a: =>2x^2-2x+2x-2-2x^2-x-4x-2=0

=>-5x-4=0

=>x=-4/5

b: =>6x^2-9x+2x-3-6x^2-12x=16

=>-19x=19

=>x=-1

c: =>48x^2-12x-20x+5+3x-48x^2-7+112x=81

=>83x=83

=>x=1

\(a,2^x+2^{x+3}=144\\ 2^x.\left(1+2^3\right)=144\\ 2^x.9=144\\ 2^x=144:9\\ 2^x=16=2^4\\ vậy:x=4\)

\(b,\left(x-5\right)^{2022}=\left(x-5\right)^{2021}\\ Vì:\left[{}\begin{matrix}0^{2022}=0^{2021}\\1^{2022}=1^{2021}\end{matrix}\right.\\ Vậy:\left[{}\begin{matrix}x-5=0\\x-5=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)

\(c,\\ \left(2x+1\right)^3=9.81\\ \left(2x+1\right)^3=3^2.3^4\\ \left(2x+1\right)^3=3^6\\ \left(2x+1\right)^3=\left(3^2\right)^3=9^3\\ Vậy:2x+1=9\\ 2x=9-1\\ 2x=8\\ x=\dfrac{8}{2}\\ x=4\)

a) \(\left(2x-1\right)^2-25=0\)

\(\left(2x-1\right)^2=0+25=25\)

\(\left(2x-1\right)^2=5^2=\left(-5\right)^2\)

\(\Rightarrow\left[\begin{array}{nghiempt}2x-1=5\\2x-1=-5\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}2x=6\\2x=-4\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}x=3\\x=-2\end{array}\right.\)

b) \(8x^3-50x=0\)

\(2x\left(4x^2-25\right)=0\)

\(\Rightarrow\left[\begin{array}{nghiempt}2x=0\\4x^2-25=0\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}x=0\\4x^2=25\Rightarrow x^2=\frac{25}{4}\Rightarrow\left[\begin{array}{nghiempt}x=\frac{5}{2}\\x=-\frac{5}{2}\end{array}\right.\end{array}\right.\)

a) 2x+1 là bội của x-2, suy ra: 2x+1 chia hết cho x-2

(2x+1)-(x-2) chia hết cho x-2

x+3 chia hết cho x-2

(x+3)-(x-2) chia hết cho x-2

5 chia hết cho x-2 nên x-2 là ước của 5

Ta có bảng: 

x-2 /  -1 / -5 / 1 / 5

x   /  -3 / -7 / -1/ 3

Vậy : x={ -3; -7; -1; 3}

1     <=>2x^3+2x^2+x^2+x+5x+5=5

       <=>[x+1][2x^2+x+5]

       2x^2+x+5>0=>x=-1

2     Đặt x+1=a; x-2=b;2x-1=a+b

       <=>a^3+b^3=[a+b]^3

       <=>3ab[a+b]=0

       <=>3[x+1][x-2][2x-1]=0

        <=>x=-1 hoặc x=2 hoặc x=1/2

        Vậy phượng trình có tập nghiệm S={-1;2;1/2}

1) 2x³ + 3x² + 6x + 5 = 0 

 2x³+2x²+x²+x+5x+5=0

2x²(x+1)+x(X+1)+5(X+1)=0

(2x²+x+5)(X+1)=0

=> 2x²+x+5= 0 hoặc x+1=0

......

1) (3x-1)(-1/2x+5)=0

TH1: 3x-1=0

        3x   = 1

          x    = 1/3

TH2:  -1/2x+5=0

         -1/2x     =-5

               x     = 10

2)  (3/4-x)^3=-8

     (3/4-x)^3=(-2)^3

=> 3/4-x=-2

           x=3/4+2

           x= 11/4

3)  |2x-1|=-4^2

     |2x-1|=16

=> 2x-1=-16 hoặc 2x-1=16

TH1: 2x-1=-16

        2x   =-15

          x    = -15/2

TH2:  2x-1=16

          2x   =17

            x    = 17/2

\(1,\)

\(2x\left(x-3\right)-\left(3-x\right)=0\)

\(\Leftrightarrow2x\left(x-3\right)+\left(x-3\right)=0\)

\(\Leftrightarrow\left(2x+1\right)\left(x-3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}2x+1=0\\x-3=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=3\end{cases}}\)

\(2,\)

\(3x\left(x+5\right)-6\left(x+5\right)=0\)

\(\Leftrightarrow\left(3x-6\right)\left(x+5\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}3x-6=0\\x+5=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=-5\end{cases}}\)

\(3,\)

\(x^4-x^2=0\)

\(\Leftrightarrow x^2\left(x^2-1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x^2=0\\x^2-1=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\pm1\end{cases}}\)

\(4,\)

\(x^2-2x=0\)

\(\Leftrightarrow x\left(x-2\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x-2=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)

\(5,\)

\(x\left(x+6\right)-10\left(x-6\right)=0\)

\(\Leftrightarrow x^2+6x-10x+60=0\)

\(\Leftrightarrow x^2-4x+60=0\)

\(\Leftrightarrow x^2-4x+4+56=0\)

\(\Leftrightarrow\left(x-2\right)^2=-56\)(Vô lý)

=> Phương trình vô nghiệm

\(\Rightarrow x^2+2x+1-y^2-4y-4-7=0\\ \Leftrightarrow\left(x+1\right)^2-\left(y+2\right)^2=7\\ \Leftrightarrow\left\{{}\begin{matrix}\left(x+1\right)^2=16\\\left(y+2\right)^2=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\left\{{}\begin{matrix}x+1=4\\y+2=3\end{matrix}\right.\\\left\{{}\begin{matrix}x+1=-4\\y+2=-3\end{matrix}\right.\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=3\\y=1\end{matrix}\right.\)