\(\frac{3}{4}+\frac{1}{4}\cdot x+x-\frac{7}{6}\cdot x=\frac{5}{12}\)

\(\frac{3}{4}+\frac{1}{4}\cdot x-\frac{7}{6}\cdot x+x\cdot1=\frac{5}{12}\)

\(\frac{3}{4}+x\left(\frac{1}{4}-\frac{7}{6}+1\right)=\frac{5}{12}\)

\(\frac{3}{4}+x\cdot\frac{1}{12}=\frac{5}{12}\)

\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{3}{4}\)

\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{9}{12}\)

\(x\cdot\frac{1}{12}=\frac{-1}{3}\)

\(x=\frac{-1}{3}\text{ : }\frac{1}{12}\)

\(x=\frac{-1}{3}\cdot12\)

\(x=\frac{-12}{3}\)

\(x=-4\)

\(\text{b, }0,25\cdot x-\frac{2}{3}\cdot x=-1\frac{1}{6}\)

\(\frac{1}{4}\cdot x-\frac{2}{3}\cdot x=\frac{-7}{6}\)

\(x\cdot\left(\frac{1}{4}-\frac{2}{3}\right)=\frac{-7}{6}\)

\(x\cdot\frac{-5}{12}=\frac{-7}{6}\)

\(x=\frac{-7}{6}\text{ : }\frac{-5}{12}\)

\(x=\frac{-7}{6}\cdot\frac{12}{-5}\)

\(x=\frac{-14}{-5}\)

giải rùi

A= 1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512 
A = 1 - 1/2 + 1/2- 1/4 + 1/4 - 1/8 + 1/8 - 1/16 + 1/16 - 1/32 + 1/32 - 1/64 + 1/64 - 1/128 + 1/128 - 1/256 - 1/256 - 1/512 
A = 1 - 1/512 

Ủng hộ mk nha! ^_^

(10/99 +11/199 -12/299).(1/2-1/3+-1/6)

=(10/99 +11/199 -12/299).0

=0

HOK TỐT

Đề bài: (10/99+11/199-12/299).(1/2-1/3+ -1/6)

=(10/99+11/199-12/299).(3/6-2/6+ -1/6)

=(10/99+11/199-12/299).(3-2+ -1/6)

=(10/99+11/199-12/299).0

=0.

Hok tốt nhé !

\(\left(\frac{10}{99}+\frac{11}{199}-\frac{12}{299}\right).\left(\frac{1}{2}-\frac{1}{3}+\frac{-1}{6}\right)\)

\(=\left(\frac{10}{99}+\frac{11}{199}-\frac{12}{299}\right).0\)

\(=0\)

~ Hok tốt ~

Cạnh còn lại của H.B.H là:

                \(\frac{8}{5}.\frac{3}{4}=\frac{6}{5}\left(m\right)\)

       Chu vi H.B.H là:

                 \(\frac{8}{5}.2+\frac{6}{5}.2=\frac{28}{5}\left(m\right)\)

                              Đáp số: \(\frac{28}{5}m\).

dấu chấm là cộng trừ hay nhân chia vậy bạn

\(6.\left(\frac{2}{3}\right)^2-3.\left(-\frac{2}{3}\right)^2+1\)

\(=6.\frac{4}{9}-3.\frac{4}{9}+1\)

\(=\frac{4}{9}\left(6-3\right)+1\)

\(=\frac{4}{9}.3+1=\frac{4}{3}+1=\frac{7}{3}\)