\(a,=b\sqrt{a}\left(\sqrt{a}+1\right)+\left(\sqrt{a}+1\right)=\left(b\sqrt{a}+1\right)\left(\sqrt{a}+1\right)\\ b,a< 0\text{ nên biểu thức không phân tích đc}\)

\(4a^2-4a+1-4b^2\)

<=>\(\left(2a-1\right)^2-4b^2\)

<=>\(\left(2a-1+2b\right)\left(2a-1-2b\right)\)

\(4a^2-4a+1-4b^2\)

\(=\left(2a-1\right)^2-4b^2\)

\(=\left(2a-1+2b\right)\left(2a-1-2b\right)\)

 4a^{2 -} 4b² - 4a -1 
= (4a²- 4a +1 ) - 4b²
= [(2a)² -2a.1 + 1² ] - (2b)2
= (2a -1 )² - (2b)2
= 2a - 1 - 2b ) . ( 2a - 1 + 2b )

\(4a^3-3a+1\)

\(=\left(4a^3-4a\right)+\left(a+1\right)\)

\(=4a\left(a^2-1\right)+\left(a+1\right)\)

\(=4a\left(a-1\right)\left(a+1\right)+\left(a+1\right)\)

\(=\left(a+1\right)\left(4a^2-4a+1\right)\)

\(=\left(a+1\right)\left(2a-1\right)^2\)

=(a² +1)²-(2a)²

=(a²+1+2a)(a²+1-2a)

=(a+1)²(a-1)²

^{mình làm thế ko biết có đúng hay ko}

( a² + 1 )² - 4a²

= ( a² + 1 )² - ( 2a )²

= ( a² + 1 + 2a ) ( a² + 1 - 2a )

........

( a² + 1 )² - 4a²

( a² + 1 )² - ( 2a)²

= ( a² + 1 + 2a ) ( a² + 1 - 2a )

= ( a + 1 ) ² ( a - 1 )²

\(8a^4-2a^2-4a+2\)

\(=2\cdot\left(4a^4-a^2-2a+1\right)\)

\(=2\cdot\left(2a-1\right)\cdot\left(2a^3+a^2-1\right)\)

\(8a^4-2a^2-4a+2\)

\(=2\left(4a^4-a^2-2a+1\right)\)

\(=2\left(4a^4-2a^3+2a^3-a^2-2a+1\right)\)

\(=2\left(2a-1\right)\left(2a^3+a^2-1\right)\)

thêm bớt 4(x-a)^2 . a^2 là được

làm ra rứa ná

nói rõ ra đc ko bạn