a) \(2^{x+2}-2^2=96\)

 <=> \(2^x.2^2-2^x=96\)

 <=> \(2^x\left(4-1\right)=96\)

<=> \(3.2^x=96\)

<=> \(2^x=32\)

<=> \(2^x=2^5\)

<=> x = 5 

b, \(x-\left(\frac{50x}{100}+\frac{25x}{200}\right)=11\frac{1}{4}\)

\(\Rightarrow x-\left(\frac{1x}{2}+\frac{1x}{8}\right)=\frac{45}{4}\)

\(\Rightarrow x-\left(\frac{4x}{8}+\frac{1x}{8}\right)=\frac{45}{4}\)

\(\Rightarrow x-\frac{5x}{8}=\frac{45}{4}\)

\(\Rightarrow\frac{8x}{8}-\frac{5x}{8}=\frac{45}{4}\)

\(\Rightarrow\frac{3x}{8}=\frac{45}{4}\Rightarrow x=\frac{45}{4}\div\frac{3}{8}=30\)

Vậy x = 30 

a) = (3x +1)² =0 

3x+1 =0

x = -1/3

b) = (5x)² -2² =0

(5x+2)(5x-2) = 0

5x+2 =0

x = -2/5

5x -2  =0

x= 2/5

xem đi rui lam tip

a) 9x² + 6x + 1 = 0  => (3x)² + 2 x 3x + 1 = 0  => (3x + 1)²  = 0  => 3x + 1 = 0  => x = \(\frac{-1}{3}\)

b) 25x² = 4  => x² = 4 : 25  => x² = 0,16  => x = 0,4 hoặc x = -0,4

c) 8 - 125x³ = 0  => 125x³ = 8  => x³ = 8 : 125  => x³ = \(\frac{8}{125}\)=> x = \(\frac{2}{5}\)

c) = 2³ - (5x)³ =0

(2-5x)(4 +10x +25x²) =0

2-5x=0

x = 2/5

4 + 10x +25x²  = 0 (máy tính giải dc)

d) = (( 2x+1) - 5(x+2))² =0

2x+1 -5x -10=0

3x= -9

x = -3

(hoàn toàn ad hđt đáng nhớ thui,bn à)

Tìm x

3x + 7x = 72

(3+7)x = 72

21.x = 72

     x = 72:21

     x = 72/21

     x = 24/7

câu tính nhanh sai đề hay sao í

co minh ra nen minh nghi ko sai dau a

\(\left(25x^2y-13xy^2+y^3\right)-A=11x^2y-2y^3.\)

\(\Rightarrow A=\left(25x^2y-13xy^2+y^3\right)-\left(11x^2y-2y^3\right)\)

\(\Leftrightarrow A=25x^2y-13xy^2+y^2-11x^2y+2y^3\)

\(\Leftrightarrow A=\left(25x^2y-11x^2y\right)-13xy^2+y^2+2y^3\)

\(\Leftrightarrow A=14x^2y-13xy^2+y^2+2y^3\)

\(\dfrac{4}{9-25x^2}\\ =\dfrac{4}{\left(3-5x\right)\left(3+5x\right)}\)

\(\dfrac{4}{9}-25x^2=0\)

\(\left(\dfrac{2}{3}\right)^2-\left(5x\right)^2=0\)

\(\left(\dfrac{2}{3}+5x\right)\left(\dfrac{2}{3}-5x\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}\dfrac{2}{3}+5x=0\\\dfrac{2}{3}-5x=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}5x=-\dfrac{2}{3}\\-5x=-\dfrac{2}{3}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{2}{15}\\x=\dfrac{2}{15}\end{matrix}\right.\)

\(\dfrac{4}{9-25x^2}=0\\ \Leftrightarrow\dfrac{4}{\left(3-5x\right)\left(3+5x\right)}=0\\ \Leftrightarrow\left(3-5x\right)\left(3+5x\right)=0\\ \)

\(\Leftrightarrow\left[{}\begin{matrix}3-5x=0\\3+5x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{5}\\x=-\dfrac{3}{5}\end{matrix}\right.\)

Vậy....

x² - 25x⁴=0

<=>x²(1-25x²)=0

<=>x²[1²-(5x)²]=0

<=>x²(1-5x)(1+5x)=0

=>x²=0                =>x=0 

hoặc 1-5x=0         =>1=5x <=>x=0,2

hoặc 1+5x=0        =>1=-5x <=> x=-0,2

(x+2)+(4x+4)+(7x+6)+...+(25x+18)+(28x+20)=1560

(x+4x+7x+...+25x+28x)+(2+4+6+..+18+20)=1560

145x+110=1560

145x=1450

x=10

vậy........