Tìm x biết
A/3x^2-3x(x-2)=36
B/(3x^2-x+1)(x-1)+x^2(4-3x)=5/2
Giải giúp với
7.38. Tìm giá trị của x, biết rằng:
a) 3x\(^2\) - 3x(x - 2) = 36
b) 5x(4x\(^2\) - 2x +1) - 2x(10x\(^2\) - 5x +2) = -36
\(a,3x^2-3x\left(x-2\right)=36\\ \Leftrightarrow3x^2-3x^2+6x=36\\ \Leftrightarrow6x=36\\ \Leftrightarrow x=6\\ b,5x\left(4x^2-2x+1\right)-2x\left(10x^2-5x+2\right)=-36\\ \Leftrightarrow20x^3-10x^2+5x-20x^3+10x^2-4x+36=0\\ \Leftrightarrow\left(20x^3-20x^3\right)+\left(-10x^2+10x^2\right)+\left(5x-4x\right)=-36\\ \Leftrightarrow x=-36\)
Bài 2 Tìm x biết 1, (2x-2).(3x+1)-(3x-2).(2x-3)=5 2,(1-3x).(3x-5)-(2x-4)(2-3x)=x-6 3,(2x-1).(4x^2+2x+1)-(2x+1)(4x^2-2x+1)=5x+6 Giúp tớ với
Bài 5.Tìm x N, sao cho:
a)3636 : (12x –91) = 36
b)(x : 23 + 45) . 67 = 8911
c)[(6x –39) : 7]. 4 = 12
d)(3x –24). 73= 2. 74
e)x(x –10) = 0
f)(x+ 1). (x –2) = 0
g)(9 –x)3= 64
h)3x= 81
i)2 . 3x= 10 . 312+ 8 . 312
j)(19x + 2.52) : 14 = (13 -8)2-42
\(a,\Rightarrow12x-91=101\\ \Rightarrow12x=192\\ \Rightarrow x=16\\ b,\Rightarrow x:23+45=133\\ \Rightarrow x:23=88\\ \Rightarrow x=\dfrac{88}{23}\\ c,\Rightarrow\left(6x-39\right):7=3\\ \Rightarrow6x-39=21\\ \Rightarrow6x=60\\ \Rightarrow x=10\\ d,\Rightarrow3x-24=\dfrac{148}{73}\\ \Rightarrow3x=\dfrac{1900}{73}\\ \Rightarrow x=\dfrac{1900}{219}\\ e,\Rightarrow\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\\ f,\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\\ d,\left(9-x\right)^3=64=4^3\\ \Rightarrow9-x=4\\ \Rightarrow x=5\\ h,\Rightarrow x=27\\ i,\Rightarrow6x=312\cdot12=624\cdot6\\ \Rightarrow x=624\\ j,\Rightarrow\left(19x+104\right):14=25-42=-17\\ \Rightarrow19x+104=-238\\ \Rightarrow19x=-342\\ \Rightarrow x=-18\)
Bài 2 Tìm x 1,. ( x+1 ) (x+ 3 ) - x ( x+ 2 ) =7 2,. 2x ( 3x + 5 ) - x ( 6x - 1 ) =33 3,. ( 3x^2 - x +1 ) ( x - 1) + x^2 ( 4 - 3x ) = 5/2 Giúp em với mn !
1: =>x^2+4x+3-x^2-2x=7
=>2x=4
hay x=2
a, thu gọn và chỉ ra bậc của đa thức A=( 9x^2yz).(-2xy^3 )
b, tìm đa thức m biết : 3x^2+3xy-x^3-M=3x^2+2xy-4y^2
giải giúp em với
a: \(A=-18x^3y^4z\)
Bậc là 8
b: \(M=3x^2+3xy-x^3-3x^2-2xy+4y^2=-x^3+xy+4y^2\)
B1. Tính giá trị: A=(x+2)^2 - (x-2)^2 với x=125
B2. Thu gọn:
a, 2x.(2x-1)^2 - 3x.(x+3).(x-3) - 4x.(x+1)^2
b. (3x+1)^2 - 2.(3x+1).(3x+5) + (3x+5)^2
B3: Tìm x biết (x+2)^2 - x^2 +4=0
b1
A=(125+2)2 - (125-2)2 = 1272 - 1232 = 1000
Tìm x:
a) x(2x - 1)(x + 5) - (2x^2 + 1)(x + 4,5) = 3,5
b) 3x^2 - 3x(x - 2) = 36
c) (3x^2 - x + 1)(x - 1) + x^2(4 - 3x) = 5/2
Giúp mình với (T^T),
Tìm x, biết :
a) (x-2)3 +6(x+1)2-x3+12=0
b) (x-5) (x+5) - (x+3)2+3(x-2)2=(x+1)2- (x+4)(x-4)+3x2
c) (2x+3)2 +(x-1)(x+1)=5(x+2)2-(x-5)(x+1)+(x+4)
d) (1-3x)2-(x-2)(9x+1)=(3x-4)(3x+4)-9(x+3)2
Giúp mk với ạ, mk cảm ơn !
a) (x-2)3+6(x+1)2-x3+12=0
\(\Rightarrow\)x3-6x2+12x-8+6(x2+2x+1)-x3+12=0
\(\Rightarrow\)x3-6x2+12x-8+6x2+12x+6-x3+12=0
\(\Rightarrow\)24x+10=0
\(\Rightarrow\)24x=-10
\(\Rightarrow\)x=\(\dfrac{-10}{24}=\dfrac{-5}{12}\)
b)(x-5)(x+5)-(x+3)2+3(x-2)2=(x+1)2-(x-4)(x+4)+3x2
\(\Rightarrow\)x2-25-(x2+6x+9)+3(x2-4x+4)=x2+2x+1-(x2-16)+3x2
\(\Rightarrow\)x2-25-x2-6x-9+3x2-12x+12=x2+2x+1-x2+16+3x2
\(\Rightarrow\)3x2-18x-22=3x2+2x+17
\(\Rightarrow\)3x2-18x-22-3x2-2x-17=0
\(\Rightarrow\)-20x-39=0
\(\Rightarrow\)-20x=39
\(\Rightarrow\)x=\(-\dfrac{39}{20}\)
c) (2x+3)2 +(x-1)(x+1)=5(x+2)2-(x-5)(x+1)+(x+4)
⇒4x2+12x+9+x2-1=5(x2+4x+4)-(x2+x-5x-5)+x+4
⇒5x2+12x+8=5x2+20x+20-x2-x+5x+5+x+4
⇒5x2+12x+8-5x2-20x-20+x2+x-5x-5-x-4=0
⇒x2-13x-21=0