\(C=\dfrac{2^6\cdot3^{10}}{3^9\cdot2^6}=3\\ D=\dfrac{3^{24}\cdot3^{10}}{3^{21}\cdot3^{11}}=\dfrac{3^{34}}{3^{32}}=3^2=9\\ F=\dfrac{2^{45}\cdot5^{14}}{5^{15}\cdot2^{47}}=\dfrac{1}{2^2\cdot5}=\dfrac{1}{20}\\ G=\dfrac{2^2\cdot5^2\cdot5^3}{2^3\cdot5^4}=\dfrac{1\cdot5}{2}=\dfrac{5}{2}\)

C=3

D=9

F=1/20

G=5/2

Em ko giải chi tiết vì nó lâu

Mong thông cảm!

C= \(\dfrac{8^2.9^5}{3^9.4^3}\)

   = \(\dfrac{\left(2^3\right)^2.\left(3^2\right)^5}{3^9.\left(2^2\right)^3}\)

   = \(\dfrac{2^6.3^{10}}{3^9.2^6}\)

   = \(\dfrac{3^1}{1}\)

   = \(\dfrac{3}{1}\)

\(\frac{9^3\cdot2^{10}\cdot27^5}{4^5\cdot81^6}=\frac{3^6\cdot2^{10}\cdot3^{15}}{2^{10}\cdot3^{24}}=\frac{1}{3^3}=\frac{1}{27}\)

\(\frac{27^4\cdot2^5-3^{11}\cdot4^3}{8^2\cdot9^6}=\frac{3^{12}\cdot2^5}{2^6\cdot3^{12}}-\frac{3^{11}\cdot2^6}{2^6\cdot3^{12}}=\frac{1}{2}-\frac{1}{3}=\frac{1}{6}\)

=))

a) \(\frac{9^3.2^{10}.27^5}{4^5.81^6}\)= \(\frac{\left(3^2\right)^3.2^{10}.\left(3^3\right)^5}{\left(2^2\right)^5.\left(3^4\right)^5}\)= \(\frac{3^{2.3}.2^{10}.3^{3.5}}{2^{2.5}.3^{4.5}}\)= \(\frac{3^6.2^{10}.3^{15}}{2^{10}.3^{20}}\)= \(\frac{3^{21}.2^{10}}{2^{10}.3^{20}}\)= \(\frac{3^{20}.2^{10}.3}{2^{10}.3^{20}}\)= \(3\)

\(a,\frac{9^3\cdot2^{10}\cdot27^5}{4^5\cdot81^6}\)

\(=\frac{\left[3^2\right]^3\cdot\left[2^2\right]^5\cdot\left[3^3\right]^5}{\left[2^2\right]^5\cdot\left[3^4\right]^6}\)

\(=\frac{3^6\cdot2^{10}\cdot3^{15}}{2^{10}\cdot3^{24}}=\frac{3^6\cdot3^{15}}{3^{24}}=\frac{3^{21}}{3^{24}}=3^{21-24}=3^{-3}=\frac{1}{27}\)

b, Như bạnThảo Nguyễn 緑

đk -3 =< x =< 10

\(\sqrt{x+3}-2+\sqrt{10-x}-3=x^2-7x+6\)

\(\Leftrightarrow\dfrac{x+3-4}{\sqrt{x+3}+2}+\dfrac{10-x-9}{\sqrt{10-x}+3}=\left(x-6\right)\left(x-1\right)\)

\(\Leftrightarrow\dfrac{x-1}{\sqrt{x+3}+2}+\dfrac{1-x}{\sqrt{10-x}+3}=\left(x-6\right)\left(x-1\right)\)

\(\Leftrightarrow\left(x-1\right)\left(\dfrac{1}{\sqrt{x+3}+2}-\dfrac{1}{\sqrt{10-x}+3}-x+6\ne0\right)=0\Leftrightarrow x=1\)(tm)

\(9^{2+2+1}=9^5\)

\(3^5.2^5=\left(3.3.3.3.3\right).\left(2.2.2.2.2\right)=\left(3.2\right).\left(3.2\right).\left(3.2\right).\left(3.2\right).\left(3.2\right)=6.6.6.6.6=6^5\)

Tích nha mik tích lại

thanks nhiều

a: =>14x+20+5=6x-9-9x

=>14x+25=-3x-9

=>17x=-34

=>x=-2

b: =>\(2x^2-30x+2x-30=2x^2+10x-10x-50\)

=>-28x-30=-50

=>-28x=-20

=>x=20/28=5/7

c: =>2x+x^3-x=x^3+1

=>x=1

d: =>x^3-3x^2+3x-1-x(x^2+2x+1)=10x-2x^2-11x-22

=>x^3-3x^2+3x-1-x^3-2x^2-x=-2x^2-x-22

=>-5x^2+2x-1+2x^2+x+22=0

=>-3x^2+3x+21=0

=>x^2-x-7=0

=>\(x=\dfrac{1\pm\sqrt{29}}{2}\)

b) x^10=1x

=> x=0 ; 1

c)(2x-15)^5=(2x-15)^3

=> (2x-15)^4 = (2x-15)^2

=> (2x-15)^2 =1

=> 2x-15=1

=> x=8