nhanh giúp em ạ

1. am going to meet

2. fought

3.happens

4. will take

5. will take place

6. bought/ 29. is going to leave

7. went

8. jogging

9. bought

10. leave

11.bought

12 to travel

13. learn

14 is going to travel

15. study

16. taught

17.  aren't watching 

18.cooking

19. playing

20. visiting

bình chọn giúp mik :)) chúc bn học tốt

1. am going to meet

2. fought

3.happens

4. will take

5. will take place

6. bought/ 29. is going to leave

7. went

8. jogging

9. bought

10. leave

11.bought

12 to travel

13. learn

14 is going to travel

15. study

16. taught

17.  aren't watching 

18.cooking

19. playing

20. visiting

bình chọn giúp mik :)) chúc bn học tốt

bang a nha ban

ủa câu mấy cơ ?

Gọi giao điểm AE và BP là F;

Gọi giao điểm QD và AB là H; 

Gọi kéo dài AD cắt BF tại P'     

Dễ cm M là trung điểm AC

Xét \(\Delta OMC\) có QD//CM\(\Rightarrow\dfrac{OD}{OM}=\dfrac{QD}{CM}\)(hệ quả tales)

Tương tự với \(\Delta OAM\) có \(\dfrac{OD}{OM}=\dfrac{DH}{AM}\) 

\(\Rightarrow\dfrac{QD}{CM}=\dfrac{DH}{AM}\)

Mà CM=AM (vì M là tđ AC)

\(\Rightarrow QD=DH\)

Dễ cm P là trung điểm BF

Xét \(\Delta ABP'\) có DH//BP'

\(\Rightarrow\dfrac{DH}{BP'}=\dfrac{AD}{AP'}\)(tales)

Tương tự với \(\Delta AFP'\) có \(\dfrac{QD}{FP'}=\dfrac{AD}{AP'}\)

\(\Rightarrow\dfrac{DH}{BP'}=\dfrac{QD}{FP'}\)

Mà DH=QD (cmt) 

\(\Rightarrow BP'=FP'\)

\(\Rightarrow\)P' là trung điểm BF

\(\Rightarrow P\equiv P'\)

\(\Rightarrow A,D,P\) thẳng hàng

b) Ta có: \(\left(-\dfrac{1}{2}\right)^2\cdot2\dfrac{6}{7}-\dfrac{14}{15}:2\dfrac{1}{3}+\left(-1.21\right)^0\)

\(=\dfrac{1}{4}\cdot\dfrac{20}{7}-\dfrac{14}{15}:\dfrac{7}{3}+1\)

\(=\dfrac{5}{7}-\dfrac{14}{15}\cdot\dfrac{3}{7}+1\)

\(=\dfrac{5}{7}-\dfrac{2}{5}+1\)

\(=\dfrac{25-14-35}{35}=\dfrac{-24}{35}\)

`@` `\text {Ans}`

`\downarrow`

`a)`

\(24 \div a+24=30\)

`=> 24 \div a = 30 - 24`

`=> 24 \div a = 6`

`=> a = 24 \div 6`

`=> a = 4`

Vậy, `a=4`

`b)`

\( 1974 \div 14+a \times 141=423\)

`=> 141 + a \times 141 = 423`

`=> a \times 141 = 423 - 141`

`=> a \times 141 = 282`

`=> a = 282 \div 141`

`=> a = 2`

Vậy, `a=2`

`c)`

\(120-(45-a \times 4)=115\)

`=> 45 - a \times 4 = 120 - 115`

`=> 45 - a \times 4 = 5`

`=> a \times 4 = 45 - 5`

`=> a \times 4 = 40`

`=> a = 40 \div 4`

`=> a = 10`

Vậy, `a=10`

`d)`

\((a \times 4-44) \div 4=44\)

`=> a \times 4 - 44 = 44 \times 4`

`=> a \times 4 - 44 = 176`

`=> a \times 4 = 176 + 44`

`=> a \times 4 = 220`

`=> a = 220 \div 4`

`=> a = 55`

Vậy, `a = 55.`

a) 24:a+24=30

 24:a= 30 - 24

24:a=6

a= 24:6

a=4

______

b) 1974:14+ax141=423 

141 + a x 141 = 423

141 x (a+1) = 423

a+1 = 423 : 141

a+1=3

a=3-1

a=2

_____
c) 120-(45-ax4)=115

45 - a x 4= 120 - 115

45 - a x 4= 5

a x 4 = 45 - 5

a x 4 = 40

a = 40:4

a=10

______

  d) (ax4-44):4=44

a x 4 - 44 = 44  x 4

a x 4 - 44 = 176

a x 4 = 176 + 44

a x 4 = 220

a= 220:4

a=55

a) \(24:a+24=30\)

\(\Rightarrow24:a=30-24\)

\(\Rightarrow24:a=6\)

\(\Rightarrow a=24:6\)

\(\Rightarrow a=4\)

b) \(1974:14+a\cdot141=423\)

\(\Rightarrow141+a\cdot141=423\)

\(\Rightarrow141\cdot\left(1+a\right)=423\)

\(\Rightarrow1+a=423:141\)

\(\Rightarrow1+a=3\)

\(\Rightarrow a=3-1\)

\(\Rightarrow a=2\)

c) \(120-\left(45-a\cdot4\right)=115\)

\(\Rightarrow45-a\cdot4=120-115\)

\(\Rightarrow45-a\cdot4=5\)

\(\Rightarrow a\cdot4=45-5\)

\(\Rightarrow a=40:4\)

\(\Rightarrow a=10\)

d) \(\left(a\cdot4-44\right):4=44\)

\(\Rightarrow a\cdot4-44=44\cdot4\)

\(\Rightarrow a\cdot4-44=176\)

\(\Rightarrow a\cdot4=176+44\)

\(\Rightarrow a\cdot4=220\)

\(\Rightarrow a=220:4\)

\(\Rightarrow a=55\)

A