(7x-11)^3-10^2=10^2.9
tính A = \(\frac{72^3.54^2}{1084}\)
tính B = \(\frac{3^{10}.11+3^{10}.19}{9^2.9^3.5^2}\)
tính C = \(\frac{3737.43-4343.37}{2+4+6+.....+100}\)
Câu 1: Rút gọn các biểu thức sau:
C = \(\dfrac{8^2.9^5}{3^9.4^3}\)
D = \(\dfrac{81^6.9^5}{27^7.3^{11}}\)
F = \(\dfrac{8^{15}.25^7}{125^5.2^{47}}\)
G = \(\dfrac{10^2.5^3}{8.25^2}\)
\(C=\dfrac{2^6\cdot3^{10}}{3^9\cdot2^6}=3\\ D=\dfrac{3^{24}\cdot3^{10}}{3^{21}\cdot3^{11}}=\dfrac{3^{34}}{3^{32}}=3^2=9\\ F=\dfrac{2^{45}\cdot5^{14}}{5^{15}\cdot2^{47}}=\dfrac{1}{2^2\cdot5}=\dfrac{1}{20}\\ G=\dfrac{2^2\cdot5^2\cdot5^3}{2^3\cdot5^4}=\dfrac{1\cdot5}{2}=\dfrac{5}{2}\)
C=3
D=9
F=1/20
G=5/2
Em ko giải chi tiết vì nó lâu
Mong thông cảm!
C= \(\dfrac{8^2.9^5}{3^9.4^3}\)
= \(\dfrac{\left(2^3\right)^2.\left(3^2\right)^5}{3^9.\left(2^2\right)^3}\)
= \(\dfrac{2^6.3^{10}}{3^9.2^6}\)
= \(\dfrac{3^1}{1}\)
= \(\dfrac{3}{1}\)
\(\frac{9^3.2^{10}.27^5}{4^5.81^6}\)
\(\frac{27^4.2^5-3^{11}.4^3}{8^2.9^6}\)
\(\frac{9^3\cdot2^{10}\cdot27^5}{4^5\cdot81^6}=\frac{3^6\cdot2^{10}\cdot3^{15}}{2^{10}\cdot3^{24}}=\frac{1}{3^3}=\frac{1}{27}\)
\(\frac{27^4\cdot2^5-3^{11}\cdot4^3}{8^2\cdot9^6}=\frac{3^{12}\cdot2^5}{2^6\cdot3^{12}}-\frac{3^{11}\cdot2^6}{2^6\cdot3^{12}}=\frac{1}{2}-\frac{1}{3}=\frac{1}{6}\)
=))
a) \(\frac{9^3.2^{10}.27^5}{4^5.81^6}\)= \(\frac{\left(3^2\right)^3.2^{10}.\left(3^3\right)^5}{\left(2^2\right)^5.\left(3^4\right)^5}\)= \(\frac{3^{2.3}.2^{10}.3^{3.5}}{2^{2.5}.3^{4.5}}\)= \(\frac{3^6.2^{10}.3^{15}}{2^{10}.3^{20}}\)= \(\frac{3^{21}.2^{10}}{2^{10}.3^{20}}\)= \(\frac{3^{20}.2^{10}.3}{2^{10}.3^{20}}\)= \(3\)
\(a,\frac{9^3\cdot2^{10}\cdot27^5}{4^5\cdot81^6}\)
\(=\frac{\left[3^2\right]^3\cdot\left[2^2\right]^5\cdot\left[3^3\right]^5}{\left[2^2\right]^5\cdot\left[3^4\right]^6}\)
\(=\frac{3^6\cdot2^{10}\cdot3^{15}}{2^{10}\cdot3^{24}}=\frac{3^6\cdot3^{15}}{3^{24}}=\frac{3^{21}}{3^{24}}=3^{21-24}=3^{-3}=\frac{1}{27}\)
b, Như bạnThảo Nguyễn 緑
giải pt \(\sqrt{x+3}+\sqrt{10-x}=x^2-7x+11\)
đk -3 =< x =< 10
\(\sqrt{x+3}-2+\sqrt{10-x}-3=x^2-7x+6\)
\(\Leftrightarrow\dfrac{x+3-4}{\sqrt{x+3}+2}+\dfrac{10-x-9}{\sqrt{10-x}+3}=\left(x-6\right)\left(x-1\right)\)
\(\Leftrightarrow\dfrac{x-1}{\sqrt{x+3}+2}+\dfrac{1-x}{\sqrt{10-x}+3}=\left(x-6\right)\left(x-1\right)\)
\(\Leftrightarrow\left(x-1\right)\left(\dfrac{1}{\sqrt{x+3}+2}-\dfrac{1}{\sqrt{10-x}+3}-x+6\ne0\right)=0\Leftrightarrow x=1\)(tm)
\(9^2.9^2.9^1\)
\(\left(3^{10}:3^5\right)\left(2^9:2^4\right)\)
Ai tích mik mik tích lại
Thề luôn
Thanks
\(9^{2+2+1}=9^5\)
\(3^5.2^5=\left(3.3.3.3.3\right).\left(2.2.2.2.2\right)=\left(3.2\right).\left(3.2\right).\left(3.2\right).\left(3.2\right).\left(3.2\right)=6.6.6.6.6=6^5\)
Tích nha mik tích lại
thanks nhiều
Giải các bất phương trình sau:
a) -2x2 + 7x - 10 < 0
b) \(\dfrac{1+x}{1-x}\) ≤ 2
c) \(\dfrac{x}{x-2}-\dfrac{2}{x-3}\) > 1
d) (x2 + 4x + 10)2 - 7(x2 + 4x + 11) + 7 < 0
a) 2(7x+10)+5=3(2x-3)-9x
b) (x+1)(2x-30=(2x-10)(x+5)
c) 2x+x(x+1)(x-1)=(x+1)(x2-x+1)
d) (x-1)3-x(x+1)2=5x(2-x)-11(x+2)
a: =>14x+20+5=6x-9-9x
=>14x+25=-3x-9
=>17x=-34
=>x=-2
b: =>\(2x^2-30x+2x-30=2x^2+10x-10x-50\)
=>-28x-30=-50
=>-28x=-20
=>x=20/28=5/7
c: =>2x+x^3-x=x^3+1
=>x=1
d: =>x^3-3x^2+3x-1-x(x^2+2x+1)=10x-2x^2-11x-22
=>x^3-3x^2+3x-1-x^3-2x^2-x=-2x^2-x-22
=>-5x^2+2x-1+2x^2+x+22=0
=>-3x^2+3x+21=0
=>x^2-x-7=0
=>\(x=\dfrac{1\pm\sqrt{29}}{2}\)
(7X - 11 )3 = 25.52 + 2 . 102
. = x (>o<)
TÌM X
(7x-11)^3=2^5.5^2+200
x^10=x
(2x-15)^5=(2x-15)^3
b) x^10=1x
=> x=0 ; 1
c)(2x-15)^5=(2x-15)^3
=> (2x-15)^4 = (2x-15)^2
=> (2x-15)^2 =1
=> 2x-15=1
=> x=8