4/3x1/7+4/7x1/11+4/11x1/15+4/15x1/19=?
(15x1-15)x(10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20)
Quá dễ phải hôn ^_^
(15x1-15) x) (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20)
= (15-15) x (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20)
= 0 x (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20)
= 0
= (15 - 15)\(\times\)(10 +1 +2 +3 +4 +5 +6 +7 +8 +9 +10 +11 +12 +13 +14 +15 +16 +17 +18 +19 +20)
= 0\(\times\)(10 +1 +2 +3 +4 +5 +6 +7 +8 +9 +10 +11 +12 +13 +14 +15 +16 +17 +18 +19 +20)
= 0
(15x1-15) x) (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20) = (15-15) x (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20) = 0 x (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20) = 0
1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6+1/6x1/7+1/7x1/8+1/8x1/9
1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6+1/6x1/7+1/7x1/8+1/8x1/9
=7/18
1) 1/1×2 + 2/2×4 + 3/4×7 + 4/7×11 +...+ 8/29×37 + 9/37×46 + 10/46×56
2) 4/3×7 + 4/7×11 + 4/11×15 + 4/15×19 + 4/19×23 + 4/23×27
3) 4/3×6 + 4/6×9 + 4/9×12 + 4/12×15 + ... + 4/99×102
\(A=\frac{1}{1\cdot2}+\frac{2}{2\cdot4}+\frac{3}{4\cdot7}+\frac{4}{7\cdot11}+...+\frac{10}{46\cdot56}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{46}-\frac{1}{56}\)
\(A=1-\frac{1}{56}\)
\(A=\frac{55}{56}\)
\(B=\frac{4}{3\cdot7}+\frac{4}{7\cdot11}+\frac{4}{11\cdot15}+...+\frac{4}{23\cdot27}\)
\(B=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{23}-\frac{1}{27}\)
\(B=\frac{1}{3}-\frac{1}{27}\)
\(B=\frac{8}{27}\)
\(C=\frac{4}{3\cdot6}+\frac{4}{6\cdot9}+\frac{4}{9\cdot12}+...+\frac{4}{99\cdot102}\)
\(C=\frac{4}{3}\left(\frac{3}{3\cdot6}+\frac{3}{6\cdot9}+\frac{3}{9\cdot12}+...+\frac{3}{99\cdot102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{99}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\cdot\frac{33}{102}\)
\(C=\frac{22}{51}\)
Tính nhanh
5/6x1/7-1/7x1/6
8/15:4/5x3/2
5/6 x 1/7 - 1/7 x 1/6
= 1/7 x (5/6 - 1/6)
= 1/7 x 2/3
= 2/21
8/15 : 4/5 x 3/2
= 2/3 x 3/2
= 1
a: =1/7(5/6-1/6)=1/7x2/3=2/21
b: =8/15x5/4x3/2=1
`5/6xx1/7-1/7xx1/6`
`= 1/7 xx (5/6-1/6)`
`= 1/7 xx 2/3`
`= 2/21`
`8/15: 4/5 xx3/2`
`= 2/3 xx 3/2`
`= 1`
Tính nhanh :
A. 1/21 + 2/21 + 3/21 + 4/21...+ 19/21 + 20/21
B. 3/7 + 4/19 + 7/11 + 15/11 + 15/19 + 4/7
A. Dãy số có số số hạng là
( 20/21 - 1/21) :1/21 + 1 = 20
Tổng dãy trên là
( 1/21 + 20/21) x 20 : 2 = 10
B. 3/7 + 4/19 + 7/11 + 15/11 + 15/19 + 4/7
= 4
Thực hiện phép tính:
a. 7/-25 + -18/25 + 4/23 + 5/7 + 19/23
b. -2 + 15/19 + -15/17 +15/23 + 4/19
c. -5/11 + [-6/11 +1]
d. 1,4 . 15/49 - [4/5 + 2/3] : hai một phần năm
e. 7/19 .8/11 + 7/19 . 3/11 + 12/19
\(\dfrac{7}{-25}+\dfrac{18}{25}+\dfrac{4}{23}+\dfrac{5}{7}+\dfrac{19}{23}\)
=\(\left(\dfrac{-7}{25}+\dfrac{18}{25}\right)+\left(\dfrac{4}{23}+\dfrac{19}{23}\right)+\dfrac{5}{7}\)
= \(\dfrac{11}{25} +1+\dfrac{5}{7}\)
= \(1\dfrac{11}{25}+\dfrac{5}{7}\)
= \(2\dfrac{27}{175}\)
b) \(-2+\dfrac{15}{19}+\dfrac{-15}{17}+\dfrac{15}{23}+\dfrac{4}{19}\)
=\(-2+\left(\dfrac{ }{ }\right)\)
tính bằng cách thuận tiện nhất
a,4/15 x 7/8 + 4/15 x 2/9
b, 13/29 x 23/11 -13/19 x 8/11 - 13/19 x 4/11
4) so sánh hai phân số sau
a) 7/15 và 4/9
B1 tính nhanh nếu có thể
a) (-18).5+5.10+5.(-2)
b) (-15):(-5)+7.(-3/7)
c) (-157)+(-16)+257+(-43)+(-84)
d) (+23)+(-135)-(-77)-/-65/+(-30)
e) -5/7 + (-6/11+1)
f) 1/2-2/3+4/5-5/6
g)1/3.4/5+1/3.6/5+2/3
h) -5/7.2/11+-5/7.9/11+1 5/7 không phải 15 phần 7
I)19/5.2007/2017+19/5.10/2017
K) 4/25.5/9+-4/25.10/3+7/9
m) 7/19.8/11+7/19.3/11+12/19
n)17/13.18/23-4/13.18/23-(-5)/23
P) 5/7 .5/11+5/7.2/11-5/7.14/11
q)-2/17+15/19+-15/17+13/20+4/19
X)7/-25+-18/25+4/23+5/8+19/23
S)5/7.-4/19+-15/7.5/19
Tính
a) 4/3*7 + 4/7*11 + 4/11*15 + 4/15*19 + 4/19*23 + 4/23*27
b) 1/2*3 + 1/3*4 + 1/4*5 + 1/5*6 +1/6*7
c) 2/3*5 + 2/5*7 + 2/7*9 + 2/9*11 + 2/11*13 + 2/1*2 + 2/2*3 + 2/3*4 + 2/8*9 + 2/9*10
a)\(\frac{4}{3.7}+\frac{4}{7.11}+...+\frac{4}{23.27}=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{23}-\frac{1}{27}=\frac{1}{3}-\frac{1}{27}=\frac{8}{27}\)
b)\(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{6.7}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}=\frac{1}{2}-\frac{1}{7}=\frac{5}{14}\)
c)\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{11.13}+\frac{2}{1.2}+\frac{2}{2.3}+...+\frac{2}{9.10}=\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{11}-\frac{1}{13}\right)+2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=\frac{1}{3}-\frac{1}{13}+2\left(1-\frac{1}{10}\right)=\frac{10}{39}+\frac{9}{5}=\frac{401}{195}\)