Theo đề ta có:

\(\left(5+\frac{1}{5}-\frac{2}{9}\right)-\left(2-\frac{1}{23}-2\frac{3}{5}+\frac{5}{6}\right)\)\(-\left(8-\frac{2}{3}-\frac{1}{18}\right)\)

= \(5+\)\(\frac{1}{5}-\frac{2}{9}\)-\(2+\frac{1}{23}+2+\frac{3}{5}+\frac{5}{6}-8+\frac{2}{3}-\frac{1}{18}\)

=\(\left(5+2-8\right)+\left(\frac{1}{5}+\frac{3}{5}\right)-\left(\frac{2}{9}-\frac{5}{6}-\frac{2}{3}+\frac{1}{18}\right)+\frac{1}{23}\)

=  -1 +\(\frac{4}{5}\)\(-\frac{-11}{9}\)+\(\frac{1}{23}\)

= -1 +\(\frac{4}{5}+\frac{11}{9}+\frac{1}{23}\)

\(\left(5+\frac{1}{5}-\frac{2}{9}\right)-\left(2-\frac{1}{23}-2\frac{3}{5}+\frac{5}{6}\right)-\left(8-\frac{2}{3}-\frac{1}{18}\right)\)

= \(5+\frac{1}{5}-\frac{2}{9}-2+\frac{1}{23}+2+\frac{3}{5}-\frac{5}{6}-8+\frac{2}{3}+\frac{1}{18}\)

= \(\left(5-8\right)+\left(\frac{1}{5}+\frac{3}{5}\right)-\left(\frac{2}{9}-\frac{1}{18}-\frac{2}{3}\right)-\left(2-2\right)+\frac{1}{23}-\frac{5}{6}\)

= \(\left(-3\right)+\frac{4}{5}+\frac{1}{2}+\frac{1}{23}-\frac{5}{6}\)

= \(\left(\left(-3\right)+\frac{4}{5}+\frac{1}{2}-\frac{5}{6}\right)+\frac{1}{23}\)

= \(-\frac{38}{15}+\frac{1}{23}\)

= \(-\frac{859}{345}\)

trong tích trên có 1 thừa số như thế này:

\(\left(\frac{1}{125}-\frac{1}{5^3}\right)\)

\(=\left(\frac{1}{125}-\frac{1}{125}\right)\)

=0

=> tích trên bằng 0

Bài 3 :

a) \(\left(\frac{1}{25}-0,6\right)^2:\frac{49}{125}+\left[\left(3\frac{1}{4}-6\frac{5}{9}\right)\cdot2\frac{2}{17}\right]\)

\(=\left(\frac{1}{25}-\frac{3}{5}\right)^2\cdot\frac{125}{49}+\left[\left(\frac{13}{4}-\frac{59}{9}\right)\cdot\frac{36}{17}\right]\)

\(=\left(-\frac{14}{25}\right)^2\cdot\frac{125}{49}+\left[\left(-\frac{119}{36}\right)\cdot\frac{36}{17}\right]\)

\(=-\frac{196}{625}\cdot\frac{125}{49}+\left(-7\right)=-\frac{4}{5}+\left(-7\right)=-\frac{39}{5}\)

Trả lời :

\(\left(\frac{1}{25}-0,6\right)^2\div\frac{49}{125}+\left[\left(3\frac{1}{4}-6\frac{5}{9}\right)\times2\frac{2}{17}\right]\)

\(=\left(\frac{1}{25}-\frac{3}{5}\right)^2\div\frac{49}{125}+\left[\frac{-119}{36}\times\frac{36}{17}\right]\)

\(=\left(\frac{-14}{25}\right)^2\div\frac{49}{125}-7\)

\(=\frac{4}{5}-7\)

\(=\frac{-31}{5}\)

\(\left(\frac{1}{25}-0,6\right)^2:\frac{49}{125}+\left[\left(3\frac{1}{4}-6\frac{5}{9}\right).2\frac{2}{17}\right]\)

\(=\left(-\frac{14}{25}\right)^2.\frac{125}{49}+\left[\left(\frac{13}{4}-\frac{59}{9}\right).\frac{36}{17}\right]\)

\(=\frac{196}{625}.\frac{125}{49}+\left(-\frac{119}{36}.\frac{36}{17}\right)\)

\(=\frac{4}{5}+\left(-7\right)\)

\(=-\frac{31}{5}\)

Số cây cam là:
120 : ( 2 + 3 ) x 2 = 48 (cây)
Số cây xoài là:
( 1 + 5 ) = 20 ( cây )
Số cây chanh là:
120 - ( 48 + 20 ) = 52 ( cây )
               Đáp số : cam : 48 cây
                            xoài : 20 cây
                            chanh : 52 cây.

ai trên 10 điểm thì mình nha

\(=\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}-\left(-\frac{5}{4}\right)-\frac{6}{11}+\frac{48}{49}\)\(\frac{48}{49}\)

\(=\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}+\frac{5}{4}-\frac{18}{33}+\frac{48}{49}\)

\(=\left(\frac{-1}{4}+\frac{5}{4}\right)+\left(\frac{7}{33}-\frac{18}{33}\right)-\frac{5}{3}\)\(+\frac{48}{48}\)

\(=1+\frac{-1}{3}-\frac{5}{3}+\frac{48}{49}\)

\(=1+\left(-2\right)+\frac{48}{49}\)

\(=-1+\frac{48}{49}\)

\(=\frac{-49}{49}+\frac{48}{49}\)

\(=\frac{-1}{49}\)

Bước đến nhà em bóng xế tà

Đứng chờ năm phút bố em ra

Lơ thơ phía trước vài con chó

Lác đác đằng sau chiếc chổi chà

Sợ quá anh chuồn quên đôi dép

Bố nàng ngoác mỏ đứng chửi cha

Phen này nhất quyết thuê cây kiếm

Trở về chém ổng đứt làm ba

= [ 60/90 - ( 12/15 + 10/15) ] : 6/5

= ( 2/3 - 22/15 ) x 5/6

= ( 10/15 - 22/15 ) x 5/6

= -12/15 x 5/6

= -60/90

= -2/3

( 15/10 x 4/9 - ( 4/5 + 2/3 )) : 6/5

( 15/10 x 4/9 - ( 12/15 + 10/15 )) : 6/5

(30/45 - 66/45 ) : 6/5

-12/15 : 6/5 ( đã rút gọn -36/45 = -12/15 )

-2/3

k mk na <3

a) A = \(\frac{15}{7}:\left(\frac{1}{15}-\frac{7}{5}\right)-\frac{15}{7}:\left(\frac{17}{15}+\frac{11}{5}\right)=\frac{15}{7}:\frac{-20}{15}-\frac{15}{7}:\frac{50}{15}\)

A = \(\frac{15}{7}.\frac{15}{-20}-\frac{15}{7}.\frac{15}{50}=\frac{15}{7}.\left(\frac{-15}{20}-\frac{15}{50}\right)=\frac{15}{7}.\frac{-105}{100}=-\frac{9}{4}\)

b) B = \(\frac{1}{\left(-\frac{2}{3}\right)^4}.\left(-4\right)^2-1^{2016}-10\frac{1}{3}=\frac{1}{\frac{16}{81}}.16-1-10\frac{1}{3}=\frac{81}{16}.16-1-10\frac{1}{3}\)

B = \(81-1-10-\frac{1}{3}=70-\frac{1}{3}=\frac{209}{3}\)