1 Unless she is lazy, she can pass the exam

2 Unless she takes some exercises, he will be healthy

3 Unless you study hard, you won't pass the exam

4 Unless you are impatient, you won't make mistakes

5 Unless he gets my mail, he won't send the information we need

6 Unless she travels to London, she will not visit the museum

7 Unless I get the money, I won't buy a mobile phone

8 Unless you make trouble, I will not send you to the principal

9 Unless I have enough time this evening, I will not watch a movie

10 Unless he has money, he will not lend me what I need

1: Ta có: \(A=25x^4-24x^2-1\)

\(=25x^4-25x^2+x^2-1\)

\(=\left(x^2-1\right)\left(25x^2+1\right)\)

\(=\left(x-1\right)\left(x+1\right)\left(25x^2+1\right)\)

2: Ta có: \(A=64x^4+63x^2-1\)

\(=64x^4+64x^2-x^2-1\)

\(=\left(x^2+1\right)\left(64x^2-1\right)\)

\(=\left(x^2+1\right)\left(8x-1\right)\left(8x+1\right)\)

3: Ta có: \(A=x^4-15x^2+50\)

\(=x^4-5x^2-10x^2+50\)

\(=\left(x^2-5\right)\left(x^2-10\right)\)

4: Ta có: \(A=-10x^4+9x^2+1\)

\(=-10x^4+10x^2-x^2+1\)

\(=\left(x^2-1\right)\left(-10x^2-1\right)\)

\(=-\left(10x^2+1\right)\left(x-1\right)\left(x+1\right)\)

cho cả cấu trúc để lần sau bạn có thể dễ làm nè :3

     S + wish + O + V_ed: wish ở hiện tại

    S + wish + O + would/ could + V: wish ở tương lai 

   S + wish + O + had V_p2 (tức là dùng QKHT): wish ở quá khứ

(tương tự với if only)

Bai 1: 5. would come

Bai 2: 1. I wish you could come to the theater with me.

2. I wish my father gave up smoking

3. I wish I knew my friend's address to send her this postcard.

4. I wish I hadn't bought that old car.

5. They wish they wouldn't have to work tomorrow.

6. We wish she could join us in our trip to Hanoi last weekend.

7. I wish I knew more about cars.

8. If only I had a washing machine.

9. If only he had worked harder during the exam.

10. If only I could visit Paris for a year

Ta có : \(f\left(2\right)=2a+b-6\)

\(\lim\limits_{x\rightarrow2^+}\dfrac{x-\sqrt{x+2}}{x^2-4}=\lim\limits_{x\rightarrow2^+}\dfrac{x^2-x-2}{\left(x-2\right)\left(x+2\right)\left(x+\sqrt{x+2}\right)}\)  

\(=\lim\limits_{x\rightarrow2^+}\dfrac{x+1}{\left(x+2\right)\left(x+\sqrt{x+2}\right)}=\dfrac{3}{16}\)

\(\lim\limits_{x\rightarrow2^-}x^2+ax+3b=4+2a+3b\) 

H/s liên tục tại điểm x = 2 \(\Leftrightarrow\dfrac{3}{16}=2a+3b+4=2a+b-6\)

Suy ra : \(a=\dfrac{179}{32};b=-5\) => t = a + b = 19/32 . Chọn C 

Câu 2

\((1) MnO_2 + 4HCl \to MnCl_2 + Cl_2 + 2H_2O\\ (2) Cl_2 + H_2 \xrightarrow{as} 2HCl\\ (3) 3Cl_2 + 2Fe \xrightarrow{t^o} 2FeCl_3\\ (4) 2FeCl_3 + Fe \to 3FeCl_2\\ (5) 2NaOH + Cl_2 \to NaCl + NaClO + H_2O\)

\((1) 4Al + 3O_2 \xrightarrow{t^o} 2Al_2O_3\\ (2) 2Fe + 3Cl_2 \xrightarrow{t^o} 2FeCl_3\\ (3) C + O_2 \xrightarrow{t^o} CO_2\\ (4) 2KMnO_4 \xrightarrow{t^o} K_2MnO_4 + MnO_2 + O_2\\ (5) 4P + 5O_2 \xrightarrow{t^o} 2P_2O_5\\ (6) 2KClO_3 \xrightarrow{t^o} 2KCl + 3O_2\\ (7) Fe + H_2SO_4 \to FeSO_4 + H_2\\ (8) Cu + 2H_2SO_4 \to CuSO_4 + SO_2 + 2H_2O\\ (9) 2Fe + 6H_2SO_4 \to Fe_2(SO_4)_3 + 3SO_2 + 6H_2O\\ (10) 2Al + 6H_2SO_4 \to Al_2(SO_4)_3 + 3SO_2 + 6H_2O\)

Đặt \(\sqrt{x^2-x+1}=a>0;\sqrt{x^2+x+1}=b>0\).

\(PT\Leftrightarrow2a^2-b^2=-\dfrac{\sqrt{3}}{3}ab\)

\(\Leftrightarrow\left(a+\dfrac{\sqrt{3}}{2}b\right)\left(2a-\dfrac{2\sqrt{3}}{3}b\right)=0\)

\(\Leftrightarrow2a-\dfrac{2\sqrt{3}}{3}b=0\) (Do a, b > 0)

\(\Leftrightarrow2\sqrt{x^2-x+1}=\dfrac{2\sqrt{3}}{3}\sqrt{x^2+x+1}\)

\(\Leftrightarrow x^2-x+1=\dfrac{1}{3}\left(x^2+x+1\right)\Leftrightarrow2x^2-4x+2=0\Leftrightarrow x=1\).

Vậy x = 1

Nếu muốn biết thêm cách vẽ thì lên gg nhé ! Ảnh này chị lấy trên mạng

Giá trị các nhóm đất:

Đất feralit: Trồng cây công nghiệp

Đất mùn núi cao: trồng rừng phòng hộ đâu nguồn

Đát phù sa: Trồng cây lương thực , thực phẩm( lúa, cây ăn quả, hoa màu,...)trồng cây công nghiệp ngắn ngày (hàng năm)