Dãy biến đổi nào sau đây có thể thực hiện trực tiếp?
A) Cu(OH)2 --> CuO --> Cu --> CuCl2
B) CuO --> Cu --> Cu(OH)2 --> CuCl2
C) CuO --> Cu(OH)2 --> CuCl2 --> Cu
D) Cu --> CuO --> Cu(OH)2 --> CuCl2.
3. viết PTHH thực hiện dãy biến hóa sau:
a. Cu-CuSO4-CuCl2-Cu(NO3)-Cu(OH)2-CuO-CuCl2-Cu-CuCl2-Cu(OH)2
b.Na-Na2O-NaOH-Na2CO3-Na2SO4-NaCl-NaOH-Na3PO4-NaOH
a)
(1) \(Cu+2H2SO4\left(đ\right)-^{t0}->CuSO4+SO2\uparrow+2H2O\)
\(\left(2\right)CuSO4+BaCl2->CuCl2+BaSO4\downarrow\)
(3) \(CuCl2+2AgNO3->Cu\left(NO3\right)2+2AgCl\downarrow\)
(4) \(Cu\left(NO3\right)2+2NaOH->Cu\left(OH\right)2\downarrow+2NaNO3\)
(5) \(Cu\left(OH\right)2-^{t0}->CuO+H2O\)
(6) \(CuO+2HCl->CuCl2+H2O\)
(7) \(CuCl2-^{t0}->Cu+Cl2\uparrow\)
(8) \(Cu+Cl2-^{t0}->CuCl2\)
(9) \(CuCl2+2NaOh->Cu\left(OH\right)2\downarrow+2NaCl\)
b)
\(4Na+O2-^{t0}->2Na2O\)
\(Na2O+H2O->2NaOH\)
\(2NaOH+CO2->Na2CO3+H2O\)
\(Na2CO3+H2SO4->Na2SO4+CO2\uparrow+H2O\)
\(Na2SO4+BaCl2->2NaCl+BaSO4\downarrow\)
\(2NaCl+2H2O-\xrightarrow[có-màng-ngăn]{đpdd}2NaOH+Cl2\uparrow+H2\uparrow\)
\(3NaOH+H3PO4->Na3PO4+3H2O\)
thực hiện dãy chuyển hoá sau
Cu-->CuO-->CuCl2-->Cu(OH)-->CuO
(1) 2Cu + O2 ---to---> 2CuO
(2) CuO + 2HCl ---> CuCl2 + H2O
(3) CuCl2 + 2NaOH ---> Cu(OH)2 + 2NaCl
(4) \(Cu\left(OH\right)_2\overset{t^o}{--->}CuO+H_2O\)
Câu 1: Viết dãy chuyển hoá sau :Cu(OH)2 -------> CuO -------> CuCl2 -------> Cu(NO3)2 -------> Cu(OH)2 .
$Cu(OH)_2 \xrightarrow{t^o} CuO + H_2O$
$CuO + 2HCl \to CuCl_2 + H_2o$
$CuCl_2 + 2AgNO_3 \to Cu(NO_3)_2 + 2AgCl$
$Cu(NO_3)_2 + 2KOH \to Cu(OH)_2 + 2KNO_3$
Câu 1: Viết dãy chuyển hoá sau :Cu(OH)2 =>CuO=>CuCl2=>Cu(NO3)2=>Cu(OH)2 .
Viết phương trình thực hiện dãy chuyển hóa sau
CuO --> CuSO4 --> Cu(NO3)2 --> Cu(OH)2 --> CuO --> CuCl2 --> Cu
Câu 4: Viết PTHH thực hiện chuỗi biến hóa sau:
Cu(OH)2 ->CuO -> CuSO4 ->CuCl2 ->Cu(NO3)2 -> Cu -> CuO.
$Cu(OH)_2 \xrightarrow{t^o} CuO + H_2O$
$CuO + H_2SO_4 \to CuSO_4 + H_2O$
$CuSO_4 + BaCl_2 \to BaSO_4 + CuCl_2$
$CuCl_2 + 2AgNO_3 \to 2AgCl + Cu(NO_3)_2$
$Cu(NO_3)_2 + Fe \to Cu + Fe(NO_3)_2$
$2Cu + O_2 \xrightarrow{t^o} 2CuO$
Cu -> CuO -> CuSO4 -> CuCl2 -> Cu(NO3)2 -> Cu(OH)2 -> CuO -> Cu
\(Cu\overset{\left(1\right)}{-->}CuO\overset{\left(2\right)}{-->}CuSO_4\overset{\left(3\right)}{-->}CuCl_2\overset{\left(4\right)}{-->}Cu\left(NO_3\right)_2\overset{\left(5\right)}{-->}Cu\left(OH\right)_2\overset{\left(6\right)}{-->}CuO\overset{\left(7\right)}{-->}Cu\)
\(\left(1\right)2Cu+O_2\overset{t^o}{--->}2CuO\)
\(\left(2\right)CuO+H_2SO_4--->CuSO_4+H_2O\)
\(\left(3\right)CuSO_4+BaCl_2--->BaSO_4\downarrow+CuCl_2\)
\(\left(4\right)CuCl_2+2AgNO_3--->2AgCl\downarrow+Cu\left(NO_3\right)_2\)
\(\left(5\right)Cu\left(NO_3\right)_2+2NaOH--->Cu\left(OH\right)_2\downarrow+2NaNO_3\)
\(\left(6\right)Cu\left(OH\right)_2\overset{t^o}{--->}CuO+H_2O\)
\(\left(7\right)CuO+H_2\overset{t^o}{--->}Cu+H_2O\)
\(2Cu+O_2\underrightarrow{t^o}2Cuo\)
\(CuO+H_2SO_4->CuSO_4+H_2O\)
\(CuSO_4+BaCl_2->BaSO_4\downarrow+CuCl_2\)
\(CuCl_2+2AgNO_3->Cu\left(NO_3\right)_2+2AgCl\downarrow\)
\(Cu\left(NO_3\right)_2+2NaOH->Cu\left(OH\right)_2\downarrow+2NaNO_3\)
\(Cu\left(OH\right)_2\underrightarrow{t^o}CuO+H_2O\)
\(CuO+H_2\underrightarrow{t^o}Cu+H_2O\)
Viết PTHH của dãy biến hoá sau đây a) Cu—->CuO——> CuCl2——> Cu(OH)2 ——> CuSO4 ——> CuCl2 b) Fe ——> Fe2O3 ——-> FeCl3 ——> Fe(OH)3 ——> Fe2(SO4)3 ——> Fe(NO3)3 c) SO2 ——> SO3 ——> H2SO4 ——> Na2SO4 ——> NaCl ——> NaOH
Viết các PTHH hoàn thành sơ đồ biến đổi sau : Cu-->CuSO4-->CuCl2-->Cu(OH)2-->CuO-->Cu
\((1)Cu+2H_2SO_{4(\text{đ})}\xrightarrow{t^o} CuSO_4+2H_2O+SO_2\uparrow\\ (2)CuSO_4+BaCl_2\to CuCl_2+BaSO_4\downarrow\\ (3)CuCl_2+2NaOH\to Cu(OH)_2\downarrow +2NaCl\\ (4)Cu(OH)_2\xrightarrow{t^o}CuO+H_2O\\ (5)CuO+H_2\xrightarrow{t^o}Cu+H_2O\)