Khi giải phương trình \(\dfrac{x+1}{2}+\dfrac{x+1}{4}=1-\dfrac{3\left(x+1\right)}{5}\), ta được nghiệm là
\(x=-\dfrac{7}{27}\).\(x=\dfrac{7}{27}\).\(x=\dfrac{1}{3}\).\(x=-\dfrac{3}{7}\).Hướng dẫn giải:\(\dfrac{x+1}{2}+\dfrac{x+1}{4}=1-\dfrac{3\left(x+1\right)}{5}\)
\(\Leftrightarrow\dfrac{x+1}{2}+\dfrac{x+1}{4}+\dfrac{3\left(x+1\right)}{5}=1\)
\(\Leftrightarrow\left(x+1\right)\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{3}{5}\right)=1\)
\(\Leftrightarrow\dfrac{27}{20}\left(x+1\right)=1\)
\(\Leftrightarrow x+1=\dfrac{20}{27}\)
\(\Leftrightarrow x=-\dfrac{7}{27}\)