( 1 - \(\frac{1}{1+2}\)) . ( 1 - \(\frac{1}{1+2+3}\)) ... ( 1 - \(\frac{1}{1+2+3+...+2018}\) )
Thực hiện phép tính trên
Thực hiện phép tính:\(\left(1-\frac{1}{2018}\right).\left(1-\frac{2}{2018}\right).\left(1-\frac{3}{2018}\right)...\left(1-\frac{2020}{2018}\right)\)
Thực hiện phép tính : \(\left(1\frac{1}{1+2}\right).\left(1\frac{1}{1+2+3}\right)...\left(1\frac{1}{1+2+3+...+2018}\right)\)
Thực hiện phép tính
\(\left(1-\frac{1}{1+2}\right).\left(1-\frac{1}{1+2+3}\right)...\left(1-\frac{1}{1+2+3+...+2018}\right)\)
thực hiện phép tính:
\(\left(1\frac{1}{1+2}\right).\left(1\frac{1}{1+2+3}\right).....\left(1\frac{1}{1+2+3+...+2018}\right)\)
Thực hiện phép tính:
\(\left(1-\frac{1}{1+2}\right).\left(1-\frac{1}{1+2+3}\right).....\left(1-\frac{1}{1+...+2018}\right)\)
Thực hiện phép tính
( 1 - \(\frac{1}{1+2}\)) . ( 1 - \(\frac{1}{1+2+3}\)) ... ( 1 - \(\frac{1}{1+2+3+...+2018}\))
\(\left(1-\frac{1}{1+2}\right).\left(1-\frac{1}{1+2+3}\right).....\left(1-\frac{1}{1+2+3+.....+2018}\right)\)
\(=\left(1-\frac{1}{\frac{2.3}{2}}\right).\left(1-\frac{1}{\frac{3.4}{2}}\right).......\left(1-\frac{1}{\frac{2018.2019}{2}}\right)\)
\(=\left(1-\frac{2}{2.3}\right).\left(1-\frac{2}{3.4}\right).......\left(1-\frac{2}{2018.2019}\right)\)
\(=\left(1-\frac{1}{3}\right).\left(1-\frac{5}{6}\right).......\left(1-\frac{1}{2037171}\right)\)
\(=\frac{2}{3}.\frac{5}{6}......\frac{2037170}{2037171}\)
\(=\frac{4}{6}.\frac{10}{12}.......\frac{4074340}{4074342}\)
\(=\frac{1.4}{2.3}.\frac{2.5}{3.4}......\frac{2017.2020}{2018.2019}\)
\(=\frac{1.2......2017}{2.3.....2018}.\frac{4.5......2020}{3.4......2019}=\frac{1}{2018}.\frac{2020}{3}=\frac{1010}{3027}\)
thực hiện phép tính
\(\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+50}\)
Thực hiện phép tính:
a, A= \(\frac{1}{6}.\left(-2\frac{3}{5}\right)+1\frac{2}{3}.\left(\frac{-13}{5}\right)\)
b, B=\(\frac{5}{7}:\left(\frac{1}{2}-\frac{1}{3}\right)+\frac{5}{7}:\left(\frac{1}{5}-\frac{1}{6}\right)\)
c, C= \(2^3+3.\left(\frac{2017}{2018}\right)^0.\left(\frac{1}{2}\right)^{-2}:4+[\left(-2\right)^2:\frac{1}{2}].\left(\frac{-1}{2}\right)^3\)
giúp vs, mik cần gấp
A= E387E4837
B = 883433
C = UỲUWFHQWURY48E3947
\(\left|\frac{-3}{2}+1,2\right|+1\frac{2}{3}:6-2018^0\)
Thực hiện phép tính