Tính \(A=1.2.3+2.3.4+3.4.5+...+97.98.99+98.99.100\) .Khi đó : \(A=?\) .
Tính:
1.2.3+2.3.4+3.4.5+4.5.6+...+97.98.99+98.99.100
Đặt A=1.2.3+2.3.4+3.4.5+4.5.6+...+98.99.100
4A=(1.2.3+2.3.4+3.4.5+4.5.6+...+98.99.100)4
4A=1.2.3(4-0)+2.3.4(5-1)+3.4.5(6-2)+4.5.6(7-3)+...+98.99.100(101-97)
4A=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+4.5.6.7-3.4.5.6+...+98.99.100.101-97.98.99.100
4A=1.2.3.4-1.2.3.4+2.3.4.5-2.3.4.5+3.4.5.6-3.4.5.6+...+97.98.99.100-97.98.99.100+98.99.100.101
4A=98.99.100.101
=>A=98.99.100.101/4
TICK ĐÚNG GIÚP MÌNH Ặ
Tính giá trị biểu thức \(A=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{97.98.99}+\frac{1}{98.99.100}\) .Khi đó : \(A=?\)
T/c:A=1/1*2*3+1/2*3*4+1/3*4*5+1/4*5*6+...+1/97*98*99+1/98*99*100
2A=2/1*2*3+2/2*3*4+2/3*4*5+2/4*5*6+...+2/97*98*99+1/98*99*100
2A=(1/1*2-1/2*3)+(1/2*3-1/3*4)+(1/3*4-1/4*5)+.....+(1/97*98-1/98*99)+(1/98*99-1/99*100)
2A=1/2+1/99*100
A=tự tính nha
A= [(1/2-1/2*3)/2]+[(1/2-1/3*4)/2]+...+[(1/2-1/99*100)/2]
A=(1/2-1/99*100)/2
A=-101/198/2
A=-101/396
Tính:\(A=1.2.3+2.3.4+3.4.5+...+98.99.100\)
Tính:
1.2.3+2.3.4+3.4.5+...+98.99.100
Đặt A = 1.2.3 + 2.3.4 + 3.4.5 + ... + 98.99.100
4A = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + ... + 98.99.100.4
4A = 1.2.3.4 + 2.3.4.(5 - 1) + 3.4.5.(6 - 2) + ... + 98.99.100.(101 - 97)
4A = 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + 3.4.5.6 - 2.3.4.5 + ... + 98.99.100.101 - 97.98.99.100
4A = 98.99.100.101
=> A = 98.99.100.101 : 4
=> A = 24497550
B=1.2.3+2.3.4+...+97.98.99+98.99.100
\(B=1\cdot2\cdot3+2\cdot3\cdot4+3\cdot4\cdot5+...+98\cdot99\cdot100\)
\(\Rightarrow4B=4\cdot\left(1\cdot2\cdot3+2\cdot3\cdot4+...+98\cdot99\cdot100\right)\)
\(\Rightarrow4B=1\cdot2\cdot3\cdot\left(4-0\right)+2\cdot3\cdot4\cdot\left(5-1\right)+3\cdot4\cdot5\cdot\left(6-2\right)+...+98\cdot99\cdot100\cdot\left(101-97\right)\)
\(\Rightarrow4B=1\cdot2\cdot3\cdot4+2\cdot3\cdot4\cdot5-1\cdot2\cdot3\cdot4-....+98\cdot99\cdot100\cdot101-97\cdot98\cdot99\cdot100\)
\(\Rightarrow4B=98\cdot99\cdot100\cdot101\)
\(\Rightarrow B=\dfrac{98\cdot99\cdot100\cdot101}{4}\)
\(\Rightarrow B=25\cdot98\cdot99\cdot101\)
B=1x2x3+2x3x4+...+98x99x100
=>4B=1x2x3x(4-0)+2x3x4x(5-1)+...+98x99x100x(101-97)
4B=1x2x3x4+2x3x4x5-1x2x3x4+...+98x99x100x101-97x98x99x100
4B=98x99x100x101
=>B=\(\dfrac{98\cdot99\cdot100\cdot101}{4}\)=24497550.
Tính tổng:
A=1.2.3+2.3.4+3.4.5+...+97.98.99
A= 1.2.3 +2.3.4 + 3.4.5 + ... + 97.98.99
=> 4A = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + ... + 97.98.99.4
=> 4A =1.2.3.4 + 2.3.4.(5-1) + 3.4.5(6-2) + ...+ 97.98.99( 100 - 96)
=> 4A = 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + 3.4.5.6 - 2.3.4.5 + 97.98.99.100 - 96.97.98.99.
=>4A= 97.98.99.100
=> A= (97.98.99.100)/ 4 = 97.98.99.25
Em có thể tham khảo cách làm tương tự như link:
Cách làm nhé. Đừng chép hết. Đề bài của bạn khác 1 chút so với của em.
Câu hỏi của Ngô Hồng Thuận - Toán lớp 7 - Học toán với OnlineMath
A= 1.2.3 + 2.3.4 + 3.4.5 + ... + 98.99.100
A= 1.2.3 + 2.3.4 + 3.4.5 +.....+ 98.99.100
4A = 98.99.100.4 + .....+ 3.4.5.4 + 2.3.4.4 + 1.2.3.4
4A = 98.99.100.(101-97) +... + 2.3.4.(5-1) + 1.2.3.4
4A = 98.99.100.101 - 97.98.99.100+......+2.3.4.5 - 1.2.3.4 + 1.2.3.4
4A = 98.99.100.101
A = 98.99.100.101 : 4
A = 24497550
Tính S=1.2.3+2.3.4+3.4.5+...+97.98.99
Ta có: \(S=1\cdot2\cdot3+2\cdot3\cdot4+3\cdot4\cdot5+...+97\cdot98\cdot99\)
\(\Leftrightarrow4\cdot S=1\cdot2\cdot3\cdot\left(4-0\right)+2\cdot3\cdot4\cdot\left(5-1\right)+3\cdot4\cdot5\cdot\left(6-2\right)+...+97\cdot98\cdot99\cdot\left(101-97\right)\)
\(\Leftrightarrow4\cdot S=98\cdot99\cdot100\cdot101\)
\(\Leftrightarrow S=\text{24497550}\)
Tính S=1.2.3+2.3.4+3.4.5+...+97.98.99
\(S=1.2.3+2.3.4+...+97.98.99\)
\(\Rightarrow4S=1.2.3.4+2.3.4\left(5-1\right)+...+97.98.99.\left(100-96\right)\)
\(\Rightarrow4S=1.2.3.4+2.3.4.5-1.2.3.4+...+97.98.99.100-96.97.98.99\)
\(\Rightarrow4S=97.98.99.100\)
\(\Rightarrow S=\frac{97.98.99.100}{4}\)
\(\Rightarrow S=97.98.99.25\)
S=1.2.3+2.3.3.4.5+...+97.98.99
4.S=1.2.3.4+2.3.4(5-1)+3.4.5.(6-2)+....+97.98.99.(100-96)
4S-S=1.2.3.4+2.3.4.(5-1)-1.2.3.4+3.4.5.(6-2)-2.3.4.(5-1)+...+97.98.99.(100-96)-96.97.98.(99-95)
S= 97.98.99.100:4=23 527 350