Xin lỗi bn , mk còn thiếu 1 câu :

\(8^{14}=4^N\)

\(\Rightarrow N=14.2\)

\(\Rightarrow N=28\)

a,\(8:2^N=2\)

\(2^N=8:2\)

\(2^N=4\)

\(2^N=2^2\)

b, \(8^n:2^n=4\)

\(\Rightarrow n=1\)

8 : 2^n=2

2^n = 8 : 2

2^n = 4 = 2^2

=> n=2

a,

8^14 = 2^3x14=2^42

4^n = 2^2n

=> 2^2n = 2^42

2n=42

n=21

b,

<=> (8:2)^n = 4

4^n=4

n=1

\(8^n:2^n=16^{2011}\)

\(\left(2^3\right)^n:2^n=\left(2^4\right)^{2011}\)

\(2^{3n}:2^n=2^{8044}\)

\(2^{3n-n}=2^{8044}\)

\(\Rightarrow3n-n=8044\)

\(2n=8044\)

\(\Rightarrow n=\frac{8044}{2}\)

\(n=4022\)

Vậy \(n=4022\)

\(\left(2^3\right)^n\)\(:2^n\)\(=\left(2^4\right)^{2021}\)

\(2^{3n}\)\(:2^n\)\(=2^{4x2021}\)\(=2^{8084}\)

\(2^{3n-n}\)\(=2^{8084}\)

\(=>3n-n=8084\)

\(2n=8084\)

\(n=8084:2=4042\)

\(=>n=4042\)

\((11:21)2×(32010−3):3+3=35n+5⇒32010−3+3=35n+5\)

\(⇒32010=35n+5⇒5n+5=2010⇒5n=2005⇒n=401\)

\(2\times\left(3^{2010}-3\right):3+3=3^{5n+5}\)

\(\Rightarrow3^{2010}-3+3=3^{5n+5}\)

\(\Rightarrow3^{2010}=3^{5n+5}\)

\(\Rightarrow5n+5=2010\)

\(\Rightarrow5n=2005\)

\(\Rightarrow n=401\)