a) Theo ĐL BTKL ta có:

\(m_{KOH}+m_{FeCl_3}=m_{Fe\left(OH\right)_3}+m_{KCl}\)

b) Theo a) ta có:

\(m_{Fe\left(OH\right)_3}=m_{KOH}+m_{FeCl_3}-m_{KCl}\)

\(\Leftrightarrow m_{Fe\left(OH\right)_3}=16,8+16,25-27,45=5,6\left(g\right)\)

1. 2Al + 3O₂ \(\rightarrow\) 2AlCl₃

tỉ lệ 2:3:2

2. 2Fe + 3Cl₂ \(\rightarrow\) 2FeCl₃

tỉ lệ 2:3:2

3. 2Na + 2H₂O \(\rightarrow\) 2NaOH + H₂

tỉ lệ 2:2:2

4. Zn + 2HCl \(\rightarrow\) ZnCl₂ + H₂

tỉ lệ 1:2:1:1

5. 2C_xH_y + (2x+y/2)O₂ \(\rightarrow\) 2xCO₂ + yH₂O

tỉ lệ 2:(2x+y/2):2x:y

6.P₂O₅ + 3H₂O \(\rightarrow\) 2H₃PO₄

tỉ lệ 1:3:2

7. Fe₂(SO₄)₃ + 6KOH \(\rightarrow\) 2Fe(OH)₃ + 3K₂SO₄

tỉ lệ 1:6:2:3

8. 2Fe + 3Cl₂ \(\rightarrow\) 2FeCl₃

tỉ lệ 2:3:2

9. 2C_nH_2n-2 + (n-1)O₂ \(\rightarrow\) 2nCO₂ + 2(n-1)H₂O

tỉ lệ 2:(n-1):2n:2(n-1)

10. N₂O₅ + H₂O \(\rightarrow\) 2HNO₃

tỉ lệ 1:1:2

11. FeCl₃ + 3NaOH \(\rightarrow\) Fe(OH)₃ + NaCl

tỉ lệ 1:3:1:1

12. 2Al + 3Cl₂ \(\rightarrow\) 2AlCl₃

tỉ lệ 2:3:2

\(a,\\ \left(1\right)Fe+Cu\left(NO_3\right)_2\rightarrow Fe\left(NO_3\right)_2+Cu\\ \left(2\right)Fe\left(NO_3\right)_2+2KOH\rightarrow Fe\left(OH\right)_2\downarrow+2KNO_3\\ \left(3\right)Fe\left(OH\right)_2+2HCl\rightarrow FeCl_2+2H_2O\)

\(\left(4\right)FeCl_2\) \(\rightarrow\left(đpdd\right)\)  \(Fe+Cl_2\)

\(b,\\ \left(1\right)2Fe+3Cl_2\rightarrow\left(t^o\right)2FeCl_3\\ \left(2\right)FeCl_3+3AgNO_3\rightarrow Fe\left(NO_3\right)_3+3AgCl\downarrow\\ \left(3\right)Fe\left(NO_3\right)_3+3KOH\rightarrow Fe\left(OH\right)_3+3KNO_3\\ \left(4\right)2Fe\left(OH\right)_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+6H_2O\)

2KClO3 ---> 2KCl +3O2

4P + 5O2,---> 2P2O5

P2O5 + 3H2O ---> 2H3PO4

2Fe(OH)3 ---> nhiệt độ Fe2O3 +3H2O

FeCl3 +2NaOH ---> Fe(OH)2 +2NaCl

CẦN GẤP !

hệ số:

2:2:3

4:5:2

1:3:2

2:1:3

1:3:1:3

\(2Fe+3Cl_2\xrightarrow[]{t^0}2FeCl_3\\ FeCl_3+3AgNO_3\rightarrow Fe\left(NO_3\right)_3+3AgCl\\ Fe\left(NO_3\right)_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaNO_3\\ 2Fe\left(OH\right)_3\xrightarrow[]{t^0}Fe_2O_3+3H_2O\)

a) SO₂ + Na₂O -> Na₂SO₃

Na₂SO₃ + H₂SO₄ -> Na₂SO₄ + SO₂ + H₂O

Na₂SO₄ + Ba(OH)₂ -> BaSO₄ \(\downarrow\)+ 2NaOH

2NaOH + CO₂ -> Na₂CO₃ + H₂O

b) CaO + CO₂ -> CaCO₃

CaCO₃ \(\rightarrow^{t^o}\) CaO + CO₂

CaO + H₂O -> Ca ( OH)₂

Ca ( OH)₂ + CO₂ -> CaCO₃ + H₂O

CaCO₃ + H₂SO₄ -> CaSO₄ + CO₂ + H₂O

c) 2Fe + 3Cl₂ \(\rightarrow^{t^o}\) 2FeCl₃

FeCl₃ + 3NaOH -> Fe(OH)₃ \(\downarrow\) + 3NaCl

2Fe(OH)₃ \(\rightarrow^{t^o}\) Fe₂O₃ + 3H₂O

Fe₂O₃ + 3H₂SO₄ -> Fe₂(SO₄)₃ + 3H₂O

Fe₂(SO₄)₃ + 3BaCl₂ -> 2FeCl₃ + 3BaSO₄\(\downarrow\)

d) Fe + 2HCl -> FeCl₂ + H₂

FeCl₂ + 2AgNO₃ -> 2AgCl\(\downarrow\) + Fe(NO₃)₂

Fe(NO₃)₂ + 2NaOH -> Fe(OH)₂\(\downarrow\) + 2NaNO₃

Fe(OH)₂ + H₂SO₄ -> FeSO₄ + 2H₂O

a, SO₂ + 2NaOH \(\rightarrow\)Na₂SO₃ + H₂O

Na₂SO₃ + H₂SO₄ \(\rightarrow\)Na₂SO₄ + H₂O + SO₂

Na₂SO₄ + Ba(OH)₂\(\rightarrow\) BaSO₄+ 2 NaOH

CO₂ + 2 NaOH \(\rightarrow\)Na₂CO₃ + H₂O

b, CaO + CO₂\(\rightarrow\) CaCO₃

CaCO₃ -t⁰-> CaO + CO₂

CaO + H₂O \(\rightarrow\)Ca(OH)₂

Ca(OH)₂ + CO₂ \(\rightarrow\)CaCO₃ + H₂O

CaCO₃ + H₂SO₄ \(\rightarrow\)CaSO₄ + H₂O + CO₂

c, 2Fe + 3Cl₂ -t⁰-> 2FeCl₃

FeCl₃ + 3NaOH \(\rightarrow\)Fe(OH)₃ + 3NaCl

2Fe(OH)₃ -t⁰-> Fe₂O₃ + 3H₂O

Fe₂O₃ + 3H₂SO₄ \(\rightarrow\)Fe₂(SO4)₃ + 3H₂O

Fe₂(SO4)₃ + 3BaCl₂ \(\rightarrow\)2FeCl₃ + 3BaSO₄

d, Fe + 2HCl \(\rightarrow\)FeCl₂ + H₂

FeCl_{2 +} 2AgNO₃ \(\rightarrow\)Fe(NO₃)₂ + 2AgCl

Fe(NO₃)₂ + 2NaOH \(\rightarrow\)Fe(OH)₂ + 2NaNO₃

Fe(OH)₂ + H₂SO₄\(\rightarrow\) FeSO₄ + 2H₂O

e, 2Cu + O₂ -t⁰-> 2CuO

CuO + 2HCl \(\rightarrow\)CuCl₂ + H₂O

CuCl₂ + 2NaOH\(\rightarrow\) Cu(OH)₂ + 2NaCl

Cu(OH)₂ -t⁰-> CuO + H₂O

CuO + H₂ -t⁰-> Cu + H₂O

Cu + 2H₂SO_4đặc \(\rightarrow\)CuSO₄ + SO₂ + 2H₂O

f, 2Al₂O₃ -đpnc/ criolit-> 4Al + 3O₂

2Al + 3Cl₂ -t⁰-> 2AlCl₃

AlCl₃ + 3NaOH \(\rightarrow\)Al(OH)₃ + 3NaCl

2NaCl + 2H₂O -đpmn-> 2NaOH + Cl₂ + H₂

2NaOH + CuCl₂ \(\rightarrow\)Cu(OH)₂ + 2NaCl

FeCl₃+3NaOH→Fe(OH)₃+3NaCl

2Fe(OH)₃→Fe₂O₃+3H₂O

Fe₂0₃+3CO→2Fe+3CO₂

Fe+H₂SO₄→FeSO₄+H₂

FeCl₃ + 3NaOH ➜ Fe(OH)₃ + 3NaCl

2Fe(OH)₃ ➜ Fe₂O₃ + 3H₂O

Fe₂O₃ + 3CO ➜ 2Fe + 3CO₂

Fe + CuSO₄ ➜ FeSO₄ + Cu

1

1)4

2

3

5

Câu 1 :

( 1 ) 4Al + 3O2 → 2Al2O3 ( Nhiệt độ )

( 2 ) Al2O3 + 6HCl → 2AlCl3 + 3H2O

( 3 ) AlCl3 + 3NaOH → Al(OH)3 + 3NaCl

Câu 2 :

( 1 ) 2Al + 6HCl → 2AlCl3 + 3H2

( 2 ) AlCl3 + 3NaOH → Al(OH)3 + 3NaCl

( 3 ) 2Al(OH)3 → Al2O3 + 3H2O ( Nhiệt độ )

Câu 3 :

( 1 ) Fe + H2SO4 → H2 + FeSO4

( 2 ) BaCl2 + FeSO4 → FeCl2 + BaSO4

( 3 ) FeCl2 + 2NaOH → NaCl + Fe(OH)2

( 4 ) Fe(OH)2 → FeO + H2O ( Nhiệt độ )

Câu 4 :

( 1 ) Fe(OH)2 → FeO + H2O ( Nhiệt độ )

( 2 ) FeO + H2SO4 → H2O + FeSO4

( 3 ) BaCl2 + FeSO4 → FeCl2 + BaSO4

( 4 ) FeCl2 + 2NaOH → NaCl + Fe(OH)2

Câu 5 :

( 1 ) Fe + 2HCl → FeCl2 + H2

( 2 ) 2AgNO3 + FeCl2 → 2AgCl + Fe(NO3)2

( 3 ) Fe(NO3)2 + NaOH → NaNO3 + Fe(OH)2

( 4 ) H2SO4 + Fe(OH)2 → 2H2O + FeSO4

Câu 6 :

( 1 ) 3Cl2 + 2Fe → 2FeCl3 ( Nhiệt độ )

( 2 ) 3NaOH + FeCl3 → 3NaCl + Fe(OH)3

( 3 ) 3H2SO4 + 2Fe(OH)3 → Fe2(SO4)3 + 6H2O

( 4 ) 3BaCl2 + Fe2(SO4)3 → 2FeCl3 + 3BaSO4

Câu 7 :

( 1 ) 3NaOH + Fe(NO3)3 → 3NaNO3 + Fe(OH)3

( 2 ) 2Fe(OH)3 → Fe2O3 + 3H2O ( Nhiệt độ )

( 3 ) 2Al + Fe2O3 → Al2O3 + 2Fe

( 4 ) 3Cl2 + 2Fe → 2FeCl3 ( Nhiệt độ )

Câu 8 :

( 1 ) Fe2(SO4)3 + 6NaOH → 3Na2SO4 + 2Fe(OH)3

( 2 ) 2Fe(OH)3 → Fe2O3 + 3H2O ( Nhiệt độ )

( 3 ) Fe2O3 + 3H2SO4 → Fe2(SO4)3 + 3H2O

( 4 ) 3BaCl2 + Fe2(SO4)3 → 2FeCl3 + 3BaSO4

(1) 2Fe + 3Cl2 -^t0-> 2FeCl3

(2) FeCl3 + 3NaOH - > Fe(OH)3 + 3NaCl

(3) 2Fe(OH)3 -^t0-> Fe2O3 + 3H2O

(4) Fe2O3 + 3H2SO4(l) - > Fe2(SO4)3 + 3H2O

(5) Fe2(SO4)3 + 3BaCl2 - > 2FeCl3 + 3BaSO4

1. 2Fe + 3Cl2 \(\rightarrow\)2 FeCl3

2. FeCl3 + 3NaOH \(\rightarrow\) Fe(OH)3 + 3NaCl

3. 2Fe(OH)3 \(\rightarrow\) Fe2O3 + 3H2O

4. Fe2O3 + 3H2SO4 \(\rightarrow\) Fe2(SO4)3 + 3H2O

5. Fe2(SO4)3 + 3BaCl2 \(\rightarrow\) 2FeCl3 + 3BaSO4