tính hợp lý
126 + (- 20) + 2004 + (- 106)
Tính: 126 + (-20) + 2004 + (-106)
126 + (–20) + 2004 + (–106)
= (126 – 20) + 2004 +(–106)
= 106 + 2004 + (–106)
= 106 + (–106) + 2004 (tính chất giao hoán).
= 0 + 2004
= 2004.
Tính:
a) 126+(−20)+2004+(−106)126+(−20)+2004+(−106);
b) (−199)+(−200)+(−201)(−199)+(−200)+(−201).
a) 126+(−20)+2004+(−106)126+(−20)+2004+(−106)
=2004+126+[(−20)+(−106)]=2004+126+[(−20)+(−106)]
=2004+126+[−(20+106)]=2004+126+[−(20+106)]
=2004+126+(−126)=2004+126+(−126)
=2004+[126+(−126)]=2004+0=2004=2004+[126+(−126)]=2004+0=2004.
b) (−199)+(−200)+(−201)=−(199+200+201)(−199)+(−200)+(−201)=−(199+200+201)
=−(199+201+200)=−[(199+201)+200]=−(199+201+200)=−[(199+201)+200]
=−(400+200)=−600=−(400+200)=−600.
Bài 2: Tính bằng cách hợp lý nhất:
a) (-2010) – (119 -2010) b) 217 +[ 43 + (-217) +(-23)]
c) (18+29)+(158 -18 -29) d) 126 +(-20) +2004+(-106)
e) (-199) +(-200) +(-201) f) 99 + (-100) +101
giup mk voi
mk can gap
a/ (- 2010) - (119 - 2010)
= (- 2010) - 119 + 2010
= - 119
b/ 217 + [43 + (- 217) + (- 23)]
= 217 + [43 + (-217) - 23]
= 217 + (-217) + 20
= 20
Bài 2: Tính bằng cách hợp lý nhất:
a) (-2010) – (119 -2010)
= -2010 - 119 + 2010
= 2010 - 2010 - 119
= 0 - 119
= -119
b) 217 +[ 43 + (-217) +(-23)]
= 217 + 43 - 217 - 23
= ( 217 - 217 ) + ( 43 - 23 )
= 0 + 20
= 20
c) (18+29)+(158 -18 -29)
= 18 + 29 + 158 - 18 - 29
= ( 18 - 18 ) + ( 29 - 29 ) + 158
= 0 + 0 + 158
= 158
d) 126 +(-20) +2004+(-106)
= 126 - 20 + 2004 - 106
= [( 126 - 20 ) - 106 ] + 2004
= [ 106 - 106 ] + 2004
= 0 + 2004
= 2004
e) (-199) +(-200) +(-201)
= -199 - 200 - 201
= -199 - 201 - 200
= - 400 - 200
= -600
f) 99 + (-100) +101
= 99 - 100 + 101
= 99 + 101 -100
= 200 - 100
= 100
126 + ( - 20 ) + 2004 + ( - 106 ) = ?
126+106+(-20)+2004
126+106+(-20)+2004
=[126+(-20)]+[106+2004]
=106+2110
=2216
126+(-20)+2004+(-106)
\(126+\left(-20\right)+2004+\left(-106\right)\)
\(=126-20+2004-106\)
\(=106+2004-106\)
\(=2110-106\)
\(=2004\)
a) 126 + (-20) + 2004 + (-106) = 106 + 2004 + (-106) = 106 + (-106) + 2004 = 0 + 2004 = 2004
126 + (-20) + 2004 + (-106)
= 126 + 2004 + (-20) + (-106)
= 2130 + (-20) + (-106)
= 2110 + (-106)
= 2004
(-404)+1002+(-2000)+1998+(-596)
126+(-20)+2004+(-106)
(-404)+1002+(-2000)+1998+(-596)
=[1002+1998+(-2000)]+[(-404)+(-596)]
= 0+0=0
126+(-20)+2004+(-106)
={126+[(-20)+(-106)]+2004
=0 + 2004 =2004
Thực hiện phép tính ( tính nhanh nếu có thể)
a) (2345 + 45) - 2345 b) (-2010) - (119 - 2010)
c) (18 + 29) + (158 - 18 - 29) d) 126 + (-20) + 2004 + (-106)
e) (-199) + (-200) + (201) f) 99 + (-100) + 101
g) 217 + [ 43 + (-217) + (-23)]
a: \(\left(2345+45\right)-2345\)
\(=2345+45-2345\)
\(=45+\left(2345-2345\right)\)
=45+0
=45
b: \(\left(-2010\right)-\left(119-2010\right)\)
\(=-2010-119+2010\)
\(=\left(-2010+2010\right)-119\)
=0-119
=-119
c: \(\left(18+29\right)+\left(158-18-29\right)\)
\(=18+29+158-18-29\)
\(=158+\left(18-18\right)+\left(29-29\right)\)
=158+0+0
=158
d: \(126+\left(-20\right)+2004+\left(-106\right)\)
\(=126-20+2004-106\)
\(=\left(126-20-106\right)+2004\)
=0+2004
=2004
e: \(\left(-199\right)+\left(-200\right)+\left(201\right)\)
\(=-199-200+201\)
\(=-199+\left(201-200\right)\)
=-199+1
=-198
f: \(99+\left(-100\right)+101\)
\(=\left(99+101\right)-100\)
=200-100
=100
g: \(217+\left[43+\left(-217\right)+\left(-23\right)\right]\)
\(=217+43-217-23\)
\(=\left(217-217\right)+\left(43-23\right)\)
=0+20
=20
1. Tính bằng cách giao hoán hoặc kết hợp
a. 126+(-20)+2004+(-106)
b. ( -199)+(-200+(-201)
2. Tìm tổng tất cả các số nguyên x , biết
a. - 4 < x< 3
b. -5<x<5