b: \(\Leftrightarrow4x+13=5\)

hay x=-2

a) 2x(3x+1) – (2x+3)(3x-2) = 12

\(\Leftrightarrow6x^2+2x-\left(6x^2-4x+9x-6\right)=12\)

\(\Leftrightarrow6x^2+2x-6x^2+4x-9x+6=12\)

\(\Leftrightarrow-3x+6=12\) 

\(\Leftrightarrow-3x=6\)  

\(\Leftrightarrow x=-2\)  

vậy x = -2

 b)  (x+2)² – (x-3)(x+3) = 5

\(\Leftrightarrow\left(x+2\right)^2-\left(x^2-9\right)=5\)

\(\Leftrightarrow x^2+4x+4-x^2+9-5=0\)  

\(\Leftrightarrow4x+8=0\)

\(\Leftrightarrow4x=-8\) 

\(\Leftrightarrow x=-2\)

Vậy  x = -2

\(\Leftrightarrow3x^2+2x+x^2+2x+1-4x^2+25+12=0\\ \Leftrightarrow4x+38=0\\ \Leftrightarrow x=-\dfrac{19}{2}\)

\(\Leftrightarrow3x^2+2x+x^2+2x+1-4x^2+25=-12\\ \Leftrightarrow4x=-38\Leftrightarrow x=-\dfrac{19}{2}\)

\(\Rightarrow3x^2+2x+x^2+2x+1-4x^2+25=-12\)

\(\Rightarrow4x=-38\Rightarrow x=-\dfrac{19}{2}\)

\(\Leftrightarrow3x^2+2x+x^2+2x+1-4x^2+25+12=0\\ \Leftrightarrow4x+38=0\\ \Leftrightarrow x=-\dfrac{19}{2}\)

a)(x+2).(x+3)-(x-2).(x+5)=10

  ( x^2 +3x+2x+6)-(x^2 +5x-2x-10)=10

 x^2 +3x+2x+6-x^2 -5x+2x+10-10=0

 2x+6=0

2x=-6

x=-3

b: \(3x^2-2x-1=0\)

=>\(3x^2-3x+x-1=0\)

=>\(\left(x-1\right)\left(3x+1\right)=0\)

=>\(\left[{}\begin{matrix}x-1=0\\3x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{1}{3}\end{matrix}\right.\)

a: Bạn ghi lại đề đi bạn

a) 

<=> 3x - 3 + x - 2 = 2x - 2 - x + 1

<=> 3x + x - 2x + x = -2 + 1 + 3 + 2

<=>    3x               = 4

<=>   x                  = 4/3

Các câu sau làm tương tự

\(\left(3x-3\right)+\left(x-2\right)=\left(2x-2\right)-\left(x-1\right)\)

<=>   \(3x-3+x-2=2x-2-x+1\)

<=>  \(4x-5=x-1\)

<=> \(3x=4\)

<=>  \(x=\frac{4}{3}\)

Vậy....

Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu

a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14) 

=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84

=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84) 

=> 156 -  56x = 24x - 324 

=>  24x + 56x = 324 + 156 

=> 80x = 480 

=> x = 480 : 80 =  6 

Vậy x = 6 

b, 5(3x + 5) - 4(2x - 3) = 5x + 3(2x + 12) + 1 

=> 15x + 25 - 8x + 12 = 5x + 6x + 36 + 1 

=> (15x - 8x) + (25 + 12) = 11x + 37 

=> 7x + 37 = 11x + 37 

=> 11x - 7x = 0 

=>  x = 0 

\(a,5\left(3x+5\right)-4\left(2x-3\right)=5x+8\left(2x+12\right)+1\)

\(\Rightarrow5\left(3x+5\right)-4\left(2x-3\right)-5x-8\left(2x+12\right)-1=0\)

\(\Rightarrow15x+25-8x+12-5x-16x-96-1=0\)

\(\Rightarrow-14x-60=0\)

\(\Rightarrow-14x=60\) \(\Rightarrow x=-\frac{60}{14}=\frac{-30}{7}\)

\(b,\left(2x+3\right)\left(x-4\right)-\left(3x-5\right)\left(x-4\right)=\left(5-x\right)\left(x-2\right)\)

\(\Rightarrow2x^2+3x-8x-12-3x^2+5x+12x-20=5x-x^2-10+2x\)

\(\Rightarrow-x^2+12x-32=7x-x^2-10\)

\(\Rightarrow-x^2+12x-32-7x+x^2+10=0\)

\(\Rightarrow5x-22=0\)

\(\Rightarrow5x=22\Rightarrow x=\frac{22}{5}\)

a) 5(3x+5)-4(2x-3) = 5x+8(2x+12)+1

15x + 25 - 8x + 12 = 5x + 16x + 96 + 1

15x - 8x - 5x - 16x = 96 + 1 - 25 - 12

-14x = 60

x = \(\frac{60}{-14}\)

x = \(-\frac{30}{7}\)

b) (2x+3)(x-4)-(3x-5)(x-4) = (5-x).(x-2)

(x - 4)(2x + 3 - 3x +5) = 5x - 10 - x² + 2x

(x - 4)[(2x - 3x) + (3 + 5)] = 5x - 10 - x² + 2x

(x - 4)(-x + 8) = 5x - 10 - x² + 2x

-x² + 8x + 4x - 32 = 5x - 10 - x² + 2x

(-x² + x²) + (8x + 4x - 5x - 2x) = -10 + 32

5x = 22

x = \(\frac{22}{5}\) 

a) 5(3x+5)-4(2x-3)=5x+8(2x+12)+1

<=> 15x+25-8x+12=5x+16x+96+1

<=>15x-8x-5x-16x=-25-12+96+1

<=> -14x       = 60

<=>  x= \(\frac{-60}{14}\)=\(\frac{-30}{7}\)

Vậy x= \(\frac{-30}{7}\)