TRONG QUYỂN NÂNG CAO PHÁT TRIỂN TOÁN 6 CÓ ĐẤY

Bạn lấy số cuối dãy trừ số đầu dãychia khoảng cách la 1 va tru 1 la tim ra so phan tu

Roi ban lay so dau day cong so cuoi daycong phan tu ban vua tinh ra chia 2

Ta có A=1/10.11+1/11.12+...+1/98.99+1/99.100

            =1/10-1/11+1/11-1/12+...+1/98-1/99+1/99-1/100

            =1/10-1/100

           =10/100-1/100

          =9/100

Vậy A=9/100

Giải:

A=1/10.11+1/11.12+...+1/98.99+1/99.100

A=1/10-1/11+1/11-1/12+...+1/98-1/99+1/99-1/100

A=1/10-1/100

A=9/100

Chúc bạn học tốt!

A=10.11+11.12+...+19.20

3A=10.11.3+11.12.3+...+19.20.3=10.11(12-9)+11.12(13-10)+12.13(14-11)+...+19.20(21-18)

3A=10.11.12 - 9.10.11 + 11.12.13 - 10.11.12 + 12.13.14 - 11.12.13 +...+ 19.20.21 - 18.19.20

3A=19.20.21-9.10.11 => A=(19.20.21-9.10.11)/3

\(A=\frac{1}{7}.\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+...+\frac{1}{68}-\frac{1}{70}\right)\)

\(A=\frac{1}{7}.\left(\frac{1}{10}-\frac{1}{70}\right)=\frac{1}{7}.\frac{3}{35}=\frac{3}{245}\)

A=\(\frac{7}{10.11}\)+\(\frac{7}{11.12}\)+\(\frac{7}{12.13}\)+...+\(\frac{7}{69.70}\)

A=\(\frac{7}{10}\)-\(\frac{7}{11}\)+\(\frac{7}{11}\)-\(\frac{7}{12}\)+\(\frac{7}{12}\)-\(\frac{7}{13}\)+...+\(\frac{7}{69}\)-\(\frac{7}{70}\)

A=\(\frac{7}{10}-\frac{7}{70}\)

A=\(\frac{7}{10}-\frac{1}{10}\)

Ạ=\(\frac{6}{10}=\frac{3}{5}\).

\(A=\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+..+\frac{7}{69.70}\)

=\(7.\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+..+\frac{1}{69}-\frac{1}{70}\right)\)

=\(7.\left(\frac{1}{10}-\frac{1}{70}\right)=7.\frac{3}{35}=\frac{21}{35}\)

tổng này có:99-10+1=90 so hang

(10,10+99,99)x90:2=4954,05

k nhe

Lời giải:

$S=10.11+11.12+12.13+...+29.30$

$3S=10.11(12-9)+11.12(13-10)+12.13(14-11)+...+29.30(31-28)$

$=(10.11.12+11.12.13+12.13.14+...+29.30.31)-(9.10.11+10.11.12+...+28.29.30)$

$=29.30.31-9.10.11=25980$

$\Rightarrow S=8660$

\(A=\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\)

\(\Rightarrow A=7.\left(\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}+....+\frac{1}{69.70}\right)\)

\(\Rightarrow A=7.\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)

\(\Rightarrow A=7\left(\frac{1}{10}-\frac{1}{70}\right)\)

\(\Rightarrow A=7.\frac{3}{35}\)

\(\Rightarrow A=\frac{3}{5}\)