a) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(\Leftrightarrow\frac{x-23}{24}+\frac{x-23}{25}-\frac{x-23}{26}-\frac{x-23}{27}=0\)
\(\Leftrightarrow\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\)
\(\Leftrightarrow x-23=0\)( vì \(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\ne0\))
\(\Leftrightarrow x=23\)
Vậy nghiệm của pt x=23
Tìm x€ Z:(1/24*25+1/25*26+...+1/29*30)*120+x:1/3=-5
( 1/24 x 25 + 1/25 x 26 + ... + 1/29 x 30 ) x 150 + 103/100 [ 103/100 x ( X - 1 ) ] = 22
giải phương trình sau:
\(x = {x-25 \over 25} + {x-26 \over 24} + {x-27 \over 23} + {x-26 \over 22} +{x-17 \over 30}\)
24 x 25 x 26 = ?
\(24\cdot25\cdot26\)
\(=6\cdot4\cdot25\cdot26\)
\(=6\cdot100\cdot26\)
\(=176\cdot100\)
\(=17600\)
24 x 25 x 26
= 6 x 4 x 25 x 6
= 100 x 6 x 26
= 100 x 156
= 15600
24 x 25 x 26
= ( 24 x 25 ) x 26
= 600 x 26
= 15.600
Hoặc
24 x 25 x 26
= 24 x ( 25 x 26 )
= 24 x 650
= 15.600
Học Tốt !
( 26 - 25 + 3 ) x ( 48 -24 x 2 )
( 26 - 25 + 3 ) . ( 48 - 24 . 2 )
= ( 1 + 3 ) . ( 48 - 48 )
= 4 . 0
= 0
(26-25+3)x(48-24*2)
=(1+3)x(48-48)
=4x0
=0
Chúc bạn học giỏi
24 x (x -25 ) + 26 có giá trị nhỏ nhất
x-3/24+x-3/25+x-3/26+x-3/27
(X-19)/24+(X-19)/25=(X-19)/26+(X-19)/27
\(\frac{x-19}{24}\)+ \(\frac{x-19}{25}\)= \(\frac{x-19}{26}\)+ \(\frac{x-19}{27}\)
<=> \(\frac{x-19}{24}\)+ \(\frac{x-19}{25}\)- \(\frac{x-19}{26}\)- \(\frac{x-19}{27}\)= 0
<=> \(\frac{x}{24}\)- \(\frac{19}{24}\)+ \(\frac{x}{25}\)- \(\frac{19}{25}\)- \(\frac{x}{26}\)+\(\frac{19}{26}\)- \(\frac{x}{27}\)+\(\frac{19}{27}\)= 0
<=> \(\left(\frac{x}{24}+\frac{x}{25}-\frac{x}{26}-\frac{x}{27}\right)+\left(-\frac{19}{24}-\frac{19}{25}+\frac{19}{26}-\frac{19}{27}\right)=0\)
<=> \(x\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)-19\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\)
<=> \(x\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)\)= \(19\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)\)
<=> x = 19
x-23/24 + x-23/25=x-23/26 + x-23/27