Tính B=\(\left(\dfrac{7}{19.31}+\dfrac{5}{19.43}+\dfrac{3}{23.43}+\dfrac{11}{23.57}\right)\):\(\left(\dfrac{1}{31}-\dfrac{1}{57}\right)\)
Làm nhanh cho mình nha!!Mai thi rùi
Tính tỉ số \(\dfrac{A}{B}\) biết \(A=\dfrac{4}{7.31}+\dfrac{6}{7.41}+\dfrac{9}{10.41}+\dfrac{7}{10.57}\) và \(B=\dfrac{7}{19.31}+\dfrac{5}{19.43}+\dfrac{3}{23.43}+\dfrac{11}{23.57}\)
\(A=\dfrac{4}{7.31}+\dfrac{6}{7.41}+\dfrac{9}{10.41}+\dfrac{7}{10.57}\Rightarrow\dfrac{A}{5}=\dfrac{4}{35.31}+\dfrac{6}{35.41}+\dfrac{9}{50.41}+\dfrac{7}{50.57}\)
\(\dfrac{A}{5}=\dfrac{1}{31}-\dfrac{1}{35}+\dfrac{1}{35}-\dfrac{1}{41}+\dfrac{1}{41}-\dfrac{1}{50}+\dfrac{1}{50}-\dfrac{1}{57}\)
\(\dfrac{A}{5}=\dfrac{1}{31}-\dfrac{1}{57}=\dfrac{26}{31.57}\Rightarrow A=\dfrac{130}{31.57}\)
\(\dfrac{B}{2}=\dfrac{7}{38.31}+\dfrac{5}{38.41}+\dfrac{3}{46.43}+\dfrac{11}{46.57}\Rightarrow\dfrac{B}{2}=\dfrac{1}{31}-\dfrac{1}{57}=\dfrac{26}{31.57}\)
\(\Rightarrow B=\dfrac{52}{31.57}\)
\(\dfrac{A}{B}=\dfrac{130}{31.51}:\dfrac{52}{31.57}=\dfrac{5}{2}\)
Ta có : `A:5=4/35.31+6/35.41++9/50.41+7/50.57`
`A/5 = 1/31 - 1/35 +1/35-1/41+1/41-1/50+1/50-1/57`
`A/5 =1/31-1/57` `(1)`
Lại có : `B:2=7/38.31 +5/38.43+3/46.43+11/46.57`
`B/2 =1/31-1/38+1/38-1/43+1/43-1/46+1/46-1/57`
`B/2 =1/31-1/57` `(2)`
Từ `(1)` và `(2)` `=>A/5 =B/2`
`=>A/B=5/2`
\(\text{Câu 1: Cho các số A và B. Hãy tính tỉ số }\)\(\dfrac{A}{B}\) \(biết:\)
\(a\)) \(A=\dfrac{4}{7.31}+\dfrac{6}{7.41}+\dfrac{9}{10.41}+\dfrac{7}{10.57};\)
\(B=\dfrac{7}{19.31}+\dfrac{5}{19.43}+\dfrac{3}{23.43}+\dfrac{11}{23.57}\)
\(b\)) \(A=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{2021};\)
\(B=\dfrac{2020}{1}+\dfrac{2019}{2}+\dfrac{2018}{3}+...+\dfrac{1}{2020}\)
a) Ta có: \(A=\dfrac{4}{7\cdot31}+\dfrac{6}{7\cdot41}+\dfrac{9}{10\cdot41}+\dfrac{7}{10\cdot57}\)
\(=\dfrac{20}{31\cdot35}+\dfrac{30}{35\cdot41}+\dfrac{45}{41\cdot50}+\dfrac{35}{50\cdot57}\)
\(=5\left(\dfrac{4}{31\cdot35}+\dfrac{6}{35\cdot41}+\dfrac{9}{41\cdot50}+\dfrac{7}{50\cdot57}\right)\)
\(=5\left(\dfrac{1}{31}-\dfrac{1}{35}+\dfrac{1}{35}-\dfrac{1}{41}+\dfrac{1}{41}-\dfrac{1}{50}+\dfrac{1}{50}-\dfrac{1}{57}\right)\)
\(=5\left(\dfrac{1}{31}-\dfrac{1}{57}\right)\)
Ta có: \(B=\dfrac{7}{19\cdot31}+\dfrac{5}{19\cdot43}+\dfrac{3}{23\cdot43}+\dfrac{11}{23\cdot57}\)
\(=\dfrac{14}{31\cdot38}+\dfrac{10}{38\cdot43}+\dfrac{6}{43\cdot46}+\dfrac{22}{46\cdot57}\)
\(=2\left(\dfrac{7}{31\cdot38}+\dfrac{5}{38\cdot43}+\dfrac{3}{43\cdot46}+\dfrac{11}{46\cdot57}\right)\)
\(=2\left(\dfrac{1}{31}-\dfrac{1}{38}+\dfrac{1}{38}-\dfrac{1}{43}+\dfrac{1}{43}-\dfrac{1}{46}+\dfrac{1}{46}-\dfrac{1}{57}\right)\)
\(=2\left(\dfrac{1}{31}-\dfrac{1}{57}\right)\)
Suy ra: \(\dfrac{A}{B}=\dfrac{5\left(\dfrac{1}{31}-\dfrac{1}{57}\right)}{2\left(\dfrac{1}{31}-\dfrac{1}{57}\right)}=\dfrac{5}{2}\)
Tính B=\(\left(\frac{7}{19.31}+\frac{5}{19.43}+\frac{3}{23.43}+\frac{11}{23.57}\right):\left(\frac{1}{31}-\frac{1}{57}\right)\)
a,CMR
M=(\(2012+2012^2+2012^3+...+2012^{2010}\))chia hết cho 20
b,Cho
A=\(\dfrac{4}{7.31}+\dfrac{6}{7.41}+\dfrac{9}{10.41}+\dfrac{7}{10.57}\)
B=\(\dfrac{7}{19.31}+\dfrac{5}{19.43}+\dfrac{3}{23.43}\dfrac{11}{23.57}\)
Tính tỉ số \(\dfrac{A}{B}\)
Tính tỉ số \(\dfrac{A}{B}\) biết :
A = \(\dfrac{4}{7.31}\) + \(\dfrac{6}{7.41}\) + \(\dfrac{7}{10.57}\)
B = \(\dfrac{7}{19.31}\) + \(\dfrac{5}{19.43}\) + \(\dfrac{3}{23.43}\) + \(\dfrac{11}{23.57}\)
Tính B=(7/19.31+5/19.43+3/23.43+11/23.57):(1/31-1/57)
Tính B=(7/19.31+5/19.43+3/23.43+11/23.57):(1/31-1/57)
\(\left(\frac{7}{19.31}+\frac{5}{19.43}+\frac{3}{23.43}+\frac{11}{23.57}\right):\left(\frac{1}{31}-\frac{1}{57}\right)\)
\(=\frac{7}{19}.\frac{7}{31}+\frac{5}{19}.\frac{5}{43}+\frac{3}{23}.\frac{3}{43}+\frac{11}{23}.\frac{11}{57}:\frac{1}{31}-\frac{1}{57}\)
\(=\frac{7}{19}+\frac{5}{19}.\frac{7}{31}+\frac{1}{31}:\frac{5}{43}-\frac{3}{43}.\frac{3}{23}+\frac{11}{23}.\frac{11}{57}+\frac{1}{57}\)
\(=\frac{12}{19}.\frac{8}{31}:\frac{2}{43}.\frac{7}{16}.\frac{4}{19}\)
\(=\frac{1204}{1767}\)
Tính B=(7/19.31+5/19.43+3/23.43+11/23.57):(1/31-1/57)
B=7/(19.31)+5/(19.43)+3/(23.43)
+11/(23.57)
Ta nhân cả tử và mẫu của các phân số biểu thức B với 2
=>B=2(1/31-1/57)
=>A/B=5/2
A=4/(7.31)+6/(7.41)+9/(10.41)+7/(10.51)
=20/(35.31)+30/(35.41)+45/(50.41)
+35/(50.51)
=5[4/(35.31)+6/(35.41)+9/(50.41)
+7/(50.51)]
=5(1/31-1/35+1/35-1/41+1/41-1/50
+1/50-1/57)
=5(1/31-1/57)
B=7/(19.31)+5/(19.43)+3/(23.43)
+11/(23.57)
tương tự chưng minh như biểu thức A ta nhân cả tử và mẫu của các phân số biểu thức B với 2
=>B=2(1/31-1/57)
=>A/B=5/2
vậy B=5/2
Tính B=(7/19.31+5/19.43+3/23.43+11/23.57):(1/31-1/57)