ta có:

\(1+\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+...+\frac{1}{x\left(x+3\right)}\)=1\(\frac{7}{24}\)\(=\frac{31}{24}\)

\(1+\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{x\left(x+3\right)}=\frac{31}{24}\)

\(3+\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{x\left(x+3\right)}=\frac{31}{3}\)

\(3+1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{31}{3}\)

\(3+1-\frac{1}{x+3}=\frac{31}{3}\)

\(4-\frac{1}{x+3}=\frac{31}{3}\)

\(\frac{1}{x+3}=4-\frac{31}{3}=\frac{-19}{3}\)

=>ko tìm được x

Nguyễn Minh Châu giải sai rồi

=> 1/11 - 1/13 + 1/13 - 1/15 + ..... + 1/19 - 1/21 - x + 4 + 221/231 = 7/3

=> 1/11 - 1/21 - x + 4 + 221/231 = 7/3

=> 2099/420 - x = 7/3

=> x = 2099/420 - 7/3 = 373/140

Tk mk nha

Bài làm

\(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2\left(\frac{1}{11.13}+\frac{1}{13.15}+...+\frac{1}{19.21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2\left(\frac{1}{11}-\frac{1}{21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2.\frac{10}{231}-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow\frac{20}{231}-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow\frac{20}{231}-x+\frac{924}{231}+\frac{221}{231}=\frac{539}{231}\)

\(\Leftrightarrow\frac{20}{231}-x+\frac{924}{231}=\frac{539}{231}-\frac{221}{231}\)

\(\Leftrightarrow\frac{20}{231}-x+\frac{924}{231}=\frac{318}{231}\)

\(\Leftrightarrow\frac{20}{231}-x=\frac{318}{231}-\frac{924}{231}\)

\(\Leftrightarrow\frac{20}{231}-x=-\frac{606}{231}\)

\(\Leftrightarrow x=\frac{20}{231}-\frac{606}{231}\)

\(\Leftrightarrow x=-\frac{586}{231}\)

Vậy \(\Leftrightarrow=-\frac{586}{231}\)

ta có : 2/11*15 +2/13*15+...+2/19*21 - x +4+221/231=7/3

=>(1/11 -1/13 + 1/13-1/15+...+1/19 - 1/21)-x+4 +221/231=7/3

<=>(1/11 - 1/21)-x+4 + 221/231=7/3

<=>10/231 -  x+4 +221/231 =7/3

<=>1-x +4=7/3

<=>x+4=1-7/3

<=>x+4=-4/3

<=>x=-4/3-4

<=>x=-16/3

vậy x=-16/3

= 100% luôn

b: \(\Leftrightarrow1-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{23}+\dfrac{1}{23}-\dfrac{1}{34}+...+\dfrac{1}{89}-\dfrac{1}{100}+x=\dfrac{5}{3}\)

=>x+99/100=5/3

=>x=5/3-99/100=203/300

c: \(\Leftrightarrow\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}+...+\dfrac{1}{19}-\dfrac{1}{21}\right)-x+4+\dfrac{221}{231}=\dfrac{7}{3}\)

\(\Leftrightarrow\dfrac{10}{231}-x+4+\dfrac{221}{231}=\dfrac{7}{3}\)

=>5-x=7/3

hay x=8/3

chiu thoi

\(\left(\frac{2}{11\times13}+\frac{2}{13\times15}+\frac{2}{15\times17}+\frac{2}{17\times19}+\frac{2}{19\times21}\right)\times462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)\times462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-x=19\)

\(\frac{10}{231}\times462-x=19\)

\(20-x=19\)

\(\Rightarrow x=20-19=1\)

chịu thôi làm sao được chết mất

`(2/(11.13)+2/(13.15)+....+2/(19.21)).462-[0,04/(x+1,05):0,12=19`

`=>(1/11-1/13+1/13-1/15+....+1/19-1/21).462-(2/(50(x+1,05)).25/3=19`

`=>(1/11-1/21).462-1/(3(x+1,05))=19`

`=>10/231. 462-1/(3x+3,15)=19`

`=>20-1/(3x+3,15)=19

`=>1/(3x+3,15)=1`

`=>3x+3,15=1`

`=>3x=-2,15`

`=>x=-43/60`

Vậy `x=-43/60`

Giải: 

\(\left(\dfrac{2}{11.13}+\dfrac{2}{13.15}+...+\dfrac{2}{19.21}\right).462-\left[\dfrac{0,04}{x+1,05}:0,12\right]=19\) 

\(\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}+...+\dfrac{1}{19}-\dfrac{1}{21}\right).462-\left[\dfrac{1}{\dfrac{25}{x+\dfrac{21}{20}}}:\dfrac{3}{25}\right]=19\) 

\(\left(\dfrac{1}{11}-\dfrac{1}{21}\right).462-\left[\dfrac{1}{25.\left(x+\dfrac{21}{20}\right)}:\dfrac{3}{25}\right]=19\) 

                             \(20-\left[\dfrac{25.1}{3.25.\left(x+\dfrac{21}{20}\right)}\right]=19\) 

                                              \(\dfrac{1}{3.\left(x+\dfrac{21}{20}\right)}=20-19\) 

                                               \(\dfrac{1}{3.x+\dfrac{63}{20}}=1\) 

                                      \(1:\left(3.x+\dfrac{63}{20}\right)=1\) 

                                                \(3.x+\dfrac{63}{20}=1:1\) 

                                                \(3.x+\dfrac{63}{20}=1\) 

                                                         \(3.x=1-\dfrac{63}{20}\) 

                                                         \(3.x=\dfrac{-43}{20}\) 

                                                            \(x=\dfrac{-43}{20}:3\) 

                                                            \(x=\dfrac{-43}{60}\)

= ( 1/11 - 1/21 ) *4+2-y = 19

= 10/231*4+2-y = 19

= 40/231+2-y = 19

= 502/231-y = 19

=             y = 502/231 - 19 

=             y = một số âm

nha