Tìm \(lim\dfrac{\sqrt[4]{n^8-4n^4+2n}}{n^2+3n+1}\)
1 2 4 \(\dfrac{4}{3}\) Hướng dẫn giải:\(lim\dfrac{\sqrt[4]{n^8-4n^4+2n}}{n^2+3n+1}\) \(=lim\dfrac{n^2\sqrt[4]{1-\dfrac{4}{n^4}+\dfrac{2}{n^7}}}{n^2\left(1+\dfrac{3}{n}+\dfrac{1}{n^2}\right)}=1\).