1/2 - 3/4 - (-1/3) + 1/69 - 2/9 + 1/6 - 1/36
B=(-5/3+2/5):4/5+(-1/3+8/5):4/5 C=1/2-2/3-(-1/3)+1/69-(2/9)+1/6-(1/36)
\(B=\left(\dfrac{-5}{3}+\dfrac{2}{5}\right):\dfrac{4}{5}+\left(\dfrac{-1}{3}+\dfrac{8}{5}\right):\dfrac{4}{5}\)
\(B=\dfrac{-5}{3}+\dfrac{2}{5}:\dfrac{4}{5}+\dfrac{-1}{3}+\dfrac{8}{5}:\dfrac{4}{5}\)
\(B=\left(\dfrac{-5}{3}+\dfrac{-1}{3}\right)+\left(\dfrac{2}{5}+\dfrac{8}{5}\right):\dfrac{4}{5}\)
\(B=\left[\left(-2\right)+2\right]:\dfrac{4}{5}\)
\(B=0:\dfrac{4}{5}=0\)
\(=>B=\dfrac{5}{4}\cdot\left(-\dfrac{5}{3}+\dfrac{2}{5}-\dfrac{1}{3}+\dfrac{8}{5}\right)=\dfrac{5}{4}\cdot\left(-2+2\right)=\dfrac{5}{4}\cdot0=0\)
\(=>C=\left(-\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{2}\right)+\left(\dfrac{1}{69}-\dfrac{1}{36}-\dfrac{2}{9}\right)\)
\(C=\left(-\dfrac{2}{6}+\dfrac{1}{6}+\dfrac{3}{6}\right)-\dfrac{65}{276}=\dfrac{1}{3}-\dfrac{65}{276}=\dfrac{157}{276}\)
Câu 15 A= 1/3-3/4+3/5+1/2007-1/36+1/25-2/9
Câu 16 A=1/3- 3/4- (-3/5)+ 1/64- 2/9- 1/36+ 1/15
Câu 17 A=1/2- 2/3+ 3/4- 4/5+ 5/6- 6/7- 5/6+ 4/5- 3/4+ 2/3- 1/2
15: A= 1/3-3/4+3/5+1/2007-1/36+1/15-2/9
Sửa đề:
A=-3/4-2/9-1/36+1/3+3/5+1/15+1/2007
=-27/36-8/36-1/36+5/15+9/15+1/15+1/2007
=-1+1+1/2007=1/2007
16:
\(A=\dfrac{1}{3}+\dfrac{3}{5}+\dfrac{1}{15}-\dfrac{3}{4}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{64}\)
\(=\dfrac{5+9+1}{15}+\dfrac{-27-8-1}{36}+\dfrac{1}{64}\)
=1/64
17:
=1/2-1/2+2/3-2/3+3/4-3/4+4/5-4/5+5/6-5/6-6/7
=-6/7
a) 100 + 98 + 96 + ... + 2 - 97 - 95 - ... - 1
b) 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + 10 - 11 - 12 + ... + 299 - 300 + 301 + 302
c) 2 . 31 . 12 + 4 .6 . 42 + 8 . 27 . 3
d) 36 . 28 + 36 . 82 + 64 . 69 + 64 . 41
e) 99 - 97 + 95 - 93 + 91 - 89 + ...+ 7 - 5 + 3 - 1
a, 100 + 98 + 96 + ... + 2 - 9 7 - 95 - .. -1
= 100 + (98 - 97) + (96-95) + ... + + ... + (2 - 1)
= 100 + 1 + 1 + 1 +.. +1
= 100 + 1 x49
= 100 + 49
= 149
b , 1 + 2 - 3 - 4 + 5 + 6 - .... -299 - 330 +301 + 302
=( 1 + 2 - 3) + ( -4 + 5 + 6 -7 ) +... +(298 - 299 -300 +301 ) + 302
= 0 + 0 + .. + 0 + 302
= 302
c) 2 . 31 . 12 + 4 . 6 . 42 + 8 . 27 . 3
=24.31+24.42+24.27
=24.(31+42+27)
=24.100
=2400
d)
=36x(28+82)+64x(69+41)
=36x110+64x110
=110x(26+64)
=110x100
=11000
d) dãy tính trên có số số tự nhiên là: (99-1):2+1=50(số)
99-97+95-93+91-89+...+7-5+3-1(50:2=25 cặp)
(99-97)+(95-93)+(91-89)+...+(7-5)+(3-1) (25 cặp)
2+2+2+2+2+...+2+2(25 số 2)
2x25=50
1 1 1=6
2 2 2=6
3 3 3=6
4 4 4=6
5 5 5=6
6 6 6=6
7 7 7=6
8 8 8=6
9 9 9=6
10 10 10=6
(Làm gì đó để phép tính bằng 6)
Ý bạn là mỗi phép tính phải thêm dấu và ....để kết quả bằng 6 phải không ạ
(1+1+1)×2=6
2+2+2=6
3×30+3=6
(4+4+4)÷2=6
(50+50+50)×2=6
6×60×60=6
7-70×70=6
8-(80+80)=6
(90+90+90)×2=6
(100+100+100)×2=6
Bai1 tính nhanh phép tính
a) 37581-9999
Bài2 tính nhanh
a) 36×28+36×82+64×69+64×41
b) A=41×66+34×41/3+7+11+...+79
c) 1×5×6+2×10×12+4×20×24+9×45×54/1×3×5+2×6×10+4×12×20+9×27×45
Bài 1 :
a) 37581 - 9999 = 37581 - 10000 - 1 = 27581 - 1 = 27580
k cho mình nha bạn !
a)37581-9999=37581-(9999+1-1)=37581-(10000+1)=37581-10000-1=27581+1=27582
bài 1:
1/4 + 2/3 2/7 + 2/3 2/5 + 1/3 2/3 + 1/2 1/3 + 3/5 4/5 + 1/3
1/8 + 3/4 1/36 + 5/12 1/3 + 1/6 + 1/18.
bài 2:
15/16 - 3/16 17/18 - 5/6 3/4 - 4/9 1/2 - 2/5 5/6 - 3/10 3-1/3
4/5 - 1/10 5/2 - 1 5/8 - 2/5.
\(\dfrac{-7}{9}+\dfrac{-2}{9}\)
\(\dfrac{15}{4}-\dfrac{-3}{4}\)
\(\dfrac{1}{6}-\dfrac{1}{36}\)
\(1-\dfrac{3}{2}\)
\(2-\dfrac{4}{5}\)
\(\dfrac{-7}{9}+\dfrac{-2}{9}=\dfrac{-9}{9}=-1\)
\(\dfrac{15}{4}-\dfrac{-3}{4}=\dfrac{18}{4}=\dfrac{9}{2}\)
\(\dfrac{1}{6}-\dfrac{1}{36}=\dfrac{6}{36}-\dfrac{1}{36}=\dfrac{5}{36}\)
\(1-\dfrac{3}{2}=\dfrac{2}{2}-\dfrac{3}{2}=\dfrac{-1}{2}\)
\(2-\dfrac{4}{5}=\dfrac{10}{5}-\dfrac{4}{5}=\dfrac{6}{5}\)
[-1/2-[-3/5]+[-1/9+1/71-[-2/7]+4/35-7/18
1/3-3/4-[-3/5]+1/64-2/9-1/36+1/15
-5/7-[-5/67]+13/30+1/2+[-11/6]+17/14-[-2/5]
[3-1/4+2/3]-[5-1/3-6/5]-[6-7/4+3/2]
[5+1/5-2/9]-[2-1/23-73/35+5/6]-[8+2/7-1/18]
làm giúp mình mình đang cần gấp
1. | 4-2x | . 1/3 = 1/3
2. (-3)² : | x+(-1) | = (-3)
3. | 3/2 -x | + (-4/5) = -14/5
4. (-4/3) - | 2x + (-1) | = -7/3
5. -9 . | 36 - x/2 | = (-54)
6. 0,75 - | (-x) + 1/3 | = 0,25
7. (-6/5) + | x-9 |= (-6/5)
8. (-4) . | 3x - 1/5 | = 12
1) \(\left|4-2x\right|.\dfrac{1}{3}=\dfrac{1}{3}\)
\(\left|4-2x\right|=\dfrac{1}{3}:\dfrac{1}{3}\)
\(\left|4-2x\right|=\dfrac{1}{3}.3\)
\(\left|4-2x\right|=1\)
=>\(4-2x=\pm1\)
+)\(TH1:4-2x=1\) +)\(TH2:4-2x=-1\)
\(2x=4-1\) \(2x=4-\left(-1\right)\)
\(2x=3\) \(2x=4+1\)
\(x=3:2\) \(2x=5\)
\(x=1,5\) \(x=5:2\)
Vậy x=1,5 \(x=2,5\)
Vậy x=2,5
2) \(\left(-3\right)^2:\left|x+\left(-1\right)\right|=-3\)
\(9:\left|x+\left(-1\right)\right|=-3\)
\(\left|x+\left(-1\right)\right|=9:\left(-3\right)\)
\(\left|x+\left(-1\right)\right|=-3\)
=> \(x+\left(-1\right)\) sẽ không có giá trị nào ( Vì giá trị tuyệt đối luôn luôn lớn hơn hoặc bằng 0 )
Vậy x = \(\varnothing\)
3) \(\left|\dfrac{3}{2}-x\right|+\left(-\dfrac{4}{5}\right)=-\dfrac{14}{5}\)
\(\left|\dfrac{3}{2}-x\right|=\left(-\dfrac{14}{5}\right)-\left(-\dfrac{4}{5}\right)\)
\(\left|\dfrac{3}{2}-x\right|=\left(-\dfrac{14}{5}\right)+\dfrac{4}{5}\)
\(\left|\dfrac{3}{2}-x\right|=-\dfrac{10}{5}\)
\(\left|\dfrac{3}{2}-x\right|=-2\)
=> \(\dfrac{3}{2}-x\) không có giá trị nào thỏa mãn ( Vì giá trị tuyệt đối không thể là số nguyên âm )
Vậy x=\(\varnothing\)