Tìm x
\(\frac{\left(1,16-x\right)\times5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right)\times2\frac{2}{17}}=\frac{3}{4}\)
\(\frac{\left(1,16-x0\times\right)5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right)\times2\frac{2}{17}}=75\%\)
Tìm x
\(\frac{\left(1,16-x\right).5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right).2\frac{2}{17}}=75\%\)
\(\frac{\left(1,16-x\right)\cdot5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right)\cdot2\frac{2}{17}}=75\%\)
tìm x
Tìm x biết:
\(\frac{\left(1,16-x\right).5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right).2\frac{2}{17}}=75\%\)
tìm x biết
a)x+30%x = -1,3
b) \(\frac{\left(1,16-x\right).5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right).2\frac{2}{17}}=75\%\)
x + 30% x = - 1,3
x ( 100% + 30% ) = - 1,3
x . 130% = - 1,3
x = - 1,3 : 130%
x = - 1,69
tìm x biết:
a,\(7,5x:\left(9-6\frac{13}{21}\right)=2\frac{13}{25}\)
b,\(\frac{\left(1,16-x\right)\cdot5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right)\cdot2\frac{2}{17}}\)=75%
\(\frac{\left[1,16-x\right].5,25}{\left[10\frac{5}{9}-7\frac{1}{4}\right].2\frac{2}{17}}\)
\(\frac{\left[1,16-x\right].5,25}{\left[10\frac{5}{9}-7\frac{1}{4}\right].2\frac{2}{17}}\)
\(\Leftrightarrow\frac{\left[1,16-x\right].5,25}{\left[\frac{95}{9}-\frac{29}{4}\right].\frac{36}{17}}\)
\(\Leftrightarrow\frac{\left[1,16-x\right].5,25}{\frac{119}{36}.\frac{36}{17}}\)
\(\Leftrightarrow\frac{\left[1,16-x\right].5,25}{7}\)
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Mình nghĩ là thiếu đề bạn ạ, phép chia trên phải có thương ms giải tiếp đk bạn nhé! Chúc bạn học tốt!
Bài 1: Tìm x biết:
a) |x-3|-x=1
b) 4x+1+ 4x+2+4x+3=5376
c)\(\frac{\left(1,16-x\right).5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right).2\frac{2}{11}}\)=75%
Tìm x
a/\(\frac{x+7}{2003}+\frac{x+4}{2006}=\frac{x-1}{2011}+\frac{x-5}{2015}\)
b/\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
c/\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
a) \(\Leftrightarrow\frac{x+7}{2003}+1+\frac{x+4}{2006}+1-\frac{x-1}{2011}-1-\frac{x-5}{2015}-1=0\)
\(\Leftrightarrow\frac{x+2010}{2003}+\frac{x+2010}{2006}-\frac{x+2010}{2011}-\frac{x+2010}{2015}=0\)
\(\Leftrightarrow\left(x+2010\right)\left(\frac{1}{2003}+\frac{1}{2006}-\frac{1}{2011}-\frac{1}{2015}\right)=0\)
\(\Leftrightarrow x+2010=0\) ( vì 1/2003 + 1/2006 -- 1/2011 -- 1/2015 \(\ne\)0)
\(\Leftrightarrow x=-2010\)
câu b làm tương tự (có gì không hiểu hỏi mk nha) >v<