phan tich thanh nhan tu:
\(x^2+6y^2+5xy+4x+7y-5\)
phan tich thanh nhan tu chung
Phan tich thanh nhan tu ( bang ki thuat bo sung hang dang thuc):
x^2-4xy-x+3y^2+3y
x^2+4xy+2x+3y^2+6y
6x^2+xy-7x-2y^2+7y-5
6a^2-ab-2b^2+a+4b
phan tich da thuc thanh nhan tu :
5x^2 + 5xy - x - y
7x - 6x^2 - 2
5x^2 + 5xy - x - y
=5x.(x+y)-(x+y)
=(x+y)(5x-1)
7x - 6x^2 - 2
=-6x2+3x+4x-2
=-3x.(2x-1)+2.(2x-1)
=(2x-1)(2-3x)
5x + \(7\sqrt{xy}-6y+\sqrt{x}+2\sqrt{y}
phan tich thanh nhan tu
(x^2+x)^2+4x^2+4x-12 phan tich da thuc thanh nhan tu
6x2+xy-7x-2y2+7y-5 Phan tich da thuc thanh nhan tu
phan tich da thuc thanh nhan tu a, (3x+1)^2-(x+1)^2
b, 6x-6y-x^2+xy
\(a,\left(3x+1\right)^2-\left(x+1\right)^2\)
\(=\left(3x+1-x-1\right)\left(3x+1+x+1\right)\)
\(=2x\left(4x+2\right)\)
\(=4x\left(2x+1\right)\)
\(b,6x-6y-x^2+xy\)
\(=\left(6x-6y\right)-\left(x^2-xy\right)\)
\(=6\left(x-y\right)-x\left(x-y\right)\)
\(=\left(x-y\right)\left(6-x\right)\)
Phan tich da thuc thanh nhan tu
x(x-2)-4
7x2+500xy+7y2
câu đầu tiên bạn tách \(x\left(x-2\right)-4\)
bạn tách ra để có thừa số chung tìm UCLN rồi tính nhé
câu b mình chịu
phan tich da thuc thanh nhan tu
A=x^6-2x^5-4x^4+6x^3+4x^2-2x-1