 42 + 58 )

= 142 x 100

= 14200

(100 + 42 ) x 42 + ( 200 - 58 ) x 58 

= 142 x 42 + 142 x 58

= 142 x ( 42 + 58 )

= 14 200

Mong các bạn ủng hộ nha !!!! Ai đi qua xin để lại 1 k nhaaaa !!!

Làm ơn hãy k mk nhé !! 

\(\left(100+58\right)\times58+\left(200-42\right)\times12\)

\(=158\times58+158\times12\)

\(=158\times\left(58+12\right)\)

\(=158\times70=11060\)

\(128\times72+14\times256\)

\(=128\times72+14\times2\times128\)

\(=128\times\left(72+28\right)\)

\(=128\times100=12800\)

\(157\times99+123+34\)

\(=157\times99+157\times1\)

\(=157\times\left(99+1\right)\)

\(=157\times100=15700\)

\(67+98\times45+23\)

\(=98\times45+90\)

\(=98\times45+45\times2\)

\(=45\times\left(98+2\right)\)

\(=45\times100=4500\)

a) 13 x ( x +1 ) =143

x+1= 143 : 13

x+1= 11

x= 11-1

x= 10

b) ( x - 2 ) : 7 = 12

x-2= 12 x 7

x-2=84

x=84+2

x=86

c) 120 : ( x - 3 )= 8

x-3=120:8

x-3=15

x=15+3

x=18

Ghi lời giải nha mọi người

=2772 nha bạn. Nhớ tick cho mình nha!

\(=3,6\times123+3,6\times1567+3,6\times8310\)

\(=3,6\times\left(123+1567+8310\right)\)

\(=3,6\times10000\)

\(=36000\)