a) -105 - 5.x = (-5)^2

=>-105 - 5.x = 25

=> 5.x = -105 - 25

=> 5.x = -130

=> x = -130: 5

=> x = -26

c) 400 -4.|5-x| = (-6)^2

=>400- 4.|5-x| = 36

=> 4.|5-x| = 400-36

=> 4.|5-x| = 364

=> |5-x| = 364:4

=> |5-x| = 91

=> \(\left[\begin{matrix}5-x=91\\5-x=-91\end{matrix}\right.\)

=> \(\left[\begin{matrix}x=5-91\\x=5-\left(-91\right)\end{matrix}\right.\)

^{=> \(\left[\begin{matrix}x=-86\\x=96\end{matrix}\right.\)}

d) 2.|x-1| -5 = -15

=>2.|x-1| = -15+5

=>2.|x-1| = 10

=> |x-1| = 10:2

=> |x-1| = 5

=> \(\left[\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\)

=>

3: 

\(=\dfrac{1}{7}\cdot\dfrac{3}{5}\cdot\dfrac{5}{6}\cdot\dfrac{5}{8}=\dfrac{1}{7}\cdot\dfrac{1}{2}\cdot\dfrac{5}{8}=\dfrac{5}{112}\)

4:

=>2/3:x=-2-1/3=-7/3

=>x=-2/3:7/3=-2/7

5:

AC=CB=12/2=6cm

IB=6/2=3cm

1a/ \(\left(15-x\right)+\left(x-12\right)=7-\left(-5+x\right)\)

=> \(\left(15-x\right)+\left(x-12\right)+\left(-5+x\right)=7\)

=> \(15-x+x-12-5+x=7\)

=> \(\left(15-12-5\right)-\left(x+x+x\right)=7\)

=> \(\left(15-12-5\right)-7=3x\)

=> \(3x=-2-7\)

=> \(3x=-9\)

=> \(x=\frac{-9}{3}=-3\)

b/ \(x-\left\{57-\left[42+\left(-23-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\)

=> \(x-57-42-23-x=13-47+25-32+x\)

=> \(x-x+x=13-47+25-32+57+42+23\)

=> \(x=\left(13+23\right)-\left(47+57\right)+\left(25+57\right)-\left(32+42\right)\)

=> \(x=36-104+82-74\)

=> \(x=-60\)

d/ \(\left(x-3\right)\left(2y+1\right)=7\)

Vì 7 là số nguyên tố nên ta có 2 trường hợp:

TH1: \(\hept{\begin{cases}x-3=1\\2y+1=7\end{cases}}\)=> \(\hept{\begin{cases}x=4\\y=3\end{cases}}\).

TH2: \(\hept{\begin{cases}x-3=7\\2y+1=1\end{cases}}\)=> \(\hept{\begin{cases}x=10\\y=0\end{cases}}\).

Các cặp (x, y) thoả mãn điều kiện: \(\left(4;3\right),\left(10;0\right)\).

sai đề tích nha

Đề sai nha! Đăng lại nhé!

ung ho mih nha cac bn

Bài 1:

a)

\(A=\dfrac{-5}{6}\cdot\dfrac{3}{10}\\ =\dfrac{\left(-5\right)\cdot3}{6\cdot10}\\ =\dfrac{-1}{4}\)

b)

\(B=\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{12}\\ =\dfrac{4}{12}-\dfrac{3}{12}+\dfrac{1}{12}\\ =\dfrac{4-3+1}{12}\\ =\dfrac{1}{6}\)

Bài 2:

\(A=\left(\dfrac{-1}{5}\right)\cdot\dfrac{15}{4}+\left|\dfrac{4}{5}-\dfrac{14}{5}\right|:\dfrac{8}{3}\\ =\left(\dfrac{-1}{5}\right)\cdot\dfrac{15}{4}+\left|\dfrac{-10}{5}\right|\cdot\dfrac{3}{8}\\ =\left(\dfrac{-1}{5}\right)\cdot\dfrac{15}{4}+2\cdot\dfrac{3}{8}\\ =\dfrac{-3}{4}+\dfrac{3}{4}\\ =0\)

\(B=\left(\dfrac{-1}{2}\right)^2:1\dfrac{3}{8}+25\%\cdot\dfrac{3}{11}\\ =\left(\dfrac{-1}{2}\right)^2:\dfrac{11}{8}+\dfrac{3}{4}\cdot\dfrac{3}{11}\\ =\dfrac{1}{4}\cdot\dfrac{8}{11}+\dfrac{3}{4}\cdot\dfrac{3}{11}\\ =\dfrac{8}{44}+\dfrac{9}{44}\\ =\dfrac{17}{44}\)

\(C=\dfrac{-8}{5}+0,6+\left|\dfrac{-1}{2}\right|+\dfrac{1}{2}\\ =\dfrac{-8}{5}+\dfrac{3}{5}+\dfrac{1}{2}+\dfrac{1}{2}\\ =\left(\dfrac{-8}{5}+\dfrac{3}{8}\right)+\left(\dfrac{1}{2}+\dfrac{1}{2}\right)\\ =\left(-1\right)+1\\ =0\)

\(D=\dfrac{-5}{9}\cdot\dfrac{2}{13}+\dfrac{-5}{9}:\dfrac{13}{11}+1\dfrac{5}{9}\\ =\dfrac{-5}{9}\cdot\dfrac{2}{13}+\dfrac{-5}{9}\cdot\dfrac{11}{13}+\dfrac{14}{9}\\ =\dfrac{-5}{9}\cdot\left(\dfrac{2}{13}+\dfrac{11}{13}\right)+\dfrac{14}{9}\\ =\dfrac{-5}{9}\cdot1+\dfrac{14}{9}\\ =\dfrac{-5}{9}+\dfrac{14}{9}\\ =1\)

Bài 3:

a)

\(\dfrac{x}{2}+\dfrac{3}{4}=\dfrac{1}{4}\\ \dfrac{x}{2}=\dfrac{1}{4}-\dfrac{3}{4}\\ \dfrac{x}{2}=\dfrac{-1}{2}\\ \Rightarrow x=-1\)

b)

\(\dfrac{3}{5}x+0,4x=2\\\dfrac{3}{5}x+\dfrac{2}{5}x=2\\ x\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=2\\ x=2 \)

c)

\(\dfrac{x}{-3}=\dfrac{7}{6}+\left(\dfrac{-15}{18}\right)\\ \dfrac{-x}{3}=\dfrac{1}{3}\\ \Rightarrow-x=1\\ \Leftrightarrow x=-1\)

d)

\(\dfrac{4}{3}\cdot\left(\dfrac{1}{6}-\dfrac{1}{2}\right)< x< \dfrac{2}{3}\cdot\left(\dfrac{-1}{6}+\dfrac{3}{4}\right)\\ \Leftrightarrow\dfrac{4}{3}\cdot\dfrac{-1}{3}< x< \dfrac{2}{3}\cdot\dfrac{7}{12}\\ \Leftrightarrow\dfrac{-4}{9}< x< \dfrac{7}{18}\\ \Rightarrow x=0\)

Bài 1 : Tìm x

1/-(-30)-(-x)=-(+13)

⇒30+x=-13

⇒x=-13-30

⇒x=-43

2/ -(+12)-(+x)=-(+13)

⇒-12-x=-13

⇒x=-12+13

⇒x=1

3/ (-34)-x=-(-45)

⇒x=-34-45

⇒x=-79

4/-(-x)+(-15)=(-12)

⇒x-15=-12

⇒x=-12+15

⇒x=3

5/-15-x=-(-7)

⇒x=-15-7

⇒x=-22

Bài 2 : Tính

1/ (-15)-/-10/+/-9/-/-5/

=-15-10+9-5

=-21

2/14-(-13)-(-21)+(-32)

=14+13+21-32

=16

3/(-12)-(-17)-(-21)+(-32)

= -12+17+21-32

=-6

4/-/-14/ + /-10/-(-12)+(-8)

=-14+10+12-8

=0

5/-(-11)+(-15)+(+13)-21

=11-15+13-21

=-12

Các CVT giúp e vs ạ : @Phạm Thị Diệu Huyền , @Vũ Minh Tuấn , @Nguyễn Thành Trương , @HISINOMA KINIMADO , @Trần Thanh Phương , @buithianhtho , @Nguyễn Huyền Trâm , @Vy Lan Lê , @Trần Thị Hà My , @Vương Thị Thanh Hoa , @Nguyễn Văn Đạt , @Vũ Như Quỳnh , @phạm hoàng lê nguyên , @nguyen thi vang , @Nguyễn Thị Diễm Quỳnh , @Hùng Nguyễn , @Thảo Phương , @Hồ Bảo Trâm , @Nguyễn Nhật Minh , ... và 1 số CVT khác giúp mk nhé .

\(1a.8\left(x-7\right)-6\left(x-2\right)=\left|-8\right|.\left(-5\right)\\ \Leftrightarrow8x-56-6x+12=8.\left(-5\right)\\ \Leftrightarrow8x-6x-56+12=40\\\Leftrightarrow 2x=56-12-40\\ \Leftrightarrow2x=4\\ \Leftrightarrow x=2\)

\(b.-7\left(x-5\right)+2\left(7x-14\right)=28\\ \Leftrightarrow-21x+35+14x-28=28\\ \Leftrightarrow-21x+14x=-35+28+28\\ \Leftrightarrow-7x=21\\ \Leftrightarrow x=-3\)

\(c.2x+12=3\left(x-7\right)\\ \Leftrightarrow2x+12=3x-21\\\Leftrightarrow 2x-3x=-12-21\\ \Leftrightarrow-x=-33\\ \Leftrightarrow x=33\)

\(2.a.6x+1⋮3x-1\\ \Rightarrow6x-2+3⋮3x-1\\ \Rightarrow2\left(3x-1\right)+3⋮3x-1\\ \Rightarrow3⋮3x-1\\ \Rightarrow3x-1\inƯ_{\left(3\right)}=\left\{1;3;-1;-3\right\}\\ \)

Lập bảng

Vì x là số nguyên nên x=0