Cho tam giác ABC A bằng 90 độ ben ngoai tam giac ABC dung tam giac vuong can ABD tai D va ACE vuong can tai A. cm D,A,E thang hang
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Cho tam giac abc co a<90 do ve ra ngoai hai tam giac vuong can tai a abd va ace
cho tam giac abc can tai a co goc bac =50do tren tia doi cua tia bc lay diem d tren tia doi cua tia cb lay diem e sao cho bd =ba ce=ca tinh goc dae
cho tam giac abc deu ve ben ngoai tam giac cac tam giac abd vuong can tai b tam giac ace vuong can tai c tinh so goc nhon cua ade
XÉT \(\Delta ABC\)CÂN TẠI A
\(\Rightarrow\hept{\begin{cases}AB=AC\\\widehat{B}=\widehat{C}\end{cases}}\)
TA CÓ \(\widehat{A}+\widehat{B}+\widehat{C}=180^o\left(Đ/L\right)\)
THAY\(50^0+\widehat{B}+\widehat{C}=180^o\)
\(\widehat{B}+\widehat{C}=130^o\)
MÀ\(\widehat{B}=\widehat{C}\)
\(\Rightarrow\widehat{B}=\widehat{C}=\frac{130^o}{2}=65^o\)
TA CÓ \(\widehat{DBA}+\widehat{ABC}=180^o\left(KB\right)\)
\(\Rightarrow\widehat{DBA}=180^o-65^o=115^o\)
TA CÓ\(\widehat{ACE}+\widehat{ACB}=180^o\left(KB\right)\)
\(\Rightarrow\widehat{ACE}=180^o-65^0=115^o\)
XÉT \(\Delta ACE\)CÓ AC=CE (GT) =>\(\Delta ACE\)CÂN TẠI C
\(\Rightarrow\widehat{CAE}=\widehat{AEC}=\frac{180^o-115^0}{2}=32,5^0\)
XÉT \(\Delta ABD\)CÓ AB=BD (GT) =>\(\Delta ABD\)CÂN TẠI B
\(\Rightarrow\widehat{DAB}=\widehat{ADB}=\frac{180^o-115^0}{2}=32,5^0\)
TA CÓ\(\widehat{DAB}+\widehat{BAC}+\widehat{EAC}=\widehat{DAE}\)
THAY\(32,5^o+50^0+32,5^0=\widehat{DAE}\)
\(\Rightarrow\widehat{DAE}=115^0\)
Cho tam giac ABC, goc A < 90 do. Ve ngoai tam giac ABC cac tam giac vuong can tai A la ABD, ACE.
a, CM : BE=CD, BE vuong goc voi CD
b, Ke AH vuong goc voi BC, AH cat DE tai K. CM : DK=KE
cho tam giac abc vuong tai A ve ra phia ngoai tam giac abd can tai B ve ra phia ngoai tam giac ACE can tai C biet ACE=ABD cho M trung diem BC so sanh MD,ME
cho tam giac ABC co dung cao AH.ve ra ngoai tam giac ABC cac tam giac can ABD,ACE,goc ABD=goc ACE=90 do .qua C ve duong thang vuong goc BE cat ah tai k .chung minh AK=BC
cho tam giac ABC can tai A (a<90 do) ke BD vuong tAC ( D thuoc AC) CE vuong AB (E thuoc AB)
BD ca CE cat nhau tai H
a)c/m tam giac ABD = tam giac ACE
cho tam giac abc vuong can tai a,ve ra phia ngoai tam giac 2 tam giac deu abd va ace,biet be=cd
goi i =be cat cd.tinh goc bic
Ve tam giac ABC va DBC lan luot vuong can tai A va D (A va D nam tren hai nua mat phang khac nhau bo BC)
a)CM: tam giac ABD vuong can
b)Goi E la trung diem cua BC. Tu C ke duong thang vuong goc voi AE, cat AE tai M, cat AB tai F. CMR:F la trung diem cua AB
cho tam giac abc can tai a, a nho hon 90. ve bd vuong goc voi ac tai d, ce vuong goc voi ab tai e. goi i la giao diem cua bd va ce. goi m la trung diem cua bc cm a,m,i thang hang