\(2^{x-1}\)\(+5.2^{x-2=\frac{7}{32}}\)
2\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
Tìm x
\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
a. 2x-1+ 5.2x-1:2=7/32
=> 2x+1.(1+5/2)=7/32
=>2x+1.7/2=7/32
=> 2x+1=1/16=1/24
=> x+1=-4=>x=-5
\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
\(\Rightarrow2^{x-1}+5.2^{x-1}.2^3=\frac{7}{32}\)
\(\Rightarrow2^{x-1}.\left(1+5.2^3\right)=\frac{7}{32}\)
\(\Rightarrow2^{x-1}.41=\frac{7}{32}\)
\(\Rightarrow2^{x-1}=\frac{7}{1312}\)
\(\Rightarrow\) Ko có x thỏa mãn
Tìm x:
\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
2x-1+5.2x-2=\(\frac{7}{32}\)
\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
\(\Rightarrow2^{x-1}+2^{x-1}.\frac{5}{2}=\frac{7}{32}\Rightarrow2^{x-1}.\left(1+\frac{5}{2}\right)=\frac{7}{32}\Rightarrow2^{x-1}.\frac{7}{2}=\frac{7}{32}\)
\(\Rightarrow2^{x-1}=\frac{7}{32}:\frac{7}{2}=\frac{7}{32}.\frac{2}{7}=\frac{1}{16}\)
\(\Rightarrow2^{x-1}=2^{-4}\Rightarrow x-1=-4\Rightarrow x=-4+1=-3\)
Tìm x:\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
ai ko bt = -3 giải rõ ràng đi
\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
\(2.2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
\(2^{x-2}.\left(5+2\right)=\frac{7}{32}\)
\(2^{x-2}.7=\frac{7}{32}\)
\(2^{x-2}=\frac{7}{32}:7\)
\(2^{x-2}=\frac{1}{32}\)
\(\Rightarrow x-2=-5\)
\(x=-5+2\)
Vậy \(x=-3\)
Tìm x biết:
2x-1+5.2x-1=\(\frac{7}{32}\)
\(2^{x-1}+5.2^{x-1}=\frac{7}{32}\)
=> \(2^{x-1}\left(1+5\right)=\frac{7}{32}\)
=> \(2^{x-1}.6=\frac{7}{32}\)
=> \(2^{x-1}=\frac{7}{32}:6=\frac{7}{192}\)
ĐỀ SAI RỒI BẠN !
tìm x : 2x-1 +5.2x-2=\(\frac{7}{32}\)
2x-1+5.2x-2=2.2x-2+5.2x-2=2x-2.(5+2)=2x-2.7=7/32
=>2x-2=7/32:7=1/32
=>x-2=-5
=>x=-3
2x-1+5.2x-2=\(\frac{7}{32}\)
2x-1+5.2x-2=2.2x-2+5.2x-2=2x-2.(5+2)=2x-2.7=7/32
=>2x-2=7/32:7=1/32
=>x-2=-5
=>x=-3
ĐOán thế
Hả ! Vừa thấy 732 cơ mà ! Làm mất công rồi ....
Số nguyên x thỏa mãn biểu thức: \(2^{x-1}+5.2^{x-2}=\frac{7}{32}\) là x= ......
\(\Rightarrow2^x:2+5.2^x:2=\frac{7}{32}\)
\(\Rightarrow2^x.\frac{1}{2}+5.2^x.\frac{1}{2}=\frac{7}{32}\)
\(\Rightarrow2^x.\left(\frac{1}{2}+\frac{5}{2}\right)=\frac{7}{32}\)
\(\Rightarrow2^x.3=\frac{7}{32}\Rightarrow2^x=\frac{7}{96}\)
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