Kết quả của các phép tính: \(3,2.\dfrac{15}{64}-\left(\dfrac{4}{5}+\dfrac{2}{3}\right):3\dfrac{2}{3}\) là
\(\dfrac{7}{20}\). \(\dfrac{4}{5}\). \(\dfrac{9}{20}\). \(\dfrac{11}{20}\). Hướng dẫn giải:\(3,2.\dfrac{15}{64}-\left(\dfrac{4}{5}+\dfrac{2}{3}\right):3\dfrac{2}{3}\)
\(=\dfrac{16}{5}.\dfrac{15}{64}-\left(\dfrac{12}{15}+\dfrac{10}{15}\right):\dfrac{11}{3}\)
\(=\dfrac{3}{4}-\dfrac{22}{15}.\dfrac{3}{11}\)
\(=\dfrac{3}{4}-\dfrac{2}{5}\)
\(=\dfrac{7}{20}\)