Tìm x biết :1/2+1/6+1/12+1/20+1/30+1/x=41/42
1/2+1/6+1/12+1/20+1/30+1/x=41/42
tìm x
\(\frac{1}{x}=\frac{41}{42}-\frac{1}{30}-\frac{1}{20}-\frac{1}{12}-\frac{1}{6}-\frac{1}{2}\)
\(\frac{1}{x}=\frac{1}{7}=>x=7\)
1/2+1/6+1/12+1/20+1/30+1/x=41/42=?
41/42 - 1/2 - 1/6 - 1/12 - 1/20 -1/30 = 1/x
1/7 = 1/x
x = 1 / 1/7
x = 7
\(\frac{1}{1X2}+\frac{1}{2X3}+\frac{1}{3X4}+\frac{1}{4X5}+\frac{1}{5X6}+\frac{1}{x}\)= \(\frac{41}{42}\)
\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{x}=\frac{41}{42}\)
\(1-\frac{1}{6}+\frac{1}{x}=\frac{41}{42}\)
\(\frac{5}{6}+\frac{1}{x}=\frac{41}{42}\)
\(\frac{1}{x}\) =\(\frac{41}{42}-\frac{5}{6}\)
\(\frac{1}{x}\) = \(\frac{1}{7}\)
VẬy x = 7
k cho mik nha
1/2+1/6+1/12+1/20+1/30+1/x=41/42
x=
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{x}=\frac{41}{42}\)
=>\(\frac{1}{x}=\frac{41}{42}-\frac{1}{30}-\frac{1}{20}-\frac{1}{12}-\frac{1}{6}-\frac{1}{2}\)
=>\(\frac{1}{x}=\frac{410-14-21-35-70-210}{420}\)
=>\(\frac{1}{x}=\frac{1}{7}\)
=> x = 7
K mình nhé mn !!!
1/2+1/6+1/12+1/20+1/30+1/x=41/42
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{x}=\frac{41}{42}\)
\(\frac{5}{6}+\frac{1}{x}=\frac{41}{42}\)
\(\frac{1}{x}=\frac{41}{42}-\frac{5}{6}\)
\(\frac{1}{x}=\frac{1}{7}\)
Vậy x = 7
1/2+1/6+1/12+1/20+1/30+1/x=41/42
Tìm x, biết (1/2+5/6+11/12+39/30+41/42).x=3
(1/2+5/6+11/12+39/30+41/42).x=3 1901/420.x=3 x=3:1901/420 x=1260/1901
bài 1 1/2+1/6+1/12+1/20+1/30+1/x=41/42
bài 2 (x-273)*(1+3+5....+2015)=0
1/2+1/6+1/12+1/20+1/30+1/x=41/42
giai giup minh cau nay nhe
\(\frac{1}{x}=\frac{41}{42}-\frac{1}{30}-\frac{1}{20}-\frac{1}{12}-\frac{1}{6}-\frac{1}{2}\)
\(\frac{1}{x}=\frac{1}{7}\). Suy ra \(x\)= 7.
1/2 +1/6 +1/12+1/20+1/30+1/x=41/42
Ta có \(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}=\frac{41}{42}\)
mà 6 . 7 bàng 42=> x=42
mà . là dấu nhân
a,1/2+1/6+1/12+1/20+1/30+1/x=41/42