Đề sai nhé bạn sao lại >1??

sai đề nha Lê Văn Ánh Thông

k cho mình nha!

bạn ơi đề sai rồi

Nhân 2 cả 2 vế lên:

\(\left(2x+\frac{2}{1x3}\right)+...+\left(2x+\frac{2}{23x25}\right)=22x+\frac{2}{3}+\frac{2}{9}+\frac{2}{81}+\frac{2}{243}\)2/243

\(24x+\left(1-\frac{1}{3}+\frac{1}{3}-...+\frac{1}{23}-\frac{1}{25}\right)=22x+\frac{162+54+6+2}{243}\)

\(24x+\frac{24}{25}=22x+\frac{224}{243}\)

\(2x=\frac{224}{243}-\frac{24}{25}\)

\(2x=-\frac{232}{6025}\)

\(x=\frac{-116}{6075}\)

\(\left(x+\frac{1}{1.3}\right)+\left(x+\frac{1}{3.5}\right)+...+\left(x+\frac{1}{23.25}\right)=11.x+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{81}+\frac{1}{243}\right)\)

\(12x+\left[\frac{1}{2}.\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{23}-\frac{1}{25}\right)\right]=11.x+\left(\frac{81}{243}+\frac{27}{243}+\frac{3}{243}+\frac{1}{243}\right)\)

\(12x+\left[\frac{1}{2}.\left(\frac{1}{1}-\frac{1}{25}\right)\right]=11.x+\frac{112}{243}\)

\(12x+\left(\frac{1}{2}.\frac{24}{25}\right)=11.x+\frac{112}{243}\)

\(12x+\frac{12}{25}=11x+\frac{112}{243}\)

\(11x-12x=\frac{112}{243}-\frac{12}{25}\)

\(-1x=-\frac{116}{6075}\)

\(x=-\frac{116}{6075}\div\left(-1\right)\)

\(x=\frac{116}{6075}\)

\(A=\frac{5}{18.23}+\frac{1}{23.24}+\frac{7}{24.31}+\frac{2}{31.33}+\frac{4}{33.37}+\frac{1}{37.38}\)

\(A=\frac{1}{18}-\frac{1}{23}+\frac{1}{23}-\frac{1}{24}+\frac{1}{24}-\frac{1}{31}+\frac{1}{31}-\frac{1}{33}+\frac{1}{33}-\frac{1}{37}+\frac{1}{37}-\frac{1}{38}\)

\(A=\frac{1}{18}-\frac{1}{38}=\frac{5}{171}\)

Học tốt

Ta có: \(A=\frac{5}{18x23}+\frac{1}{23x24}+\frac{7}{24x31}+\frac{2}{31x33}+\frac{4}{33x37}+\frac{1}{37x38}+\frac{7}{38x45}+\frac{9}{45x54}\)

\(\Rightarrow A=\frac{1}{18}-\frac{1}{23}+\frac{1}{23}-\frac{1}{24}+\frac{1}{24}-\frac{1}{31}+...+\frac{1}{38}-\frac{1}{45}+\frac{1}{45}-\frac{1}{54}\)

\(\Rightarrow A=\frac{1}{18}-\frac{1}{54}\)

\(\Rightarrow A=\frac{3}{54}-\frac{1}{54}=\frac{1}{27}\)

Vậy \(A=\frac{1}{27}\)

*Công thức: \(\frac{a}{b.c}=\frac{1}{b}-\frac{1}{c}\left(a+b=c\right)\)

Tớ mới chuẩn bị lớp 6 thôi, ko hiểu đâu.

32×75+23×25-120

=96×25+23×25-120

=25×(96+23)-120

=25×119-120

=2975-120

=2855

32x75+32x25-120

= 32(75+25) - 120

= 32.100 -120

= 3200 -120

= 3080

32 x 75 + 23 x 25 -120

= 32 x 3 x 25 + 23 x 25 - 120

= 96 x 25 + 23 x 25 -120

= 25 x ( 96 + 23 ) -120

= 25 x 119 -120

= 2975 -120

= 2855

(\(\dfrac{11}{12}\) + \(\dfrac{11}{12.23}\)  + \(\dfrac{11}{23.24}\) + ... + \(\dfrac{11}{89.100}\)) + \(x\) = \(\dfrac{5}{3}\)

Em xem lại nhé chứ \(\dfrac{11}{23.24}\) không hợp quy luật dãy số.