218 x 7 + 218 x 16 - 218 x 14 + 218

= 218 x ( 7 + 16 - 14 + 1 )

= 218 x 10

= 2180

2180 hả (chưa chắc)

đúng thì k me nha

   218 x 7 + 218 x 16 - 218 x 14 + 218

= 218 x (7 + 16 - 14 + 1)

= 218 x 10

= 2180

Ta có : 218 - ( x + 81 ) = x - 29

\( \implies\) 218 - x - 81 = x - 29

\( \implies\) 137 - x = x - 29

\( \implies\) 2x = 166

\( \implies\) x = 83 

218 - (x +31)=x - 29

218 - x -31=x-29

218-x=x-29+31

218-x=x+2

x+2=218-x

2=218-x-x

2=218-Xx2

xX2=218-2

Xx2=216

x=216:2

x=108

218 - ( x + 31) = x - 29

<=> 218 - x - 31 = x - 29

<=> -x - x = -29 - 218 + 31

<=> -2x = -216

<=> x = - 108

Vậy x = - 108

\(\dfrac{x^2-10x-29}{1971}+\dfrac{x^2-10x-27}{1973}=\dfrac{x^2-10x-1971}{29}+\dfrac{x^2-10x-1973}{27}\)=> \(\dfrac{x^2-10x-29}{1971}-1+\dfrac{x^2-10x-27}{1973}-1=\dfrac{x^2-10x-1971}{29}-1+\dfrac{x^2-10x-1973}{27}-1\)=>\(\dfrac{x^2-10x-2000}{1971}+\dfrac{x^2-10x-2000}{1973}=\dfrac{x^2-10x-2000}{29}+\dfrac{x^2-10x-2000}{27}\) => \(\left(x^2-10x-2000\right)\left(\dfrac{1}{1971}+\dfrac{1}{1973}-\dfrac{1}{29}-\dfrac{1}{27}\right)\)

=> \(x^2-10x-2000=0\)

Tự giải ra nhé hi hi

218-(x+31)=x-29

218-31=x+x-29

2x=218-31+29=218-(31-29)

2x=218-2=216

x=216/2

x=108

     \(218-\left(x+31\right)=x-29\)

\(\Leftrightarrow\)\(218-x-31=x-29\)

\(\Leftrightarrow\)\(187-x=x-29\)

\(\Leftrightarrow\)\(2x=216\)

\(\Leftrightarrow\)\(x=108\)

Vậy....

218-(x + 31) = x - 29

=> 218 - x - 31 = x - 29

=> (218-31) - x = x - 29

=> 187 - x = x - 29

=> -x - x = -29 - 187

=> -2x = -216

=> x = -216 : (-2)

=> x = 108

218 - ( x + 31 ) = x - 29

x + 31 + x - 29 = 218

2x + 2 = 218

2x = 218 - 2

2x = 216

  x = 216 : 2

  x = 108

a) 23 + 25 + 27 + 29 + 31 + 33 + 35

= 23 + ( 25 + 35 ) + ( 27 + 33 ) + ( 29 + 31 )

= 23 +        60      +      60         +      60

= 23 + 60 x 3

= 23 +    180

= 203

b) 4 . 36 . 25 . 50

=  4 . 4 .9 . 25 . 25 . 2

= 4 . 25 . 4 . 25 . 9 . 2

=   100 . 100     . 9 . 2

= 10 000           . 18

= 180 000

c) 32 . 125 . 3 

= 4 . 8 . 5 . 25 . 3

= 4 . 25 . 8 . 5 . 3

=  100    . 8 . 5 . 3

=      800 . 5 . 3

= 4000 . 3

= 12000

d, 36 . 19 + 36 . 81

= 36 . ( 19 + 81 )

= 36 . 100

= 3600

e, 78 . 31 + 78 . 24 + 78 . 17 + 22 x 72

= 78 . ( 31 + 24  + 17 ) + 22 x 72

= 78 . 72 + 22 . 72

= 72 . ( 78 + 22 )

= 72 . 100

= 7200

A)23+25+27+29+31+33+35

= (33+27)+(25+35)+(29+31)+23

=60+60+60+23

=60x3+23

=180+23

=203

B)4.36.25.50=(36.25).(4.50)

=(4.9.25).(2.2.50)

=(4.25).9 .(2.50).2

=100.9.100.2

=100.(9+2)

=100 .11

=1100

C)32.125.3=(4.8).125.3

=(125.8).(4.3)

=1000.12

=12000

D)36.19.36.81=36.(19+81)

 = 36.100

=3600

E)78.31.+78.24+78.17+22x72=78.31+78.24+78.17+ (16+6).72

=78.31+78.24+78.17+78.16

=78.(31+24+17+16)

=78.88

=6864

thiếu đề bạn ơi

\(\frac{x+1}{35}+\frac{x+3}{33}=\frac{x+5}{31}+\frac{x+7}{29}\)

\(\Leftrightarrow\frac{x+1}{35}+1+\frac{x+3}{33}+1=\frac{x+5}{31}+1+\frac{x+7}{29}+1\)

\(\Leftrightarrow\frac{x+36}{35}+\frac{x+36}{33}=\frac{x+36}{31}+\frac{x+36}{29}\)

\(\Leftrightarrow\frac{x+36}{35}+\frac{x+36}{33}-\frac{x+36}{31}-\frac{x+36}{29}=0\)

\(\Leftrightarrow\left(x+36\right)\left(\frac{1}{35}+\frac{1}{33}-\frac{1}{31}-\frac{1}{29}\right)=0\)

\(\Leftrightarrow x+36=0\).Do \(\frac{1}{35}+\frac{1}{33}-\frac{1}{31}-\frac{1}{29}\ne0\)

\(\Leftrightarrow x=-36\)