Khi thực hiện phép tính \(\left(9x^2+6x+1\right):\dfrac{3x^2-5x-2}{x^2-x-2}\), ta có kết quả là
\(\left(3x+1\right)\left(x+1\right)\).\(\dfrac{\left(3x-1\right)\left(x+1\right)}{2}\).\(\left(3x-1\right)\left(x-1\right)\).\(\dfrac{\left(3x+1\right)\left(x+1\right)}{x+2}\).Hướng dẫn giải:\(\left(9x^2+6x+1\right):\dfrac{3x^2-5x-2}{x^2-x-2}\)
\(=\left(3x+1\right)^2.\dfrac{\left(x-2\right)\left(x+1\right)}{\left(x-2\right)\left(3x+1\right)}\)
\(=\left(3x+1\right)\left(x+1\right)\).