so sanh a va b
a, A=20/39 +22/27 + 18/43 B=14/39 +22/29+18/41
b, A=3/8^3 + 7/8^4 B= 7/8^3 + 3/8^4
So sánh A và B :
a,A=20/39+22/27+18/43,B=14/39+22/29+18/41
b,A=3/8^3+7/8^4,B=7/8^3+3/8^4
c,A=10^7+5/10^7-8,B=10^8+6/10-7
d,A=10^1992+1/10^1991+1,B=10^1993+1/10^1992+1
SO SÁNH A VÀ B
a ) A=\(\dfrac{3}{8^3}+\dfrac{7}{^{ }8^4}\) B =\(\dfrac{7}{8^3}+\dfrac{3}{8^4}\)
b ) A=\(\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43}\) B=\(\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)
a, Ta có:
A= \(\dfrac{3}{8^3}+\dfrac{7}{8^4}=\dfrac{3}{8^3}+\dfrac{3}{8^4}+\dfrac{4}{8^4}\)
B= \(\dfrac{7}{8^3}+\dfrac{3}{8^4}=\dfrac{3}{8^3}+\dfrac{4}{8^3}+\dfrac{3}{8^4}\)
Vì \(\dfrac{4}{8^4}< \dfrac{4}{8^3}\) nên A < B.
b, Ta có:
\(\dfrac{20}{39}>\dfrac{14}{39}\)
\(\dfrac{22}{27}>\dfrac{22}{29}\)
\(\dfrac{18}{43}< \dfrac{18}{41}\)
\(\Rightarrow\)\(\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43}>\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)
Hay A > B
a) A=20/39 + 22/27 + 18/23.
B+14/39 + 22/29 + 18/41.
b) A=3/8^3 + 3/8^4 + 4/8^4.
B=4/8^3 + 3/8^3 + 3/8^4
c) A=10^7+5/10^7-8
B=10^8+6/10^8-7
d) A=10^1992+1/10^1991+1
B= 10^1993+1/10^1992+1
ai tra loi dc cau nao thi noi nha
So sánh A và B :
a,A=20/39+22/27+18/43 B=14/39+22/29+18/41
b,A=3/83+7/84, B=7/83+3/84
3 like cho ai làm được
So sánh A và B biết
a,A=20/39+22/27+18/43 B,14/39+22/29+18/41
b,A=3/8^3+7/8^4 B,7/8^3+3/8^4
c,A=10^7+5/10^7-8 B=10^8+6/10^8-7
d,A=10^1992+1/10^1991+1 B=10^1993+1/10^1992+1
1/ So sánh các số sau:
a) -23 / 27 và -24 / 25
.b) A = 20 / 39 + 22 / 27 + 18 / 43 và B = 14 / 39 + 22 / 29 + 18 / 41
c) A = 3 / 83 + 7 / 84 và B = 7 / 83 + 3 / 84
2/ Tìm số nguyên dương x biết:
a) x / 9 < 7 / x < x / 6
b) 3 / x < x / 7 , 4 / x
3/ Cho a / b < 1 và n thuộc N*. Chứng minh : a / b < a+n / b+n
Cho a / b >1 và n thuộc N*. Chứng minh : a / b > a+n / b+n
1. tính nhanh các tổng sau
a) A=\(\frac{20}{39}+\frac{22}{37}+\frac{18}{43}vàB=\frac{14}{39}+\frac{22}{39}+\frac{18}{41^{ }}\)
b) A=\(\frac{3}{8^3}+\frac{7}{8^4}\)và B=\(\frac{7}{8^3}+\frac{3}{8^4}\)
So sánh A và B :
a) \(A=\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43}\)
\(B=\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)
b) \(A=\dfrac{3}{8^3}+\dfrac{7}{8^4}\)
\(B=\dfrac{7}{8^3}+\dfrac{3}{8^4}\)
c) \(A=\dfrac{10^7+5}{10^7-8}\)
\(B=\dfrac{10^8+6}{10^8-7}\)
d) \(A=\dfrac{10^{1992}+1}{10^{1991}+1}\)
\(B=\dfrac{10^{1993}+1}{10^{1992}+1}\)
d, Vì B=10^1993+1/10^1992+1 > 1 =>10^1993+1/10^1992+1>10^1993+1+9/10^1992+1+9 = 10^1993+10/10^1992+10= 10. (10^1992+1)/10. (10^1991+1) = 10^1992+1/10^1991+1=A Vậy A=B
cau d B>1 ta co tinh chat (\(\dfrac{a}{b}>\dfrac{a+m}{b+m}\) ) B> \(\dfrac{10^{1993}+1+9}{10^{1992}+1+9}\)\(=\dfrac{10^{1993}+10}{10^{1992}+10}\)=\(\dfrac{10\left(10^{1992}+1\right)}{10\left(10^{1991}+1\right)}\)=\(\dfrac{10^{1992}+1}{10^{1991}+1}\)=A
Suy ra B>A(chuc ban hoc goi nhe)
so sanh A=20/39+22/27+18/43 va B=14/39+22/29+18/41
giai mau giup minh voi
xét A và B,ta thấy:
20/39>14/39
22/27>22/29
18/43<18/41
Ta có: 20/39+22/27>14/39+22/29
2012^2013+2013^2013<2013^2013+2013^2014
xet A va B ta thay:
20/39>14/39
22/27>22/29
18/43<18/41
vay A>B