cho a b la cac so nguyen duong thoa man a+20 b+1 chia het cho 21 tim so du trong phep chia cua bieu thuc A=4^a+9^a+a+b cho 21
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Cho a,b,c la cac so nguyen duong thoa man a+b+c=3 Tim gia tri nho nhat cua bieu thuc sau
a2/b+c + b2/c+a + c2/a+b
Ta có : \(\frac{a^2}{b+c}+\frac{b+c}{4}\ge2\sqrt{\frac{a^2}{b+c}.\frac{b+c}{4}}=a\)
Tương tự : \(\frac{b^2}{a+c}+\frac{a+c}{4}\ge b\) ; \(\frac{c^2}{a+b}+\frac{a+b}{4}\ge c\)
\(\Rightarrow\frac{a^2}{b+c}+\frac{b^2}{c+a}+\frac{c^2}{a+b}\ge\left(a+b+c\right)-\frac{2\left(a+b+c\right)}{4}=\frac{a+b+c}{2}=\frac{3}{2}\)
Vậy Min = 3/2 \(\Leftrightarrow a=b=c=1\)
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bai 1 tim cac stn x y z sao cho x+y+zxyzbai 2cmr neu m^2+mn+n^2chia het cho 9 voi m ,n la cac stn thi m,n chia het cho 3bai 3 tim stn n nho nhat de cac phan so sau toi gian7/n+9.8/n+10,...,31/n+33bai 4chung to rang phan so m^3+2m/m^4+3m^2 +1 toi gianbai 5 a,cmr khong ton tai so chinh phuong nao co dang ababb,cho 51 so nguyen duong khong vuot qua 100 cmr ton tai 2 so trong 51 so noi tren ma 1 so chia het cho so con laic,tim cac so co 3 chu so sao cho hieu cua so ay va gom 3 chu so ay viet theo th...
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bai 1 tim cac stn x y z sao cho x+y+z=xyz
bai 2cmr neu m^2+mn+n^2chia het cho 9 voi m ,n la cac stn thi m,n chia het cho 3
bai 3 tim stn n nho nhat de cac phan so sau toi gian
7/n+9.8/n+10,...,31/n+33
bai 4chung to rang phan so m^3+2m/m^4+3m^2 +1 toi gian
bai 5 a,cmr khong ton tai so chinh phuong nao co dang abab
b,cho 51 so nguyen duong khong vuot qua 100 cmr ton tai 2 so trong 51 so noi tren ma 1 so chia het cho so con lai
c,tim cac so co 3 chu so sao cho hieu cua so ay va gom 3 chu so ay viet theo thu tu nguoc lai la mot so chinh phuong
bai 6cmr A=2x(x+y-1)+y^2+1 luon nhan gia tri khong am voi moi x,y
bai 7 tim hai so nguyen duong sao cho tong ,hieu thuong (so lon chia cho so nho )cua chung cong lai duoc 38
bai 8 cho ba so a,b,c thoa man a/2009=b/2010=c/2011
tinh gia tri cua bieu thuc M=4(a-b)(b-c)-(c-a)^2
1. Cho a,b,c,d la cac so nguyen thoa man \(a^2=b^2+c^2+d^2\)
chung minh rang a.b.c.d + 2015 viet duoc duoi dang hieu cua 2 so chinh phuong.
2. Cho a,b la cac so duong thoa man dieu kien a+b=1. tim gia tri nho nhat cua bieu thuc
\(P=\frac{2+a}{\sqrt{2-a}}+\frac{2+b}{\sqrt{2-b}}\)
a) tim gia tri nho nhat cua bieu thuc : A = | 1-x | + 8
b) tim cac so nguyen x biet 13 la boi cua x - 4
c) tim so nguyen x sao cho ( x + 5 ) chia het cho ( x + 3 )
giup minh voi! minh can gap gap gap.....
cho x,y,z la cac so huu ti duong thoa man x+1/yz y +1/xz z+1/xy la cac so nguyen tim gia tri lon nhat cua bieu thuc A=x+y^2+z^3
Cho a,b,c la cac so duong thoa man a+b+c=9.Tim gia tri nho nhat cua bieu thuc:
\(P=a^2+\frac{1}{a^2}+b^2+\frac{1}{b^2}+c^2+\frac{1}{c^2}\)
Ta có:\(P=a^2+\frac{1}{a^2}+b^2+\frac{1}{b^2}+c^2+\frac{1}{c^2}\)
\(\Rightarrow P\ge a^2+b^2+c^2+\frac{9}{a^2+b^2+c^2}\)(bđt cauchy-schwarz)
\(P\ge\frac{a^2+b^2+c^2}{81}+\frac{9}{a^2+b^2+c^2}+\frac{80\left(a^2+b^2+c^2\right)}{81}\)
\(\Rightarrow P\ge\frac{2}{3}+\frac{80\left(a^2+b^2+c^2\right)}{81}\left(AM-GM\right)\)
Sử dụng đánh giá quen thuộc:\(a^2+b^2+c^2\ge\frac{\left(a+b+c\right)^2}{3}=27\)
\(\Rightarrow P\ge\frac{2}{3}+\frac{80\cdot27}{81}=\frac{82}{3}\)
"="<=>a=b=c=3
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cho cac so duong a,b,c thoa man : ab+a+b=3
tim GTNN cua bieu thuc C=a^2+b^2
cho a, b la cac so nguyen duong thoa man a+ 1 va b+2007 deu chia het cho 6. CmR:4^a +a + b chia het cho 6
GIUP MINH VOI. MINH RAT GAP.CHAC CHAN SE HAU TA SAU (=^.^=)
cho a,b la cac so duong thoa man : a+b=1
Tim gia tri nho nhat cua bieu thuc: T= \(\frac{19}{ab}+\frac{6}{a^2+b^2}+2011\left(a^4+b^4\right)\)
\(T_{min}=\frac{2715}{8}\) tại \(a=b=\frac{1}{2}\)
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\(T=\frac{19}{ab}+\frac{6}{a^2+b^2}+2011\left(a^4+b^4\right)\)
\(=\frac{19}{ab}+\frac{6}{a^2+b^2}+304\left(a^4+b^4+\frac{1}{16}+\frac{1}{16}\right)+48\left(a^4+\frac{1}{16}\right)+48\left(b^4+\frac{1}{16}\right)+1659\left(a^4+b^4\right)-44\)
\(\ge\frac{19}{ab}+\frac{6}{a^2+b^2}+304ab+24\left(a^2+b^2\right)+1659.\frac{\left(\frac{\left(a+b\right)^2}{2}\right)^2}{2}-44\)
\(=\left(\frac{19}{ab}+304ab\right)+\left(\frac{6}{a^2+b^2}+24\left(a^2+b^2\right)\right)+\frac{1307}{8}\)
\(\ge152+24+\frac{1307}{8}=\frac{2715}{8}\)
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