Ai giúp mình vs mình cảm ơn trc ạ
Giúp mình vs. Mình cảm ơn trc ạ
a. 1.2 + 32 + 16.4 = 98đvC
b. 31.2 + 16.3 = 110đvC
c. 23 + 16 + 1 = 40đvC
d. 39 + 14 + 16.3 = 101đvC
Ai giúp mình với mình cảm ơn trc ạ
c) Ta có: \(\sqrt{\sqrt{x}+3}=3\)
\(\Leftrightarrow\sqrt{x}+3=9\)
\(\Leftrightarrow\sqrt{x}=6\)
hay x=36
Ta có: \(\sqrt{x-2\sqrt{x-1}}=2\)
\(\Leftrightarrow x-2\sqrt{x-1}-4=0\)
\(\Leftrightarrow x-1-2\cdot\sqrt{x-1}\cdot1+1=4\)
\(\Leftrightarrow\left(\sqrt{x-1}-1\right)^2=4\)
\(\Leftrightarrow\sqrt{x-1}-1=2\)
\(\Leftrightarrow\sqrt{x-1}=3\)
\(\Leftrightarrow x-1=9\)
hay x=10
ai giải giúp mình vs cảm ơn trc!!!
1. When does our school year starts?
2. Where is the hotel?
3. When did you saw her?
4. Who will Liz send these letters to?
1. What
2. Where
3. Who
4. When
5. How
6. What time
7. Which
8. How much
9. Why
10. How often
Ai giúp mình bài này với ạ ! Mình cần gấp ạ , cảm ơn trc nhen ☺️✌️
Mn giúp mik bài này vs ạ 🥰 . MÌNH CẢM ƠN TRC NHIỀU 🙆♀️❤
1, What would he like to have for breakfast?
He would like to have a sandwich
2,Who would you like to go fishing with?
I would like to go fishing with my father
3,What would her children like to do in the summer?
They would like to go swimming
4,When would Mrs Tam like to go shopping?
She would like to go shopping at weekends
5,Where would Hung and Tung like to study
They would like to study in the library
1 What would he like for breakfast?
He'd like a sandwich
2 Who would you like to go fishing with?
I would like to go with my father
3 What would her children like to do in summer?
They would like to swim inpool
4 When would Mrs Tam like to go shopping?
She would like to go shopping on the weekends
5 Where would Tung and Hung like to study ?
THey would like to study in the school library
Tìm GTLN của
1-x-2x^2
Giúp mình vs mình đag gấp. Mình sẽ like cho bn nào giúp mình. Mình cảm ơn trc ạ
1-x-2x^2
= 1-x-2x.2x
= 1 - ( x + 2x.2x)
= 1 - 5x
Để 1-x-2x^2 mang giá trị lớn nhất thì x phài là số âm.
\(A=1-x-2x^2\)
\(=-2\left(x^2+2\times x\times\frac{1}{4}+\left(\frac{1}{4}\right)^2-\left(\frac{1}{4}\right)^2-\frac{1}{2}\right)\)
\(=-2\left[\left(x+\frac{1}{4}\right)^2-\frac{9}{16}\right]\)
\(\left(x+\frac{1}{4}\right)^2\ge0\)
\(\left(x+\frac{1}{4}\right)^2-\frac{9}{16}\ge-\frac{9}{16}\)
\(-2\left[\left(x+\frac{1}{4}\right)^2-\frac{9}{16}\right]\le\frac{9}{8}\)
Vậy Max A = \(\frac{9}{8}\) khi x = \(-\frac{1}{4}\)
\(A=-2x^2-x+1=-\left(2x^2+\sqrt{2}.2.\frac{1}{2\sqrt{2}}x+\frac{1}{8}\right)+\frac{9}{8}\)
\(A=-\left(\sqrt{2}x+\frac{1}{2\sqrt{2}}\right)^2+\frac{9}{8}\le\frac{9}{8}\)
\(MaxA=\frac{9}{8}\Leftrightarrow\left(\sqrt{2}x+\frac{1}{2\sqrt{2}}\right)^2=0\Leftrightarrow x=-\frac{1}{4}\)
Ai giúp mình vẽ bài này được ko ạ. Có j cho mik cảm ơn trc ạ.
Xét tg ABC có \(\widehat{A}+\widehat{B}+\widehat{C}=180^0\Rightarrow\widehat{B}+\widehat{C}=180^0-60^0=120^0\)
Mà \(\widehat{B}=2\widehat{C}\Rightarrow3\widehat{C}=120^0\)
\(\Rightarrow\widehat{C}=40^0\\ \Rightarrow\widehat{B}=80^0\)
Ai giúp mình bài văn tả cồng vòng với ạ. Cho mk cảm ơn trc ạ. (*•̀ᴗ•́*)و ̑̑
Mình cần gấp nên mong mn giúp nhiệt tình ạ🥲
Trời ơi ! Ai cứu mình với , giúp mình 2 cái bài này đc ko ? Mình đang cần gấp ạ ! Cảm ơn trc nhen 😊
Trời trời giúp mình với mấy thần đồng tiếng anh ơi , mình sắp toang ròi 😢😢😢