1, CO2+H2O--->H2CO3

2, SO3+H2O--->H2SO4

3, SO2+H2O--->H2SO3

4, N2O5+H2O---> 2HNO3

5, P2O5+3H2O--->2H3PO4

6, SO2+K2O--->K2SO3

7, CO2+BaO--->BaCO3

8, SO3+Na2O--->Na2SO4

9, P2O5+3CaO--->Ca3(PO4)2

10, N2O5+K2O--->2KNO3

11, CO2+2NaOH--->Na2CO3+H2O

12, SO2+Ca(OH)2--->CaSO3+H2O

13, SO3+Ba(OH)2--->BaSO4+H2O

14, N2O5+2KOH--->2KNO3+H2O

15, P2O5+3Ba(OH)2--->Ba3(PO4)2+3H2O

16, Na2O+H2O--->2NaOH

17, K2O+H2O--->2KOH

18, CaO+H2O--->Ca(OH)2

19, BaO+H2O--->Ba(OH)2

20, Al2O3+6HCl--->2AlCl3+3H2O

21, Fe2O3+6HNO3---> 2Fe(NO3)3+3H2O

22, ZnO+H2SO4--->ZnSO4+H2O

23, 3CaO+2H3PO4--->Ca3(PO4)2+3H2O

24, Fe+2HCl--->FeCl2+H2

25, Mg+H2SO4--->MgSO4+H2

26, 2Al+6HCl--->2AlCl3+3H2

27, Zn+H2SO4---->ZnSO4+H2

28, Cu+2H2SO4---> CuSO4+SO2+2H2O

29, Al(OH)3+3HCl--->AlCl3+3H2O

30, Zn(OH)2+H2SO4--->ZnSO4+2H2O

1. CO₂ + H₂O --> H₂CO₃

2. SO₃ + H₂O --> H₂SO₄

3. SO₂ + H₂O --> H₂SO₃

4. N₂O₅ + H₂O --> 2HNO₃

5. P₂O₅ + 3H₂O --> 2H₃PO₄

6. SO2 + K2O --> K2SO3

7. CO2 + BaO --> BaCO3

8. SO3 + NA2O --> Na2SO3

9. P2O5 + 3CaO --> Ca3(PO4)2

10. N2O5 + K2O --> 2KNO3

11. CO2 + NaOH --> Na₂CO₃ + H₂O

hoặc CO₂ + NaOH → NaHCO₃

12. CO2+Ca(OH)2−−−>CaCO3+H2O

13. SO3 + Ba(OH)2 --> BaSO4 + H2O

14. N2O5 + 2KOH --> 2KNO3 + H2O

15. P2O5 + 3Ba(OH)2 --> Ba3(PO4)2 + 3H2O

Tối rùi đến đó thui nhé :3

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1.Hãy tính số mol có trong:
\(a.27,2\left(g\right)ZnCl_2\\ n_{ZnCl_2}=\dfrac{27,2}{136}=0,2\left(mol\right)\\ b.V_{O_2\left(đktc\right)}=11,2\left(l\right)\\ n_{O_2}=\dfrac{11,2}{22,4}=0,5\left(mol\right)\\ c.150\left(ml\right)ddNaOH2M\\ n_{NaOH}=0,15.2=0,3\left(mol\right)\\ d.200\left(g\right)ddH_2SO_419,6\%\\ n_{H_2SO_4}=\dfrac{200.19,6\%}{98}=0,4\left(mol\right)\)
Cho 2,7gam Al phản ứng với dd có chứa 29,4gam H2SO4.
a. Lập PTHH
b. Chất nào dư sau phản ứng và dư bao nhiêu gam.
c. Tính khối lượng muối thu được.
d. Tính thể tích khí sinh ra( đktc).

----

\(a.2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\\ n_{Al}=\dfrac{2,7}{27}=0,1\left(mol\right)\\ n_{H_2SO_4}=\dfrac{29,4}{98}=0,3\left(mol\right)\\b. Vì:\dfrac{0,1}{2}< \dfrac{0,3}{3}\Rightarrow H_2SO_4dư\\ m_{H_2SO_4\left(dư\right)}=98.\left(0,3-0,1.\dfrac{3}{2}\right)=14,7\left(g\right)\\ c.n_{Al_2\left(SO_4\right)_3}=\dfrac{0,1}{2}=0,05\left(mol\right)\\ m_{Al_2\left(SO_4\right)_3}=342.0,05=17,1\left(g\right)\\ d.n_{H_2}=\dfrac{3}{2}.0,1=0,15\left(mol\right)\\ V_{H_2\left(đktc\right)}=0,15.22,4=3,36\left(l\right)\)

Bài gọi tên phân loại hình như em làm rồi mà?

1.

a,\(n_{ZnCl_2}=\dfrac{27,2}{136}=0,2\left(mol\right)\)

b,\(n_{O_2}=\dfrac{11,2}{22,4}=0,5\left(mol\right)\)

c,\(n_{NaOH}=0,15.2=0,3\left(mol\right)\)

d,\(m_{H_2SO_4}=200.19,6\%=39,2\left(g\right)\Rightarrow n_{H_2SO_4}=\dfrac{39,2}{98}=0,4\left(mol\right)\)

2.

a, \(n_{Al}=\dfrac{2,7}{27}=0,1\left(mol\right);n_{H_2SO_4}=\dfrac{29,4}{36,5}=0,3\left(mol\right)\)

PTHH: 2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

Mol:     0,1       0,15              0,05        0,15

b,Ta có: \(\dfrac{0,1}{2}< \dfrac{0,3}{3}\) ⇒ Al hết, H₂SO₄ dư

\(m_{H_2SO_4dư}=\left(0,3-0,15\right).98=14,7\left(g\right)\)

c,\(m_{Al_2\left(SO_4\right)_3}=0,05.342=17,1\left(g\right)\)

d,\(V_{H_2}=1,5.22,4=3,36\left(l\right)\)

\(a,4K+O_2\overset{t^0}{\rightarrow}2K_2O\)

\(K_2O+H_2O\rightarrow2KOH\)

\(KOH+HCl\rightarrow KCl+H_2O\)

\(b,S+O_2\overset{t^0}{\rightarrow}SO_2\)

\(2SO_2+O_2\overset{t^0}{\rightarrow}2SO_3\)

\(SO_3+H_2O\rightarrow H_2SO_4\)

Viết lần lượt nhé: SO₃, FeCl₂, Mg(OH)₂, Zn₃(PO₄)₂, Pb(NO₃)₂, Al₂(SO₄)₃, H₂SO₃, NaOH, P₂O₅, HCl, CaCO₃, HgO, BaSO₃

31. Fe(OH)2 + 2HCl = 2H2O + FeCl2

32. HNO3 + NaOH --> H2O + NaNO3

33. BaSO4 + 2HNO3 = Ba(NO3)2 + H2SO4

34. CaCO3 + 2HCL => CaCl2 +H2O +CO2

35. HCL + AgNO3 ---> AgCl + HNO3

36. FeS +2 HCl --> FeCl2 + H2S ( sắt 2 ms đúng chứ :V)

37. FeCO3 + H2SO4 (đặc nóng) --> Fe2(CO3)2 + SO2 + CO2 + H2O

38. 2Al(OH)3 -t'--> Al2O3 + 3H2O

39. 2Fe(OH)3 -t'--> Fe2O3 + 3H2O

40. Zn(OH)2 --> ZnO + H2O

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31. Fe(OH)₂ + 2HCl \(\rightarrow\) FeCl₂ + 2H₂O

32. NaOH + HNO₃ \(\rightarrow\) NaNO₃ +H₂O

33. BaSO₃ + 2HNO₃ \(\rightarrow\) Ba(NO₃)₂ + H₂O +SO₂

34. CaCO₃ + 2HCl \(\rightarrow\) CaCl₂ + H₂O + CO₂

35. ko xảy ra

36. ko xảy ra

37. Fe₂(SO₃)₃ + 3H₂SO4 \(\rightarrow\) Fe₂(SO₄)₃ +3 H₂O +3SO₂

38. 2Al(OH)₃ \(\xrightarrow[]{t}\) Al₂O₃ + 3H₂O

39. 2Fe(OH)₃ \(\xrightarrow[]{t}\) Fe₂O₃ + 3H₂O

40. Zn(OH)₂ \(\xrightarrow[]{t}\) ZnO + H₂O

41. Mg(OH)₂ \(\xrightarrow[]{t}\) MgO + H₂O

42. Zn(NO₃)₂ + 2KOH \(\rightarrow\) Zn(OH)₂ + 2KNO₃

43, FeCl₃ + 3NaOH \(\rightarrow\) Fe(OH)₃ + 3NaCl

44. MgSO₄ + Ca(OH)₂ \(\rightarrow\) Mg(OH)₂ + CaSO4

45. K₂CO₃ + Ba(OH)₂ \(\rightarrow\) 2KOH + BaCO₃

31, Fe(OH)2+2HCl--->FeCl2+2H2O

32, NaOH+HNO3--->NaNO3+H2O

33, BaSO3+2HNO3--->Ba(NO3)2+SO2+H2O

34, CaCO3+2HCl--->CaCl2+CO2+H2O

35, AgNO3+HCl--->AgCl+HNO3

36, Fe2S3+6HCl--->2FeCl3+3H2S

37, FeSO3+H2SO4--->FeSO4+SO2+H2O

38, 2Al(OH)3--->Al2O3+3H2O

39, 2Fe(OH)3--->Fe2O3+3H2O

40, Zn(OH)2--->ZnO+H2O

41, Mg(OH)2--->MgO+H2O

42, Zn(NO3)2+2KOH--->Zn(OH)2+2KNO3

43, FeCl3+3NaOH---> Fe(OH)3+3NaCl

44, MgSO4+Ca(OH)2--->Mg(OH)2+CaSO4

45, K2CO3+Ba(OH)2--->BaCO3+2KOH

1,Fe2O3 + 6HCl-> 2FeCl3 + 3H2O

2,Ca(OH)2 + H2SO4 -> CaSO4 + 2H2O

3,2Al + 6HCl -> 2AlCl3 + 3H2

4,Ba(NO3)2 + K2SO4 -> BaSO4 + 2KNO3

5, FeCl3 + 3KOH -> Fe(OH)3 + 3KCl

6, SO2 + H2O -> H2SO3

7, P2O5 + 6NaOH -> 2Na3PO4 + 3H2O

8, SO3 + 2KOH -> K2SO4 + H2O

9, Al2S3 + 6HCl -> 3H2S + 2AlCl3

10, Ca(HCO3)2 + 2HCl -> CaCl2 + 2CO2 + 2H2O

11, chưa cân bằng xong

12, 2K + 2H2O -> 2KOH + H2

13, Fe3O4 + 8HCl -> 2FeCl3 + FeCl2 + 4H2O

14, Ca(OH)2 + FeSO4 -> CaSO4 + Fe(OH)2

1. \(Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2O\)
2. \(Ca\left(OH\right)_2+H_2SO_4\rightarrow CaSO_4+2H_2O\)
3. \(2Al+6HCl\rightarrow2AlCl_3+3H_2\uparrow\)
5. \(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3\downarrow+3KCl\)
6. \(SO_2+H_2O\rightarrow H_2SO_3\)
7. \(P_2O_5+6NaOH\rightarrow2Na_3PO_4+3H_2O\)
8. \(SO_3+2KOH\rightarrow K_2SO_4+H_2O\)
9. \(Al_2S_3+6HCl\rightarrow3H_2S\uparrow+2AlCl_3\)
12. \(2K+2H_2O\rightarrow2KOH+H_2\uparrow\)
13. \(Fe_3O_4+8HCl\rightarrow2FeCl_3+FeCl_2+4H_2O\)
14. \(Ca\left(OH\right)_2+FeSO_4\rightarrow CaSO_4+Fe\left(OH\right)_2\)

1) Fe₂O₃ + 6HCl\(\rightarrow\) 2FeCl₃ + 3H₂O.

2) Ca(OH)₂ + H₂SO₄\(\rightarrow\) CaSO₄ + 2H₂O

Natri hiđroxit: NaOH

Sắt(II) oxit: FeO

Canxi đihiđrophotphat: Ca(H₂PO₄)₂

Lưu huỳnh trioxit: SO₃

Đồng(II) hiđroxit: Cu(OH)₂

Axit Nitric: HNO₃

Magie sunfit: MgSO₃

Axit sunfuhiđric: H₂S

Bazơ: Natri hidroxit: NaOH

Đồng(II)hidroxit: Cu(OH)₂

Muối: Canxi đihiđrôphotphat: CaH₂PO₄

Magie sunfit: MgSO₃

Axit; Axit Nitric: HNO₃

Axit sunfuhidric: H₂S

oxit bazo: Sắt(II) oxit: FeO

natri hiddroxit NaOH

sắt (II) oxit FeO

caxni đihiđrophotphat CaH₂PO₄

lưu huỳnh tri oxit SO₃

đồng (II) hidroxit Cu(OH)₂

axit nitric HNO₃

magie sunfit MgSO₃

axit sunfuhidric H₂S

\(1) Mg + 2HCl \to MgCl_2 + H_2\\ 2) Mg(OH)_2 \xrightarrow{t^o} MgO + H_2O\\ 3) BaCl_2 + K_2SO_4 \to BaSO_4 + 2KCl\\ 4) 2H_2 + O_2 \xrightarrow{t^o} 2H_2O\\ 5) CuO + H_2SO_4 \to CuSO_4 + H_2O\\ 6) 2Na + 2H_2O \to 2NaOH + H_2\\ 7) 2Al(OH)_3 + 6HCl \to 2AlCl_3 + 3H_2\\ 8) Fe + S \xrightarrow{t^o} FeS\\ 9) Mg + 2HCl \to MgCl_2 + H_2\\ 10) Ca(OH)_2 + CuSO_4 \to Cu(OH)_2 + CaSO_4\\ 11) Na_2O + 2HNO_3 \to 2NaNO_3 + H_2O\\ 12)CO_2 + 2KOH \to K_2CO_3 + H_2O\)

Bài 2 : 

1)  \(Mg+2HCl\rightarrow MgCl_2+H_2\)

2)  \(Mg\left(OH\right)_2\rightarrow\left(t_o\right)MgO+H_2O\)

3)  \(BaCl_2+K_2SO_4\rightarrow BaSO_4+2KCl\)

4) \(2H_2+O_2\rightarrow\left(t_o\right)2H_2O\)

5) \(CuO+H_2SO_4\rightarrow CuSO_4+H_2O\)

6) \(2Na+2H_2O\rightarrow2NaOH+H_2\)

7) \(Al\left(OH\right)_3+3HCl\rightarrow2AlCl_3+3H_2O\)

8) \(2Fe+4S\rightarrow\left(t_o\right)2FeS_2\)

10) \(Ca\left(OH\right)_2+Cu\left(NO_3\right)_2\rightarrow Ca\left(NO_3\right)_2+\)\(Cu\left(OH\right)_2\)

11) \(Na_2O+HNO_3\rightarrow NaNO_3+H_2O\)

12) \(CO_2+2KOH\rightarrow K_2CO_3+H_2O\)

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