tìm x : (x-3)^2=128
Tìm x thuộc N biết :
a) 2^x . 4 = 128
b) 2^x = 4 . 128
c) 3^x = 3^3 . 3^5
d) 2^x . ( 2^2 ) mũ 3 = ( 2^3 ) mũ 2
\(a,2^x.4=128\)
\(\Leftrightarrow2^x=128:4\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(b,2^x=4.128\)
\(\Leftrightarrow2^x=2^2.2^7\)
\(\Leftrightarrow2^x=2^9\)
\(\Rightarrow x=9\)
\(c,3^x=3^3.3^5\)
\(\Leftrightarrow3^x=3^8\)
\(\Rightarrow x=8\)
\(d,2^x.\left(2^2\right)^3=\left(2^3\right)^2\)
\(\Leftrightarrow2^x.2^6=2^6\)
\(\Leftrightarrow2^x=2^6:2^6\)
\(\Leftrightarrow2^x=1\)
\(\Rightarrow x=0\)
Trả lời:
a, 2x . 4 = 128
=> 2x = 32
=> 2x = 25
=> x = 5
b, 2x = 4.128
=> 2x = 512
=> 2x = 29
=> x = 9
c, 3x = 33 . 35
=> 3x = 38
=> x = 8
d, 2x ( 22 )3 = ( 23 )2
=> 2x . 26 = 26
=> 2x = 1
=> 2x = 20
=> x = 0
Tìm x biết ( x - 2/9)^3 ÷ -128/5 = -2/125 ÷ (x - 2/9)
Tìm x
9 <3^x<81
1<2^x.3^x <128
1. 2^x.4=128
2 x^15=x
3. 16^x<128
4. 5^x.5^x+1.5^x+2< hoặc = 100...0 (18 chữ số 0) chia 2^18
5. 2^x.(2^2)^2=(2^3)^2
6. (x^5)^10=x
Câu 3: Tìm x ∈ N, biết:
a) 3 x . 3 = 243 b) 2 x . 162 = 1024 c) 64.4x = 168 d) 2 x = 16Câu 4 : Tìm x, biết. a) 2 x .4 = 128 b) (2x + 1)3 = 125 c) 2x – 2 6 = 6 d) 49.7x = 24013:
a: 3^x*3=243
=>3^x=81
=>x=4
b; 2^x*16^2=1024
=>2^x=4
=>x=2
c: 64*4^x=16^8
=>4^x=4^16/4^3=4^13
=>x=13
d: 2^x=16
=>2^x=2^4
=>x=4
Tìm x:
A. ( x - 5 )² = 16
B. 4^x + 33 = 7²
C. 2^x . 4 = 128
D. 5^x . 3 - 75 = 0
(\(x\) - 5)2 = 16
(\(x-5\))2 = 42
\(\left[{}\begin{matrix}x-5=4\\x-5=-4\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=9\\x=1\end{matrix}\right.\)
Vậy \(x\) \(\in\) { 1; 9 }
B. 4\(x\) + 33 = 72
4\(^x\) + 33 = 49
4\(^x\) = 49 - 33
4\(^x\) = 16
4\(^x\) = 16
4\(^x\) = 42
\(x\) = 2
c. 2\(^x\).4 = 128
2\(^x\) = 128 : 4
2\(^x\) = 32
2\(^x\) = 25
\(x\) = 5
D, 5\(^x\) . 3 - 75 = 0
5\(^x\).3 = 75
5\(^x\) = 75: 3
5\(^x\) = 25
5\(^x\) = 52
\(x\) = 2
A) \(\left(x-5\right)^2=16=4^2\Rightarrow\left[{}\begin{matrix}x-5=4\\x-5=-4\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=9\\x=1\end{matrix}\right.\)
B) \(4^x+33=7^2\Rightarrow4^x=49-33\Rightarrow4^x=16=4^2\Rightarrow x=2\)
C) \(2^x.4=128\Rightarrow2^x=32=2^5\Rightarrow x=5\)
D) \(5^x.3-75=0\Rightarrow5^x.3=75\Rightarrow5^x=25=5^2\Rightarrow x=2\)
\(A.\left(x-5\right)^2=16\\ \left(x-5\right)^2=4^2\\ =>x-5=4\\ x=5+4\\ x=9\\ B.4^x+33=7^2\\ 4^x+33=49\\ 4^x=49-33\\ 4^x=16\\ 4^x=4^2\\ =>x=2\\ C.2^x\cdot4=128\\ 2^x\cdot2^2=2^7\\ 2^{x+2}=2^7\\ =>x+2=7\\ x=7-2\\ x=5\\ D.5^x\cdot3-75=0\\ 5^x\cdot3=75\\ 5^x=75:3\\ 5^x=25\\ 5^x=5^2\\ =>x=2\)
tìm x
128 -(x+13)=87 2 . x - 13= 29
128-3 . x = 92 546: (x+17) = 13
. là dấu nhân nha
128 - ( x + 13 ) = 87
x + 13 = 128 - 87
x + 13 = 41
x = 41 - 13
x = 28
2 . x - 13 = 29
2 . x = 29 - 13
2 .x = 16
x = 16 : 2
x = 8
128 - 3 . x = 92
3 . x = 128 - 92
3 . x = 36
x = 36 : 3
x = 12
546 : ( x + 17 ) = 13
x + 17 = 546 : 13
x + 17 = 42
x = 42 - 17
x = 25
Tìm x thuộc N
a)2^x(2 mũ x):4=128
b)x^15(x mũ 15)=x
c)(2.x+1)^3(mũ 3)=125
a) 2x : 4 = 128
=> 2x = 512
=> 2x = 29
=> x = 9
b) x15 = x
=> x15 = x15
=> x = 1 hoặc 0
c) ( 2x + 1 )3 = 125
=> ( 2x + 1 )3 = 53
=> 2x + 1 = 5
=> 2x = 4
=> x = 2
a) 2x : 4 = 128
=> 2x = 128 . 4
=> 2x = 512
=> 2x = 29
=> x = 9
b) x15 = x
=> x15 = x15
=> x = 1 hoặc 0
c) ( 2x + 1 )3 = 125
=> ( 2x + 1 )3 = 53
=> 2x + 1 = 5
=> 2x = 5 - 1
=> 2x = 4
=> x = 4 : 2
=> x = 2
Câu 4 : Tìm x, biết.
a) 2^x.4 = 128 b) (2x + 1)^3 = 125 c) 2x – 2^6 = 6 d) 49.7^x = 2401\(a,2^x.4=128\\2^x.2^2=2^7\\ 2^x=\dfrac{2^7}{2^2}=2^{7-2}=2^5\\ Vậy:x=5\\ ----\\ b,\left(2x+1\right)^3=125=5^3\\ \Rightarrow 2x+1=5\\ 2x=5-1=4\\ x=\dfrac{4}{2}=2\\ ----\\ c,2x-2^6=6\\ 2x=6+2^6=6+64\\ 2x=70\\ x=\dfrac{70}{2}=35\\ ----\\ d,49.7^x=2401\\ 7^x=\dfrac{2401}{49}=49=7^2\\ Vậy:x=2\)