\(4x^4-16-4x^2-16x\)

\(=4x^2\left(x^2-1\right)-16\left(1+x\right)\)

\(=4x^2\left(x+1\right)\left(x-1\right)-16\left(x+1\right)\)

\(=\left(x+1\right)\left[4x^2\left(x-1\right)-16\right]\)

\(=\left(x+1\right)4\left[x^2\left(x-1\right)-4\right]\)

Nguyễn Văn Tuấn AnhNs r, không biết thì not làm

\(4x^4-16-4x^2-16x\)

\(=4x^2\left(x^2-1\right)-16\left(x+1\right)\)

\(=4x^2\left(x-1\right)\left(x+1\right)-16\left(x+1\right)\)

\(=\left(x+1\right)\left[4x^2\left(x-1\right)-16\right]\)

\(=4\left(x+1\right)\left[x^2\left(x-1\right)-4\right]\)

\(=4\left(x+1\right)\left[x^3-x^2-4\right]\)

\(=4\left(x+1\right)\left[x^3+x^2+2x-2x^2-2x-4\right]\)

\(=4\left(x+1\right)\left[x\left(x^2+x+2\right)-2\left(x^2+x+2\right)\right]\)

\(=4\left(x+1\right)\left(x-2\right)\left(x^2+x+2\right)\)

๖ۣۜMαɾαƙαĭ ⁹⁀ᶦᵈᵒᶫ  bạn đừng ns thế người ta không biết làm nhưng vẫn cố gắng giúp 

nếu bạn ấy làm sai thì vẫn có những người như bạn sửa

\(4x^2-y^2+8x-16\)

\(=\left(2x\right)^2-\left(y-4\right)^2=\left(2x-y+4\right)\left(2x+y-4\right)\)

4x² - y² + 8y - 16

= 4x² - (y² - 8y + 16)

= (2x)² - (y - 4)²

= [2x - (y - 4)][2x + (y - 4)]

= (2x - y +4)(2x + y - 4)

Câu 1:

\(=x^2-\left(y-4\right)^2\)

\(=\left(x-y+4\right)\cdot\left(x+y-4\right)\)

\(\left(x-4\right)^2-9^2=\left(x-13\right)\left(x+5\right)\)

\(16-x^2\)

\(=\left(4-x\right)\left(4+x\right)\)

\(---\)

\(16-3x+1^2\) (kt lại đề bài nhé)

\(x^4y^4+4x^2y^2+4\)

\(=\left[\left(xy\right)^2\right]^2+2\cdot\left(xy\right)^2\cdot2+2^2\)

\(=\left[\left(xy\right)^2+2\right]^2=\left(x^2y^2+2\right)^2\)

\(---\)

\(y^2-4y+4-x^2\)

\(=y^2-2\cdot y\cdot2+2^2-x^2\)

\(=\left(y-2\right)^2-x^2\)

\(=\left(y-2-x\right)\left(y-2+x\right)\)

bạn ơi 4x^2 là j ạ

\(4xy-4x^2-y^2+16\)

\(=16-\left(4x^2-4xy+y^2\right)\)

\(=16-\left(2x-y\right)^2\)

\(=\left(4+2x-y\right)\left(4-2x+y\right)\)

\(a,=x\left(x+5\right)\\ b,=\left(y-1\right)^2-4x^2=\left(y-1-2x\right)\left(y-1+2x\right)\\ c,\text{Không phân tích đc}\)

a) \(x^{2}+5x=x(x+5)\)

b)\(y^{2}-4x^{2}-2y+1 = (y-1)^{2}-4x^{2}=(y-1-2x)(y-1+2x)\)

c)\(x^{2}-8x+16=(x-4)^{2}\)

= 4 ( x² +4x+4) = 4(x+2)²

6-4x=2(3-2x)= -2(2x-3) 

có chung 2x-3 nhé , PT ở thành (2x-3)^2-2(2x-3) =(2x-3)(2x-3-2) =(2x-3)(2x-1)

\(\left(2x-3\right)^2+6-4x\)

\(=4x^2-12x+9+6-4x\)

\(=4x^2-16x+15\)

\(=\left(4x^2-10x\right)-\left(6x-15\right)\)

\(=2x\left(2x-5\right)-3\left(2x-5\right)\)

\(=\left(2x-3\right)\left(2x-5\right)\)