Ai giải giùm mk bài này vs
Giải pt: \(\left(x+5\right)\sqrt{2x^2+1}=x^2+x+5\)
Giải nhanh nha mn
Mai mk thi mất r .-.
Giải PT:
\(\sqrt{x-1}\)+\(\sqrt{x+3}\)+\(2\sqrt{\left(x-1\right)\left(x^2-3x+5\right)}\)=4-2x
Các bạn ơi giải giúp mk với mai mk phải nộp cho cô rồi. Ai làm nhanh mk THƯỞNG 5 SAO
mn giải giùm mk bài này nka: giải hệ phương trình:
\(\sqrt{5}x-y=\sqrt{5}\cdot\left(\sqrt{3}-1\right)\)
\(2\sqrt{3}x+3\sqrt{5}y=21\)
\(\int^{\sqrt{5}x-y=\sqrt{5}\left(\sqrt{3}-1\right)}_{2\sqrt{3}x+3\sqrt{5}y=21}\Leftrightarrow\int^{y=\sqrt{5}x-\sqrt{5}\left(\sqrt{3}-1\right)}_{2\sqrt{3}x+3\sqrt{5}\left(\sqrt{5}x-\sqrt{5}\left(\sqrt{3}-1\right)\right)=21}\)
\(\Leftrightarrow\int^{y=\sqrt{5}x-\sqrt{5}\left(\sqrt{3}-1\right)}_{2\sqrt{3}x+15x-15\sqrt{3}+15=21}\Leftrightarrow\int^{y=\sqrt{5}x-\sqrt{5}\left(\sqrt{3}-1\right)}_{\left(2\sqrt{3}+15\right)x=6+15\sqrt{3}}\)
\(\Leftrightarrow\int^{y=\sqrt{5}x-\sqrt{5}\left(\sqrt{3}-1\right)}_{x=\frac{6+15\sqrt{3}}{2\sqrt{3}+15}}\Leftrightarrow\int^{y=\sqrt{5}\sqrt{3}-\sqrt{5}\sqrt{3}+\sqrt{5}=\sqrt{5}}_{x=\sqrt{3}}\)
Vậy nghiệm của hpt là: \(\int^{x=\sqrt{3}}_{y=\sqrt{5}}\)
1.
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
CÓ 1 BÀI THUI NHA, MONG MN GIẢI NHANH GIÚP MK
AI NHANH MK CHO 1 TICK, MK ĐANG RẤT CẦN ĐẤY
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\frac{18}{x+3}+1\)
\(\Leftrightarrow\frac{20}{x+3}-8=8-\frac{18}{x+3}\)
\(\Leftrightarrow\frac{20}{x+3}+\frac{18}{x+3}=8+8\)
\(\Leftrightarrow\frac{38}{x+3}=16\)
\(\Leftrightarrow x+3=2,375\)
\(\Leftrightarrow x=-0,625\)
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\left(\frac{18}{x+3}+1\right)\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\frac{18}{x+3}-1\)
\(\Leftrightarrow\frac{20}{x+3}+\frac{18}{x+3}=7-1+8\)
\(\Leftrightarrow\frac{38}{x+3}=14\)
\(\Leftrightarrow\left(x+3\right)14=38\)
\(\Leftrightarrow14x+42=38\)
\(\Leftrightarrow14x=-4\Leftrightarrow x=-\frac{4}{14}=-\frac{2}{7}\)
Vậy \(x=-\frac{2}{7}\)
Giải các pt sau
a/\(\frac{3}{x+2}=1-\frac{2}{x-3}\)
b/ \(\frac{2x}{2x^2-5x+2}+\frac{13x}{3x^2+x+2}=6\)
c/ \(x^2+\frac{4x^2}{\left(x-2\right)^2}=4\)
d/\(\left(x+2\right).\left(x+4\right)+5.\left(x+2\right).\sqrt{\frac{x+4}{x+2}}=6\)
Giải nhanh dùm mk nha mk đang cần gấp
giải chi tiết bài này giùm mình nha!!!
giải pt
\(\sqrt{x-2008}+\sqrt{y-2009}+\sqrt{z-2010}=\frac{1}{2}\left(x+y+z\right)\)
Mn ơi giúp mk với ... giải giúp mk bài toán này trg tối nay thôi nhé... Làm ơn mk đang cần gấp lắm!!!
Tìm x biết,
a) \(9\left(3x-2\right)=x\left(2-3x\right)\)
b) \(\left(2x-1\right)^2-\left(2x+5\right)\left(2x-5\right)=18\)
c) \(5x\left(x-5\right)-2x+10=0\)
d) \(x^2-5=0\)
e) \(x^3+5x^2-4x-20=0\)
f) \(x^3+2\sqrt{2x^2}+2x=0\)
Mn ơi giúp mk với ... cảm ơn rất nhiều...!!!
b)(2x - 1)^2 - (2x + 5) (2x - 5 ) = 18
4x 2 -4x+1-4x 2+25=18
26-4x=18
4x=8
x=2
a,27x-18=2x-3x^2
<=> 3x^2-2x+27-18x=0
<=> 3x^2-20x+27=0
\(\Delta\)= 20^2-4-12.27
tính \(\Delta\)rồi tìm x1 ,x2
â)\(9\left(3x-2\right)=x\left(2-3x\right)\)
\(\Leftrightarrow27x-18=2x-3x^2\)
\(\Leftrightarrow27x-18-2x+3x^2=0\)
\(\Leftrightarrow3x^2+25x-18=0\)
\(\Leftrightarrow3x^2+27x-2x-18=0\)
\(\Leftrightarrow\left(3x-2\right)\left(x+9\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x-2=0\\x+9=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{2}{3}\\x=-9\end{cases}}\)
b)\(\left(2x-1\right)^2-\left(2x+5\right)\left(2x-5\right)=18\)
\(\Leftrightarrow4x^2-4x+1-4x^2+25=18\)
\(\Leftrightarrow26-4x=18\)
\(\Leftrightarrow4x=8\)
\(\Rightarrow x=2\)
c)\(5x\left(x-5\right)-2x+10=0\)
\(\Leftrightarrow5x^2-10x-2x+10=0\)
\(\Leftrightarrow5x^2-12x+10=0\)
\(\Leftrightarrow x^2-6x+2=0\)
\(\Leftrightarrow x^2-6x+9-7=0\)
\(\Leftrightarrow\left(x-3\right)^2=7\)
\(\Rightarrow\orbr{\begin{cases}x-3=\sqrt{7}\\x-3=-\sqrt{7}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\sqrt{7}+3\\x=-\sqrt{7}+3\end{cases}}\)
d)\(x^2-5=0\)
\(\Leftrightarrow x^2=5\)
\(\Rightarrow x=\sqrt{5};-\sqrt{5}\)
e)\(x^3+5x^2-4x-20=0\)
\(\Leftrightarrow x^3-2x^2+7x^2-14x+10x-20=0\)
\(\Leftrightarrow x^2\left(x-2\right)+7x\left(x-2\right)+10\left(x-2\right)=0\)
\(\Leftrightarrow\left(x^2+7x+10\right)\left(x-2\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x+5\right)\left(x-2\right)=0\)
\(\Leftrightarrow\left(x^2-4\right)\left(x+5\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+5=0\\x^2-4=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=-5\\x^2=4\end{cases}\Rightarrow}\orbr{\begin{cases}x=-5\\x=-2;2\end{cases}}\)
giải phương trình
\(2x+1+x\sqrt{x^2+2}+\left(x+1\right).\sqrt{x^2+2x+3}=0.\)
GIẢI GIÚP MK NHA MN - THANKS ~``!!!
(2) giải pt:
a) \(\sqrt{4-2x}=5\)
b) \(\sqrt{25\left(x+1\right)}+\sqrt{9x+9}=16\)
\(\sqrt{4x^2+12x+9}=4\)
giúp mk vs ạ mai mk hc rồi
a, ĐKXĐ: \(x\le2\)
\(\sqrt{4-2x}=5\\ \Leftrightarrow4-2x=25\\ \Leftrightarrow2x=-21\\ \Leftrightarrow x=-10,5\left(tm\right)\)
b, ĐKXĐ: \(x\ge-1\)
\(\sqrt{25\left(x+1\right)}+\sqrt{9x+9}=16\\ \Leftrightarrow5\sqrt{x+1}+\sqrt{9\left(x+1\right)}=16\\ \Leftrightarrow5\sqrt{x+1}+3\sqrt{x+1}=16\\ \Leftrightarrow8\sqrt{x+1}=16\\ \Leftrightarrow\sqrt{x+1}=2\\ \Leftrightarrow x+1=4\\ \Leftrightarrow x=3\)
c, \(\sqrt{4x^2+12x+9}=4\Leftrightarrow4x^2+12x+9=16\\ \Leftrightarrow4x^2+12x-7=0\\ \Leftrightarrow\left(4x^2-2x\right)+\left(14x-7\right)=0\\ \Leftrightarrow2x\left(2x-1\right)+7\left(2x-1\right)=0\\ \Leftrightarrow\left(2x-1\right)\left(2x+7\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{7}{2}\end{matrix}\right.\)
a: \(\Leftrightarrow4-2x=25\)
hay \(x=-\dfrac{21}{2}\)
c: \(\Leftrightarrow\left|2x+3\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}2x+3=4\\2x+3=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{7}{2}\end{matrix}\right.\)
giải pt \(2+\sqrt[3]{9x^2\cdot\left(x+2\right)}=2x+3\sqrt[3]{3x\cdot\left(x+2\right)^2}\)
giúp mk nha mk cần gấp
\(2+\sqrt[3]{b^2a}=\frac{3}{2}b+\sqrt[3]{a^2b}\)