\(100-\left|x+1\right|=90\)

\(\Rightarrow\left|x+1\right|=100-90=10\)

\(\Rightarrow\left[{}\begin{matrix}x+1=10\\x+1=-10\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=9\\x=-11\end{matrix}\right.\)

⇒[x+1=10x+1=−10⇒[x+1=10x+1=−10⇒[x=9x=−11

a)=> 4.(90:x-8)=32-24=8

=>90:x-8=8:4=2

=>90:x=2+8=10

=>x=90:10=9

b)=> 3x+15+2x+20=100

=> 5x+35=100

=>5x=100-35=65

=>x=13

nha . Chúc bạn học tốt

Ta có: \(A=|x-100|+|x+90|=|x-100|+|-x-90|\)

\(\Rightarrow A\ge|x-100-x-90|=190\)

Dấu "=" xảy ra \(\Leftrightarrow x\le100\).

Vậy Min A = 190 khi x \(\le\)100.

Kb vs cho tớ nhia mn!

a, (9-8x)x2=100

     9-8x    =100:2

     9-8x   =50

        8x    =9-50

        8x    =-41

        x     =-41:8

        x     = \(\frac{-41}{8}\)

b, (20-x)x2=60

     20-x    =60:2

     20-x    =30

         x    =20-30

        x    =-10

c, \(\frac{1}{2}x+\frac{8}{4}=\frac{100}{25}\)

   \(\frac{1}{2}x+2=4\)

  \(\frac{1}{2}x=4-2\)

   \(\frac{1}{2}x=2\)

      x   =2:\(\frac{1}{2}\)

     x    =4

d, (90-x)10=1000

    90-x     =1000:10

    90-x     =100

        x      =90-100

        x=-10

****

d)(90-x)10=1000

<=>90-x=1000:10

<=>90-x=100

<=>x=90-100

<=>x=-10

Bài 3: 

a) Đặt f(x)=0

\(\Leftrightarrow x^2-4x+3=0\)

\(\Leftrightarrow\left(x-1\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=3\end{matrix}\right.\)

b) Đặt f(x)=0

\(\Leftrightarrow x^2-7x+12=0\)

\(\Leftrightarrow\left(x-3\right)\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\)

Bài 3:

c) Đặt f(x)=0

\(\Leftrightarrow x^2+2x+1=0\)

\(\Leftrightarrow\left(x+1\right)^2=0\)

\(\Leftrightarrow x+1=0\)

hay x=-1

d) Đặt f(x)=0

\(\Leftrightarrow x^4+2=0\)

\(\Leftrightarrow x^4=-2\)(Vô lý)

a: M={90;93;96;99}

b: N={90;95;100}

37

Thui đi tạo nick mới :))))

37 bn