Tìm x biết: x:[(1800 + 600) : 30]=560 : (315-35)
x;[{1800+600}:30]=560:{315-35}
tìm x
Ai nhanh tay tôi lì xì cho :
Tìm x biết : x : [ ( 1800 + 600 ) : 30 ] = 560 : ( 315 - 35 )
x : [ ( 1800 + 600 ) : 30 ] = 560 : ( 315 - 35 )
x : [ ( 1800 + 600 ) : 30 ] = 560 : 280
x : [ ( 1800 + 600 ) : 30 ] = 2
x*2 = ( 1800 + 600 ) : 30
x*2 = 2400 : 30
x*2 = 80
x = 80:2
x = 40
Tìm x: x:[(1800+600):30]=560:(315-35)
\(x:\left[\left(1800+600\right):30\right]=560:\left(315-35\right)\)
\(\Rightarrow x:\left(2400:30\right)=560:280\)
\(\Rightarrow x:80=2\)
\(\Rightarrow x=2.80\)
Vậy x=160.
Tìm x,biết:
a)x:[(1800+600):30]=560:(315-35)
b)[(250-25):15)]:x=(450-60):130
a) Không viết lại đề
x : [2400 : 30] = 560 : 280
x : 80 = 2
x = 2.80
x = 160
Vậy x = 160
b) Không viết lại đề
[225 : 15] : x = 390 : 130
15 : x = 3
x = 15 : 3
x = 3
Vậy x = 3
a. x:[(1800+600):30]=560:(315-35)
x:[2400:30] =560:280
x:80 =2
x =2*80
x =160
b.[(250-25):15] :x =(450-60):130
[225:15]:x =390:130
15:x =3
x =3*15
x =45
Học tốt!!!
\(a,x\div\left[\left(1800+600\right)\div30\right]=560\div\left(315-35\right)\)
\(\Rightarrow x\div\left[2400\div30\right]=560\div280\)
\(\Rightarrow x\div80=2\)
\(\Rightarrow x=160\)
x:[(1800-600):30]=560:(315-35) tìm x
x : [ ( 1800 + 600 ) : 30] = 560 : ( 315 - 35 )
\(x:\left[\left(1800+600\right):30\right]=560:\left(315-35\right)\)
\(x:\left[2400:30\right]=560:280\)
\(x:80=2\)
\(x=2\times80\)
\(x=160\)
\(X:80=560:280\)
\(X:80=2\)
\(X=80.2=160\)
\(x:\left[\left(1800+600\right):30\right]=560:\left(315-35\right)\)
\(\Rightarrow x:\left[2400:30\right]=560:280\)
\(\Rightarrow x:80=2\)
\(\Rightarrow x=2\times80\)
\(\Rightarrow x=160\)
Vậy x = 160
_Chúc bạn học tốt_
x:[(1800+600):30]=560:(315-35)
x:[(1800+600):30]=560:(315-35)
x : (2400 : 30) = 560 : 280
x : 80 = 2
x= 160
x : [ ( 1800 + 600 ) : 30 ] = 560 : ( 315 - 35 )
x : ( 2400 : 30 ) = 560 : 280
x : 80 = 2
x = 2 x 80
x = 160
Vậy x = 160
x : [ ( 1800 + 600 ) : 30 ] = 560 : ( 315 - 35 )
x : ( 2400 : 30 ) = 560 : 280
x : 80 = 2
x = 2 x 80
x = 160
x:[(1800+600):30]=560:(315-35)
x=
Tìm x biết: x:[(1800+600):30]=560:(315-15)
x:[(1800+600):30]=560:(315-15)
=> x:[2400:30]=560:300
=> x: 80 = 560:300
=> x = (80 x 560): 300
=> x = 448/3 = 149,(3)