nhanh lên nhé 

23. Please take the form from your teacher and ask her to sign.

24. Can you show me the nearest way to the post office

25. We are going to plant the flowers in the parks and water them in the afternoon.

26. My brother is very good at repairing household appliances.

BÀI THỰC HÀNH 6:

var n,i,t: integer;

begin

write('N='); readln(n);

write('Tong cac chu so cua N la : ');

while n<>0 do

begin

t:=t+(n mod 10);

n:=n div 10;

end;

write(t);

readln

end.

Bài thực hành số 6:
uses crt;
var n,t,k:integer;
begin
clrscr;
write('nhap n='); readln(n);
t:=0;
while n<>0 do
begin
k:=n mod 10;
n:=n div 10;
t:=t+k;
end;
writeln(t);
readln;
end.

Bài 1:

a)

Thuật toán 1:

- Bài toán thực hiện 3 vòng lặp

- Kết thúc vòng lặp giá trị S là 4

b)

Thuật toán 2:

- Bài toán thực hiện 0 vòng lặp

- Kết thúc vòng lặp giá trị S là 10

\(a,\dfrac{7}{12}-\left(x+\dfrac{7}{10}\right):\dfrac{6}{5}=\dfrac{5}{4}\)

\(\Leftrightarrow\dfrac{7}{12}-x-\dfrac{7}{10}:\dfrac{6}{5}=\dfrac{5}{4}\)

\(\Leftrightarrow\dfrac{7}{12}-x-\dfrac{7}{12}=\dfrac{5}{4}\)

\(\Leftrightarrow\dfrac{7}{12}-x=\dfrac{5}{4}+\dfrac{7}{12}\)

\(\Leftrightarrow\dfrac{7}{12}-x=\dfrac{11}{6}\)

\(\Leftrightarrow x=\dfrac{7}{12}-\dfrac{11}{6}\)

\(\Leftrightarrow\dfrac{-5}{4}\)

tham khảo !

part 1

1 which

2 won't

3 because

4 Good idea

5 on

6 therefore

part 2

1D 2F 3A 4B 5C 6E

part 3

1 studied

2 has worked

3 being interviewed

4 to be taken

5 would visit

6 put

7 endangered

8 compulsorily

part 4

1 are -> is

2 me -> to me

3 work -> working

4 when -> since

part 5 

1 written novels for

2 to read bedtime stories

3 to wearing

4 has been absent from 

5 doesn't have a passport

6 were given to Martha

7 play football that

8 whom my teacher was

part 6

1 mankind

2 polluted

3 of

4 naturally

part 7

1F 2F 3T 4T

Bạn thêm bài bài toán của SGK Trang 40 vào câu hỏi nữa nhé

Câu 3 : 

\(\%N_{\left(NH_4Cl\right)}=\dfrac{14}{53.5}\cdot100\%=26.16\%\)

\(\%N_{\left(\left(NH_4\right)_2SO_4\right)}=\dfrac{14\cdot2}{132}\cdot100\%=21.21\%\)

\(\%N_{\left(\left(NH_2\right)_2CO\right)}=\dfrac{14\cdot2}{56}\cdot100\%=50\%\)

Khi đó : lượng đạm (N) trong (NH₂)₂CO là lớn nhất

Đúng là N trong (NH₂)₂CO cao nhất nhưng bạn Quang Nhân đang nhầm PTK của hợp chất đó nên tính phần trăm sai em ạ!

\(\%m_{\dfrac{N}{\left(NH_2\right)_2CO}}=\dfrac{2.14}{\left(2.1+14\right).2+12+16}.100\approx46,667\%\)