x+2=-5

x =-7

x²+2x-3=0

(=) x²-x+3x-3=0

(=) x(x-1)+3(x-1)=0

(=) (x-1)(x+3)=0

=> x-1 = 0 hoặc x+3 = 0

x = 1 x =-3

x+4 = 10

x = 6

-3x + 2 =-7

(=) -3x =-9

(=) x = 3

0.5x + 4 = -1

(=) 0.5x =-5

(=) x =-10

Chúc bạn học tốt ^^

a)x+2=-5

\(\Leftrightarrow\)x =-7

b)x²+2x-3=0

\(\Leftrightarrow\)x²-x+3x-3=0

\(\Leftrightarrow\)x(x-1)+3(x-1)=0

\(\Leftrightarrow\)(x+3)(x-1)=0

\(\Rightarrow\)x+3=0 hoặc x-1=0

\(\Rightarrow\)x=-3 hoặc x=1

c)x+4=10

\(\Leftrightarrow\)x=6

d)-3x+2=-7

\(\Leftrightarrow\)-3x =-7-2

\(\Leftrightarrow\)3x =-9

\(\Leftrightarrow\)x =-3

e)0,5x+4=-1

\(\Leftrightarrow\)0,5x =-1-4

\(\Leftrightarrow\)0,5x = -5

\(\Leftrightarrow\)x =-5:0,5

\(\Leftrightarrow\)x =-10

Tham khảo :

   ảnh lazi

  Ps: nhớ k 

                                                                                                                                                      # Aeri # 

\(a,\frac{-2}{3}x=8\)<=> \(x=-12\)

\(b,\frac{1}{4}:x=-3+\frac{3}{4}\)<=>\(\frac{1}{4}:x=\frac{-9}{4}\)<=>\(x=-9\)

\(c,\orbr{\begin{cases}2x-\frac{1}{3}=0\\0.5x+0.25=0\end{cases}}\)<=>\(\orbr{\begin{cases}x=\frac{1}{6}\\x=\frac{-3}{4}\end{cases}}\)

a) \(\frac{-2}{3}x+4=12\)

\(\Rightarrow\frac{-2}{3}x=12-4\)

\(\Rightarrow\frac{-2}{3}x=8\)

\(\Rightarrow x=8:\frac{-2}{3}\)

\(\Rightarrow x=-12\)

Vậy x = -12

b) \(\frac{-3}{4}+\frac{1}{4}:x=-3\)

\(\Rightarrow\frac{1}{4}:x=-3-\left(\frac{3}{4}\right)\)

\(\Rightarrow\frac{1}{4}:x=\frac{-9}{4}\)

\(\Rightarrow x=\frac{1}{4}:\frac{-9}{4}\)

\(\Rightarrow x=\frac{-1}{9}\)

Vậy  \(x=\frac{-1}{9}\)

c) \(\left(2x-\frac{1}{3}\right)\left(0,5x+0,25\right)=0\)

\(\Rightarrow\orbr{\begin{cases}2x-\frac{1}{3}=0\\0,5x+0,25=0\end{cases}}\Rightarrow\orbr{\begin{cases}2x=\frac{1}{3}\\0,5x=-0,25\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{6}\\x=-0,5\end{cases}}\)

Vậy  \(x=\frac{1}{6}\)hoặc \(x=-0,5\)

_Chúc bạn học tốt_

Bạn ghi lại đề đi bạn

theo đề ta có 

(3x+2)(x+3) = (0,5x+2)(5x+7) 

=> 3x^2 + 11x + 6 = 2,5x+13,5x+14 

..................

từ đây bn tự giải tìm x

bạn làm kiểu này :

0.5x-\(\dfrac{2}{3}\)x=\(\dfrac{7}{6}\)

0-\(\dfrac{2}{3}\)x=\(\dfrac{7}{6}\)

\(\dfrac{2}{3}\)x=0-\(\dfrac{7}{6}\)

0.5x-\(\dfrac{2}{3}\)x=\(\dfrac{7}{6}\)

\(\left(\dfrac{1}{2}-\dfrac{2}{3}\right)\). x=\(\dfrac{7}{6}\)

\(\left(\dfrac{3}{6}-\dfrac{4}{6}\right)\). x=\(\dfrac{7}{6}\)

\(\dfrac{-1}{6}\). x=\(\dfrac{7}{6}\)

x=\(\dfrac{7}{6}\):\(\dfrac{-1}{6}\)

x=\(\dfrac{7}{6}\) . \(\dfrac{6}{-1}\)

x=\(\dfrac{42}{-6}\)

x=\(\dfrac{7}{-1}\)

lại bí rùi

\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\Rightarrow\left(x+1\right)\left(x+3\right)=\left(0,5x+2\right)\left(2x+1\right)\)

\(\Rightarrow x^2+3x+x+3=x^2+0,5x+4x+2\)

\(\Rightarrow x^2+3x+x-x^2-0,5x-4x=2-3\)

\(\Rightarrow-\frac{1}{2}x=-1\)

\(\Rightarrow x=2\)

\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)

\(\Rightarrow\left(x+1\right)\left(x+3\right)=\left(2x+1\right)\left(0,5x+2\right)\)

\(\Rightarrow x^2+3x+x+3=x^2+4x+0,5x+2\)

\(\Rightarrow x^2+3x+x+3-x^2-4x-0,5x-2=0\)

\(\Rightarrow1-0,5x=0\)

\(\Rightarrow\frac{1}{2}x=1\Leftrightarrow x=2\)