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\(1\frac{1}{3}.1\frac{1}{4}.1\frac{1}{5}.1\frac{1}{6}.1\frac{1}{7}.1\frac{1}{8}=\frac{4}{3}.\frac{5}{4}.\frac{6}{5}.\frac{7}{6}.\frac{8}{7}.\frac{9}{8}=\frac{9}{3}=3\)

=11/3x4x5x6x7x8

=11/20160

Mik có sửa lại đề

C1: \(\dfrac{6}{7}\times\dfrac{1}{2}+\dfrac{6}{7}\times\dfrac{1}{4}=\dfrac{3}{7}+\dfrac{3}{14}=\dfrac{6}{14}+\dfrac{3}{14}=\dfrac{9}{14}\)

C2:\(\dfrac{6}{7}\times\dfrac{1}{2}+\dfrac{6}{7}\times\dfrac{1}{4}=\dfrac{6}{7}\times\left(\dfrac{1}{2}+\dfrac{1}{4}\right)=\dfrac{6}{7}\times\left(\dfrac{2}{4}+\dfrac{1}{4}\right)=\dfrac{6}{7}\times\dfrac{3}{4}=\dfrac{9}{14}\)

4/6x1/5+4/6x3/5+2/6x4/5

=4/6.(1/5+3/5)+2/6.4/5

=4/6.4/5+2/6.4/5

=4/5.(4/6+2/6)

=4/5.6/6

=4/5.1 = 4/5

- 13 42

\(\frac{1}{20}\cdot\frac{1}{30}\cdot\frac{1}{42}\cdot\frac{1}{56}\cdot\frac{1}{72}\cdot\frac{1}{90}\)

\(=\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}\)

\(=\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)

\(=\frac{1}{4}-\frac{1}{10}\)

\(=\frac{6}{40}=\frac{3}{20}\)

ta có 

a=1+2+4+...........+211

=1+[1+1]+[1+1+2]+[1+1+2+3]+..................+[1+1+2+3+...........+20] =[1+......+1]+[1+1+.....+1]+[2+......+2]+..........+[19+19]+20

=21+[1*20+2*19+...............+19*2+20]

   =1561            

= 60 tk m nhé

40x3/2=60

bằng 60 nha bạn