\(\dfrac{69}{56}\)- \(\dfrac{3}{8}\)...<...\(\dfrac{4}{5}\)x \(\dfrac{15}{14}\)

mình ghi nhầm nên các bạn cứ hết hai phân số là một câu nhé ví dụ như \(\dfrac{-5}{8}\):\(\dfrac{15}{4}\)

a: \(A=\dfrac{-7}{28}\cdot\dfrac{15}{25}=\dfrac{-1}{4}\cdot\dfrac{3}{5}=\dfrac{-3}{20}\)

b: \(B=\dfrac{-5\cdot7}{14\cdot\left(-3\right)}=\dfrac{35}{42}=\dfrac{5}{6}\)

c: \(C=\dfrac{-1}{5}-\dfrac{1}{5}\cdot\dfrac{3}{5}=\dfrac{-1}{5}-\dfrac{3}{25}=\dfrac{-8}{25}\)

d: \(D=\dfrac{-3}{4}-\dfrac{1}{4}=-1\)

e: \(E=\dfrac{-4}{5}\left(1-\dfrac{15}{16}\right)=\dfrac{-4}{5}\cdot\dfrac{1}{16}=\dfrac{-1}{20}\)

f: \(F=\dfrac{6-7}{4}\cdot\dfrac{4+12}{22}=\dfrac{-1}{4}\cdot\dfrac{8}{11}=\dfrac{-2}{11}\)

5/14.1/3.-4/15:5/7=-2/45

nha bn

\(=\dfrac{5\cdot1\cdot\left(-4\right)\cdot7}{14\cdot3\cdot15\cdot5}=\dfrac{\left(-4\right)}{2\cdot3\cdot15}=\dfrac{-4}{90}=-\dfrac{2}{45}\)

\(\dfrac{5}{14}.\dfrac{1}{3}.\dfrac{-4}{15}:\dfrac{5}{7}=\dfrac{5}{14}.\dfrac{1}{3}.\dfrac{-4}{15}.\dfrac{7}{5}=\left(\dfrac{5}{14}.\dfrac{7}{5}\right).\left(\dfrac{1}{3}.\dfrac{-4}{15}\right)=\dfrac{1}{2}.\dfrac{-4}{45}=\dfrac{-2}{45}\)

\(\dfrac{5}{15}+\dfrac{14}{25}-\dfrac{4}{3}+\dfrac{11}{25}\\ =\left(\dfrac{5}{15}-\dfrac{4}{3}\right)+\left(\dfrac{14}{25}+\dfrac{11}{25}\right)\\ =\left(\dfrac{5}{15}-\dfrac{20}{15}\right)+\dfrac{25}{25}\\ =\dfrac{-15}{15}+\dfrac{25}{25}\\ =-1+1\\ =0\)

\(\dfrac{5}{15}\) +  \(\dfrac{14}{25}\) − \(\dfrac{4}{3}\) + \(\dfrac{11}{25}\)\(\dfrac{11}{25}\)

=   [ \(\dfrac{5}{15}\)− \(\dfrac{4}{3}\) ] + [ \(\dfrac{14}{25}\) + 

515+1425−43+1125=(515−43)+(1425+1125)=(515−2015)+2525=−1515+2525=−1+1=0

\(\dfrac{1}{4444}< 1,\dfrac{3}{7}< 1,\dfrac{9}{5}>1,\dfrac{7}{3}>1,\dfrac{14}{15}< 1,\dfrac{16}{16}=1,\dfrac{14}{11}>1\)

1/4 < 1

3/7 < 1

9/5 > 1

7/3 > 1

14/15 < 1

16/16 = 1

14/11 >1

`1/3-2/15+14/15`

`=5/15-2/15+14/15`

`=17/15`

`3/5+4-6/7`

`=21/35+140/35-30/35`

`=131/35`

giúp mình với ạ, thanks!

`1/3- 2/15 + 14/15`

`= 5/15 -2/15 + 14/15`

`=(5-2+14)/15`

`= 17/15`

`--`

`3/5 + 4 -6/7`

`= 3/5 + 20/5 - 6/7`

`= 23/5 - 6/7`

`= 131/35`

a) \(\dfrac{-12}{15}+\dfrac{-4}{26}=\dfrac{-4}{5}+\dfrac{-2}{13}=\dfrac{-52-10}{65}=\dfrac{-62}{65}\)

b) \(5\dfrac{1}{3}-2\dfrac{4}{5}=\dfrac{16}{3}-\dfrac{14}{5}=\dfrac{80}{15}-\dfrac{42}{15}=\dfrac{38}{15}\)

c) \(\dfrac{4}{5}-\left(-\dfrac{2}{7}\right)+\dfrac{-5}{10}=\dfrac{4}{5}+\dfrac{2}{7}-\dfrac{1}{2}=\dfrac{56}{70}+\dfrac{20}{70}-\dfrac{35}{70}=\dfrac{41}{70}\)

d) \(-1\dfrac{2}{7}+\dfrac{3}{14}-\dfrac{5}{21}=\dfrac{-9}{7}+\dfrac{3}{14}-\dfrac{5}{21}=\dfrac{-54}{42}+\dfrac{9}{42}-\dfrac{10}{42}=\dfrac{-55}{42}\)

e) \(12-\dfrac{11}{121}+\left(\dfrac{-8}{9}\right)-\left(-\dfrac{3}{7}\right)\)

\(=12-\dfrac{11}{121}-\dfrac{8}{9}+\dfrac{3}{7}\)

\(=\dfrac{91476}{7623}-\dfrac{693}{7623}-\dfrac{6776}{7623}+\dfrac{3267}{7623}\)

\(=\dfrac{7934}{693}\)