28 . 178 - 14 . 2 . 79 + 7.4

⇒ 28 . 178 - 28 . 79 + 28 . 1

⇒ 28 . ( 178 - 79 + 1 )

⇒ 28 . 100

⇒ 2800

   28 \(\times\) 178 - 14 \(\times\) 2 \(\times\) 79 + 7 \(\times\) 4

= 28 \(\times\) 178 - 28 \(\times\) 79 + 28 \(\times\) 1

= 28 \(\times\) (178 - 79 + 1)

= 28 \(\times\) {(178 + 1) - 79)}

= 28 \(\times\) { 179 - 79}

= 28 \(\times\) 100

= 2800

28 x 178 - 14 x 2 x 79 + 7 x 4 = 3141068

7 x 4 - 28 + 35

=28 - 28 + 35

= 0          + 35

= 35!

NHớ tk nha!

7*=28

28-28+35=35

Bằng 35

=36

x²+10x+25-4x(x+5)=0

⇔(x+5)²-4x(x+5)=0

⇔(x+5)(x+5-4x)=0

⇔(x+5)(5-3x)=0

⇔\(\left\{{}\begin{matrix}x+5=0\\5-3x=0\end{matrix}\right.\Leftrightarrow\left\{{} }\left\{{}\begin{matrix}x=-5\\x=\dfrac{5}{3}\end{matrix}\right.\)

= 300

nha từ sáng tới giờ mk chưa đc lần nào

30.4+60.3

=120+180

=300

30x4+60x3

=120+180

=300

5x²-120x-125=0

x(5x-120)=0+125

x(5x-120)=125

\(\Rightarrow\orbr{\begin{cases}x=125\\5x-120=125\Rightarrow5x=125-120\Rightarrow5x=5\Rightarrow x=5:5=1\end{cases}}\)

Vậy x=125 hoặc x=1

\(5x^2-120x-125=0\)

\(5\left(x^2-24x-25\right)=0\)

\(5\left(x-25\right)\left(x+1\right)=0\)

\(\Rightarrow5=0\)vô nghiệm 

\(\Rightarrow\orbr{\begin{cases}x-25=0\\x+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=25\\x=-1\end{cases}}}\)

5x^2-120x-125=0

x^2-24x-25=0

x^2+x-25x-25=0

X x (x+1)-25(x+1)=0

(X+1) x (X-25)=0

x+1=0 ; x-25= 0

x1=-1

x2=25

@Nguyễn Việt Lâm@Mysterious PersonAkai Haruma@tth_new giúp em với

\(PT\Leftrightarrow\left(\sqrt{4x^2-20x+28}-2\right)=3x^2-15x+18\\ \Leftrightarrow\dfrac{4x^2-20x+24}{\sqrt{4x^2-20x+28}+2}=3\left(x-2\right)\left(x-3\right)\\ \Leftrightarrow\dfrac{4\left(x-2\right)\left(x-3\right)}{\sqrt{4x^2-20x+28}+2}-3\left(x-2\right)\left(x-3\right)=0\\ \Leftrightarrow\left(x-2\right)\left(x-3\right)\left(\dfrac{4}{\sqrt{4x^2-20x+28}+2}-3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=3\\\dfrac{4}{\sqrt{4x^2-20x+28}+2}-3=0\left(1\right)\end{matrix}\right.\)

Vì \(\dfrac{4}{\sqrt{4x^2-20x+28}+2}\le2\Leftrightarrow\dfrac{4}{\sqrt{4x^2-20x+28}+2}-3\le-1< 0\)

Do đó \(\left(1\right)\) vô nghiệm

Vậy PT có nghiệm \(x=2;x=3\)